Question Number 176366 by doline last updated on 17/Sep/22 $${donner}\:{la}\:{forme}\:{trigonometrique}\:{de}\left(\mathrm{1}−{i}\sqrt{}\mathrm{3}\right)\left(\mathrm{1}+{i}\right)\left({cos}\theta−{isin}\theta\right) \\ $$ Answered by Ar Brandon last updated on 17/Sep/22 $$\left(\mathrm{2}{e}^{−\frac{\pi}{\mathrm{3}}{i}} \right)\left(\sqrt{\mathrm{2}}{e}^{\frac{\pi}{\mathrm{4}}{i}} \right)\left({e}^{−{i}\theta} \right)=\mathrm{2}\sqrt{\mathrm{2}}{e}^{\left(−\frac{\pi}{\mathrm{3}}+\frac{\pi}{\mathrm{4}}−\theta\right){i}} \\…
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Question Number 176118 by doline last updated on 12/Sep/22 $$ \\ $$ Commented by Rasheed.Sindhi last updated on 13/Sep/22 $$\mathcal{S}{pace}\:{booked}\:{for}\:{future}\:{question}? \\ $$ Terms of Service…
Question Number 176090 by doline last updated on 11/Sep/22 $${determiner}\:{z}\:{tel}\:{que}\:{z}={z}^{\mathrm{2}} −{z}+\mathrm{2} \\ $$$$ \\ $$ Commented by Frix last updated on 12/Sep/22 $$\mathrm{why}\:\mathrm{not}\:\mathrm{simply}\:\mathrm{use} \\ $$$${z}^{\mathrm{2}}…
Question Number 176070 by doline last updated on 11/Sep/22 $${demontrer}\:{par}\:{recurrence}\:{que}\:{pour}\:{tout}\:{n}>\mathrm{0}\:{appartenent}\:{a}\:{l}\:{ensemble}\:{des}\:{entier}\:{naturel}\:\mathrm{3}^{\mathrm{2}{n}−\mathrm{2}^{{n}\:} } {est}\:{multiple}\:{de}\:\mathrm{7} \\ $$ Commented by som(math1967) last updated on 11/Sep/22 $$\mathrm{3}^{\mathrm{2}{n}} −\mathrm{2}^{{n}} \\ $$$${p}\left(\mathrm{1}\right)=\mathrm{3}^{\mathrm{2}}…
Question Number 176060 by doline last updated on 11/Sep/22 $${x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{5}=\mathrm{0} \\ $$ Answered by Ar Brandon last updated on 11/Sep/22 $${x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{5}=\mathrm{0}\:\Rightarrow\left({x}−\mathrm{2}\right)^{\mathrm{2}} +\mathrm{1}=\mathrm{0} \\…
Question Number 176049 by doline last updated on 11/Sep/22 $${calculer}\:\left(−\mathrm{1}/\mathrm{2}+{i}\sqrt{\left.\mathrm{3}/\mathrm{2}\right)^{\mathrm{3}} }\right. \\ $$ Answered by Rasheed.Sindhi last updated on 11/Sep/22 $$−\mathrm{1}/\mathrm{2}+{i}\sqrt{\left.\mathrm{3}/\mathrm{2}\right)^{\mathrm{3}} } \\ $$$$=−\frac{\mathrm{1}}{\mathrm{2}}+\mathrm{i}\left(\sqrt{\mathrm{3}/\mathrm{2}}\:\right)^{\mathrm{3}} \\…
Question Number 109888 by bagusadisaputra last updated on 26/Aug/20 $$\mathrm{2}^{{x}+\mathrm{5}} =\sqrt{\mathrm{8}^{{x}} } \\ $$ Answered by som(math1967) last updated on 26/Aug/20 $$\mathrm{2}^{\mathrm{x}+\mathrm{5}} =\left(\mathrm{2}^{\mathrm{3x}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} \\…
Question Number 175083 by syamilkamil1 last updated on 18/Aug/22 $${how}\:{the}\:{next}\:{number}\:\mathrm{1},\mathrm{2},\mathrm{5},\mathrm{9},\mathrm{6},\mathrm{13},\mathrm{8},\mathrm{17},…. \\ $$ Commented by Frix last updated on 18/Aug/22 $$\mathrm{599} \\ $$ Commented by Frix…
Question Number 108476 by pticantor last updated on 17/Aug/20 $$\boldsymbol{{S}}_{{n}} =\underset{{k}=\mathrm{1}\:} {\overset{{n}} {\sum}}{k}^{\mathrm{2}} \left(−\mathrm{1}\right)^{{k}} \boldsymbol{{C}}_{\boldsymbol{{n}}} ^{\boldsymbol{{k}}} =? \\ $$$$\:\:\boldsymbol{{ple}}{ase}\:{help} \\ $$ Answered by mr W…