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Category: Operation Research

Given-the-function-f-x-2-0-lt-x-lt-2-2-2-lt-x-lt-0-of-period-4-a-sketch-the-graph-of-y-f-x-for-6-lt-x-lt-6-b-Find-the-Fourier-coefficient-a-0-a-n-and-b-n-

Question Number 204469 by DeArtist last updated on 18/Feb/24 Giventhefunctionf(x)={2,0<x<22,2<x<0ofperiod4(a)sketchthegraphofy=f(x),for6<x<6(b)FindtheFouriercoefficienta0,an,andbn(c)writedowntheFourierseries.$$\left(\mathrm{d}\right)\:\mathrm{hence}\:\mathrm{show}\:\mathrm{that}\:\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} }{\mathrm{2}{n}−\mathrm{1}}\:=\:\frac{\pi}{\mathrm{4}}…

x-1-2-D-2-x-1-D-1-y-4cos-ln-x-1-

Question Number 130827 by bemath last updated on 29/Jan/21 [(x+1)2D2+(x+1)D+1]y=4cos(ln(x+1)) Answered by EDWIN88 last updated on 29/Jan/21 letln(x+1)=tx+1=et$$\begin{cases}{\frac{{dy}}{{dx}}\:=\:\frac{{dy}}{{dt}}×\frac{{dt}}{{dx}}\:=\:\frac{\mathrm{1}}{{x}+\mathrm{1}}.\frac{{dy}}{{dt}}}\{\frac{{d}^{\mathrm{2}} {y}}{{dx}}\:=\:\frac{{d}}{{dx}}\:\left[\:\frac{\mathrm{1}}{{x}+\mathrm{1}}\:\frac{{dy}}{{dt}}\:\right]=\:\frac{\mathrm{1}}{\left({x}+\mathrm{1}\right)^{\mathrm{2}}…

Question-129102

Question Number 129102 by AbdulAzizabir last updated on 12/Jan/21 Answered by Olaf last updated on 12/Jan/21 nk=1k2={1,5,14,30,55,}=n(n+1)(2n+1)6S=23(14120+1561120+1220)$$\mathrm{S}\:=\:\frac{\mathrm{1}}{\mathrm{6}}\left(\frac{\mathrm{1}}{\mathrm{1}}−\frac{\mathrm{1}}{\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{14}}−\frac{\mathrm{1}}{\mathrm{30}}+\frac{\mathrm{1}}{\mathrm{55}}−…\right) \

A-particle-P-moves-on-the-curve-with-polar-equation-r-e-k-where-r-are-polar-coordinates-referred-to-a-fixed-pole-and-k-is-a-positive-constant-Given-that-the-radial-velocity-of-P-is-k-

Question Number 63298 by Rio Michael last updated on 02/Jul/19 AparticleP,movesonthecurvewithpolarequationr=ekθ,where(r,θ)arepolarcoordinatesreferredtoafixedpoleandkisapositiveconstant.GiventhattheradialvelocityofPiskrshowthatthetransverseaccelerationofthparticleiszero. Commented…