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Question Number 214781 by ppch145 last updated on 19/Dec/24 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{usefulness}\:\mathrm{of}\:“\mathrm{Get}\:\mathrm{Latex}''\mathrm{in}\:\mathrm{this}\: \\ $$$$\mathrm{application}? \\ $$ Commented by Tinku Tara last updated on 19/Dec/24 $$\mathrm{If}\:\mathrm{you}\:\mathrm{are}\:\mathrm{using}\:\mathrm{mobile}\:\mathrm{version}\:\mathrm{of} \\ $$$$\mathrm{word}\:\mathrm{then}\:\mathrm{using}\:\mathrm{image}\:\mathrm{will}\:\mathrm{be}…
Question Number 214757 by Tawa11 last updated on 19/Dec/24 Commented by ajfour last updated on 23/Dec/24 Hi, can you follow this question I have discussed. Really nice question, i created. https://youtu.be/PzKYmi7qrvk?si=TkeicIBzJ2aCaNZr Commented by Tawa11 last updated on 23/Dec/24 $$\mathrm{Followed}\:\mathrm{sir}…
Question Number 214569 by Atomic_30 last updated on 12/Dec/24 Answered by TonyCWX08 last updated on 12/Dec/24 $${What}\:{do}\:{you}\:{want}? \\ $$ Answered by MathematicalUser2357 last updated on…
Question Number 214448 by jahar last updated on 08/Dec/24 $$ \\ $$$$\overset{−} {{x}}\:=\:\frac{\Sigma{f}_{{i}} {x}_{{i}} }{\Sigma{f}_{{i}} \:}\:,\:\:\:\overset{−} {{u}}\:=\:\frac{\Sigma{f}_{{i}} {u}_{{i}} }{\Sigma{f}_{{i}} }\:,\:{u}\:=\:\frac{{x}−{a}}{{h}}\:, \\ $$$${proved}\:{that}\:\overset{−} {{x}}\:=\:{a}\:+\:{h}\overset{−} {{u}} \\…
Question Number 214264 by zhou0429 last updated on 03/Dec/24 Commented by Ghisom last updated on 05/Dec/24 $$\mathrm{it}\:\mathrm{makes}\:\mathrm{no}\:\mathrm{sense}\:\mathrm{trying}\:\mathrm{to}\:\mathrm{find}\:\mathrm{an}\:\mathrm{exact} \\ $$$$\mathrm{solution}\:\mathrm{since}\:\left(\mathrm{1}\right)\:\sqrt{\mathrm{39}}\:\mathrm{is}\:\mathrm{not}\:\mathrm{a}\:\mathrm{zero}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{polynomial}\:\mathrm{and}\:\left(\mathrm{2}\right)\:\mathrm{the}\:\mathrm{real}\:\mathrm{root}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{polynomial}\:\mathrm{is}\:\mathrm{no}\:\mathrm{usable}\:\mathrm{expression} \\ $$$$\mathrm{just}\:\mathrm{use}\:\mathrm{a}\:\mathrm{good}\:\mathrm{calculator}…
Question Number 214183 by jlewis last updated on 30/Nov/24 $$\left.\mathrm{a}\right)\:\mathrm{The}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{elevation}\:\mathrm{from}\:\mathrm{a}\:\mathrm{point}\:\mathrm{A}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{top}\:\mathrm{of}\:\mathrm{building}\:\mathrm{5m}\:\mathrm{away}\:\mathrm{is}\:\mathrm{45}°.\:\mathrm{Another}\:\mathrm{point} \\ $$$$\mathrm{B}\:\mathrm{is}\:\mathrm{4m}\:\mathrm{from}\:\mathrm{A}.\:\mathrm{By}\:\mathrm{scale}\:\mathrm{drawing}\:\mathrm{determine}. \\ $$$$\left.\mathrm{i}\right)\:\mathrm{the}\:\mathrm{angles}\:\mathrm{of}\:\mathrm{elevation}\:\mathrm{from}\:\mathrm{point}\:\mathrm{B} \\ $$$$\left.\mathrm{ii}\right)\mathrm{the}\:\mathrm{height}\:\mathrm{of}\:\mathrm{the}\:\mathrm{building} \\ $$$$\left.\mathrm{b}\right)\:\mathrm{A}\:\mathrm{man}\:\mathrm{who}\:\mathrm{is}\:\mathrm{in}\:\mathrm{the}\:\mathrm{elevator}\:\mathrm{half}\:\mathrm{way}\:\mathrm{the} \\ $$$$\mathrm{building}\:\mathrm{notices}\:\mathrm{a}\:\mathrm{lorry}\:\mathrm{approaching}\:\mathrm{the} \\ $$$$\mathrm{building}\:\mathrm{at}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{depression}\:\mathrm{20}°.\:\mathrm{How} \\…
Question Number 213960 by Tawa11 last updated on 22/Nov/24 Commented by Tawa11 last updated on 22/Nov/24 $$\mathrm{Prove}\:\mathrm{by}\:\mathrm{Mathematical}\:\mathrm{Induction} \\ $$ Answered by A5T last updated on…
Question Number 213890 by Tawa11 last updated on 20/Nov/24 Answered by mr W last updated on 21/Nov/24 $${h}={u}\:\mathrm{sin}\:\theta\:{t}−\frac{{gt}^{\mathrm{2}} }{\mathrm{2}} \\ $$$${t}=\frac{{u}\:\mathrm{sin}\:\theta}{{g}}\left(\mathrm{1}\pm\sqrt{\mathrm{1}−\frac{\mathrm{2}{gh}}{{u}^{\mathrm{2}} \:\mathrm{sin}^{\mathrm{2}} \:\theta}}\right) \\ $$$$\:\:=\frac{\mathrm{45}\:\mathrm{sin}\:\mathrm{52}°}{\mathrm{9}.\mathrm{81}}\left(\mathrm{1}\pm\sqrt{\mathrm{1}−\frac{\mathrm{2}×\mathrm{9}.\mathrm{81}×\mathrm{12}}{\mathrm{45}^{\mathrm{2}}…
Question Number 213658 by Danielacrsz last updated on 13/Nov/24 $${r}=\frac{\mathrm{112452}−\frac{\left(\mathrm{2108}\right)\left(\mathrm{3820}\right)}{\mathrm{80}}}{\:\sqrt{\mathrm{67778}−\frac{\left(\mathrm{2108}\right)^{\mathrm{2}} }{\mathrm{80}}\sqrt{\mathrm{232470}−\frac{\left(\mathrm{3820}\right)^{\mathrm{2}} }{\mathrm{80}}}}} \\ $$$$ \\ $$$$ \\ $$ Answered by MathematicalUser2357 last updated on 14/Nov/24…