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Question-115732

Question Number 115732 by gab last updated on 28/Sep/20 Commented by Dwaipayan Shikari last updated on 28/Sep/20 $$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{\mathrm{n}+\mathrm{1}} }{\mathrm{2n}^{\mathrm{2}} }\mathrm{e}^{\pi\mathrm{in}} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{e}^{\mathrm{i}\pi} }{\mathrm{1}^{\mathrm{2}}…

x-1-x-x-4-3-x-2-3-x-1-3-x-2-1-x-2-prove-LHS-RHS-

Question Number 181245 by Mastermind last updated on 23/Nov/22 $$\left(\mathrm{x}−\frac{\mathrm{1}}{\mathrm{x}}\right)\left(\mathrm{x}^{\frac{\mathrm{4}}{\mathrm{3}}} +\mathrm{x}^{\frac{\mathrm{2}}{\mathrm{3}}} \right)=\mathrm{x}^{\frac{\mathrm{1}}{\mathrm{3}}} \left(\mathrm{x}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{2}} }\right) \\ $$$$ \\ $$$$\mathrm{prove}\:\mathrm{LHS}=\mathrm{RHS} \\ $$ Commented by Socracious last…

Question-181217

Question Number 181217 by Mastermind last updated on 23/Nov/22 Answered by Rasheed.Sindhi last updated on 23/Nov/22 $$\mathrm{3}^{{x}} \left(\mathrm{2}{x}+\mathrm{1}\right)^{\mathrm{2}} =\mathrm{225}=\mathrm{3}^{\mathrm{2}} \mathrm{5}^{\mathrm{2}} \\ $$$${x}=\mathrm{2}\:\wedge\:\mathrm{2}{x}+\mathrm{1}=\mathrm{5} \\ $$$$\Rightarrow{x}=\mathrm{2}\:\wedge\:\mathrm{2}\left(\mathrm{2}\right)+\mathrm{1}=\mathrm{5} \\…

Question-115487

Question Number 115487 by 171 last updated on 26/Sep/20 Commented by Dwaipayan Shikari last updated on 26/Sep/20 $$\mathrm{y}^{\mathrm{2}} =\mathrm{1}+\mathrm{1}\:\left(\mathrm{x}=\mathrm{1}\right) \\ $$$$\mathrm{y}=\pm\sqrt{\mathrm{2}} \\ $$$$\mathrm{y}^{\mathrm{2}} =\mathrm{1}+\mathrm{2}\Rightarrow\mathrm{y}=\pm\sqrt{\mathrm{3}} \\…