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Category: Number Theory

Question-189090

Question Number 189090 by sonukgindia last updated on 12/Mar/23 Answered by HeferH last updated on 12/Mar/23 $$\:\mathrm{case}\:\mathrm{1}:\: \\ $$$$\left({x}^{\mathrm{2}} −\mathrm{2}{x}\right)\:=\:\mathrm{1} \\ $$$$\:{x}^{\mathrm{2}} −\mathrm{2}{x}−\mathrm{1}\:+\mathrm{2}\:=\:\mathrm{2} \\ $$$$\:\left({x}−\mathrm{1}\right)^{\mathrm{2}}…

Prove-n-7-1-7-n-6-1-

Question Number 122896 by fajri last updated on 20/Nov/20 $${Prove}\:: \\ $$$$\left({n},\mathrm{7}\right)\:=\:\mathrm{1}\:\rightarrow\:\mathrm{7}\mid\left({n}^{\mathrm{6}} \:−\:\mathrm{1}\right) \\ $$ Answered by Snail last updated on 20/Nov/20 $${Use}\:\:{Euelers}\:{theorem}\:{or}\:{fermats}\:{theorem}\:{to}\:{do}\:{so} \\ $$…

1-solve-Diopthantine-equation-754x-221y-13-2-find-the-number-abcd-such-that-4-abcd-dcba-

Question Number 188196 by cortano12 last updated on 26/Feb/23 $$\left(\mathrm{1}\right)\mathrm{solve}\:\mathrm{Diopthantine}\:\mathrm{equation} \\ $$$$\:\:\:\:\:\mathrm{754x}+\mathrm{221y}=\mathrm{13} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{abcd}\: \\ $$$$\:\:\:\mathrm{such}\:\mathrm{that}\:\mathrm{4}×\left(\mathrm{abcd}\right)=\mathrm{dcba} \\ $$ Commented by ARUNG_Brandon_MBU last updated on 26/Feb/23…

can-anybody-do-me-a-faver-and-tell-me-what-the-direct-proof-of-mobius-inversion-formula-is-proof-without-using-Dirichlet-convolutions-

Question Number 122637 by sina1377 last updated on 18/Nov/20 $${can}\:{anybody}\:{do}\:{me}\:{a}\:{faver}\:{and}\:{tell}\:{me}\:{what}\:\:{the}\:\:{direct}\:{proof}\:{of}\:\:{mobius}\:{inversion}\:{formula}\:{is}?\:\left({proof}\:{without}\:{using}\:\:{Dirichlet}\:{convolutions}\right)? \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-121834

Question Number 121834 by bemath last updated on 12/Nov/20 Answered by liberty last updated on 12/Nov/20 $$\mathrm{we}\:\mathrm{have}\:\mathrm{gcd}\left(\mathrm{93},\mathrm{27}\right)\:=\:\mathrm{3}\:\mathrm{and}\:\mathrm{6}\:\mathrm{divides}\:\mathrm{by}\:\mathrm{3} \\ $$$$\mathrm{therefore}\:\mathrm{there}\:\mathrm{exist}\:\mathrm{solutions}.\: \\ $$$$\mathrm{we}\:\mathrm{have}\:\mathrm{93}\:=\:\mathrm{3}×\mathrm{27}+\mathrm{12}\:\wedge\:\mathrm{27}\:=\:\mathrm{2}×\mathrm{12}+\mathrm{3} \\ $$$$\:\mathrm{12}\:=\:\mathrm{4}×\mathrm{3}\:+\:\mathrm{0}\: \\ $$$$\:\mathrm{3}\:=\:\mathrm{1}×\mathrm{27}−\mathrm{2}×\mathrm{12}\:…

Prove-that-for-n-4-S-n-k-1-n-k-k-is-never-a-perfect-cube-

Question Number 187296 by anurup last updated on 15/Feb/23 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{for}\:\mathrm{n}\geqslant\mathrm{4},\:\mathrm{S}_{{n}} =\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{k}^{{k}!} \:\mathrm{is}\:\mathrm{never}\:\mathrm{a}\:\mathrm{perfect}\:\mathrm{cube}. \\ $$ Commented by anurup last updated on 15/Feb/23 $$\mathrm{Please}\:\mathrm{solve}\:\mathrm{this}. \\…

Evaluate-k-1-n-4k-4k-2-1-2k-1-2k-1-

Question Number 121694 by bemath last updated on 11/Nov/20 $${Evaluate}\:\underset{{k}\:=\:\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{4}{k}+\sqrt{\mathrm{4}{k}^{\mathrm{2}} −\mathrm{1}}}{\:\sqrt{\mathrm{2}{k}−\mathrm{1}}\:+\:\sqrt{\mathrm{2}{k}+\mathrm{1}}}\:? \\ $$ Answered by liberty last updated on 11/Nov/20 $$\:\mathrm{let}\:\sqrt{\mathrm{2k}−\mathrm{1}}\:=\:\mathrm{a}\:\mathrm{and}\:\sqrt{\mathrm{2k}+\mathrm{1}}\:=\:\mathrm{b}\: \\ $$$$\Rightarrow\:\mathrm{a}^{\mathrm{2}}…

If-a-b-are-co-prime-natural-numbers-satisfying-a-2-b-a-b-3-and-b-1-is-a-prime-find-all-possible-values-of-a-b-Please-help-me-solve-this-

Question Number 187213 by anurup last updated on 14/Feb/23 $$\mathrm{If}\:{a},{b}\:\mathrm{are}\:\mathrm{co}-\mathrm{prime}\:\mathrm{natural}\:\mathrm{numbers}\:\mathrm{satisfying} \\ $$$${a}^{\mathrm{2}} \:+\:{b}\:=\:\left({a}−{b}\right)^{\mathrm{3}} \:\mathrm{and}\:{b}+\mathrm{1}\:\mathrm{is}\:\mathrm{a}\:\mathrm{prime}\:\mathrm{find}\:\mathrm{all} \\ $$$$\mathrm{possible}\:\mathrm{values}\:\mathrm{of}\:\left({a},\:{b}\right). \\ $$$$\mathrm{Please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{solve}\:\mathrm{this}. \\ $$$$ \\ $$ Terms of Service…