Question Number 180683 by Mastermind last updated on 15/Nov/22 $$\left(\mathrm{b}\right)\:\mathrm{x}\:+\:\mathrm{y}\:+\:\mathrm{Kz}\:=\:\mathrm{2} \\ $$$$\:\:\:\:\mathrm{3x}\:+\:\mathrm{4y}\:+\:\mathrm{2z}\:=\:\mathrm{K} \\ $$$$\:\:\:\:\mathrm{2x}\:+\:\mathrm{3y}\:−\:\mathrm{z}\:=\:\mathrm{1} \\ $$ Answered by manxsol last updated on 15/Nov/22 $$\begin{cases}{\mathrm{1}}&{\mathrm{1}}&{{k}}&{\mathrm{2}}\\{\mathrm{3}}&{\mathrm{4}}&{\mathrm{2}}&{{k}}\\{\mathrm{2}}&{\mathrm{3}}&{−\mathrm{1}}&{\mathrm{1}}\end{cases} \\…
Question Number 180667 by cortano1 last updated on 15/Nov/22 Commented by JDamian last updated on 15/Nov/22 I never expected this from you :( Answered by a.lgnaoui last updated on 15/Nov/22 Commented…
Question Number 49594 by jashim last updated on 08/Dec/18 $$\:\:\:\:{How}\:{can}\:{we}\:{insert}\:{images}\:{in}\:{the}\:{editor}? \\ $$ Commented by mr W last updated on 08/Dec/18 $${select}\:“{More}\:…''\:{at}\:{upper}\:{right}\:{corner}. \\ $$$${you}\:{can}\:{add}\:{an}\:{image}\:{as}\:{question}, \\ $$$${as}\:{answer}\:{or}\:{as}\:{comment}.\:{but}\:{you}…
Question Number 115117 by bobhans last updated on 23/Sep/20 $${What}\:{is}\:{the}\:{value}\:{of}\:{a}\:{and}\:{b}\:{when}\: \\ $$$$\mathrm{3}{x}^{\mathrm{4}} +\mathrm{6}{x}^{\mathrm{3}} −{ax}^{\mathrm{2}} −{bx}−\mathrm{12}\:{is}\:{completely} \\ $$$${divisible}\:{by}\:{x}^{\mathrm{2}} −\mathrm{3}\:? \\ $$ Answered by john santu last…
Question Number 180625 by Mastermind last updated on 14/Nov/22 $$\mathrm{During}\:\mathrm{the}\:\mathrm{challenge}\:\mathrm{Cup}\:\mathrm{season}.\:\mathrm{Team} \\ $$$$\mathrm{A}\:\mathrm{scored}\:\mathrm{15}\:\mathrm{goals}\:\mathrm{more}\:\mathrm{than}\:\mathrm{Team}\:\mathrm{B}. \\ $$$$\mathrm{They}\:\mathrm{have}\:\mathrm{121}\:\mathrm{goals}\:\mathrm{between}\:\mathrm{them}. \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{goals}\:\mathrm{did}\:\mathrm{each}\:\mathrm{team}\:\mathrm{score}? \\ $$$$ \\ $$ Answered by Acem last updated…
Question Number 180621 by Noorzai last updated on 14/Nov/22 Answered by cortano1 last updated on 14/Nov/22 $$\:\frac{\mathrm{m}}{\mathrm{n}}\:=\:\frac{\mathrm{2cos}\:\left(\frac{\alpha+\beta}{\mathrm{2}}\right)\mathrm{cos}\:\left(\frac{\alpha−\beta}{\mathrm{2}}\right)}{\mathrm{2sin}\:\left(\frac{\alpha+\beta}{\mathrm{2}}\right)\:\mathrm{cos}\:\left(\frac{\alpha−\beta}{\mathrm{2}}\right)} \\ $$$$\Rightarrow\mathrm{tan}\:\left(\frac{\alpha+\beta}{\mathrm{2}}\right)=\:\frac{\mathrm{n}}{\mathrm{m}} \\ $$$$\Rightarrow\mathrm{sin}\:\left(\alpha+\beta\right)\:=\:\mathrm{2sin}\:\left(\frac{\alpha+\beta}{\mathrm{2}}\right)\:\mathrm{cos}\:\left(\frac{\alpha+\beta}{\mathrm{2}}\right) \\ $$$$\:\:=\:\frac{\mathrm{2tan}\:\left(\frac{\alpha+\beta}{\mathrm{2}}\right)}{\mathrm{1}+\mathrm{tan}\:^{\mathrm{2}} \left(\frac{\alpha+\beta}{\mathrm{2}}\right)}\:=\:\frac{\frac{\mathrm{2n}}{\mathrm{m}}}{\mathrm{1}+\frac{\mathrm{n}^{\mathrm{2}} }{\mathrm{m}^{\mathrm{2}}…
Question Number 49487 by Tawa1 last updated on 07/Dec/18 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{nth}\:\mathrm{term}\:\mathrm{of}\:\mathrm{the}\:\mathrm{sequence}:\:\:\mathrm{5},\:\:\mathrm{5},\:\:\mathrm{35},\:\mathrm{65},\:\:\mathrm{275},\:… \\ $$$$ \\ $$$$\mathrm{Answer}:\:\:\:\:\:\mathrm{3}^{\boldsymbol{\mathrm{n}}} \:−\:\left(−\:\mathrm{2}\right)^{\boldsymbol{\mathrm{n}}} \:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{ple}}\mathrm{1ase}\:\mathrm{how} \\ $$ Commented by mr W last updated on…
Question Number 180549 by Mastermind last updated on 13/Nov/22 $$\mathrm{Cross}\:\mathrm{fertilization}\:\mathrm{of}\:\mathrm{130}\:\mathrm{peas}\:\mathrm{from} \\ $$$$\mathrm{different}\:\mathrm{pure}\:\mathrm{line}\:\mathrm{yielded}\:\mathrm{the}\:\mathrm{following} \\ $$$$\mathrm{phenotype}\:\left(\mathrm{GS},\:\mathrm{GW},\:\mathrm{and}\:\mathrm{YW}\:\mathrm{as}\:\mathrm{follow}\right. \\ $$$$\mathrm{GS}\:\mathrm{only}\:\left(\mathrm{36}\right),\:\mathrm{GS}\:\mathrm{and}\:\mathrm{YW}\:\left(\mathrm{15}\right),\:\mathrm{all}\:\mathrm{the} \\ $$$$\mathrm{three}\:\mathrm{phenotype}\:\left(\mathrm{9}\right),\:\mathrm{GS}\:\mathrm{and}\:\mathrm{GW}\:\left(\mathrm{14}\right) \\ $$$$\mathrm{YW}\:\mathrm{and}\:\mathrm{GW}\:\mathrm{only}\:\left(\mathrm{4}\right).\:\mathrm{the}\:\mathrm{number}\:\mathrm{of} \\ $$$$\mathrm{those}\:\mathrm{that}\:\mathrm{have}\:\mathrm{only}\:\mathrm{YW}\:\mathrm{or}\:\mathrm{only}\:\mathrm{GW} \\ $$$$\mathrm{are}\:\mathrm{equal}. \\…
Question Number 180543 by Mastermind last updated on 13/Nov/22 $$\mathrm{12}.\mathrm{589} \\ $$$$\mathrm{we}\:\mathrm{read}\:\mathrm{non}−\mathrm{decimal}\:\mathrm{12}\:\mathrm{but}\:\mathrm{decimal} \\ $$$$\mathrm{number}\:\mathrm{5},\mathrm{8},\mathrm{9}\:\mathrm{separate}\:\mathrm{read}.\:\mathrm{why}? \\ $$ Answered by MJS_new last updated on 13/Nov/22 $$\mathrm{589}.\mathrm{589}\:\mathrm{is}\:\mathrm{better}\:\mathrm{to}\:\mathrm{explain}. \\…
Question Number 49396 by tanmay.chaudhury50@gmail.com last updated on 06/Dec/18 $${Here}\:{is}\:{floods}\:{of}\:{questions}…{number}\:{of}\:{batsman} \\ $$$${limited}\:{but}\:{bowlers}\:{are}\:{all}…\:{so}\:{pls}\:{limit}\:{your} \\ $$$${questions}…{if}\:{everybody}\:{posts}\:{questions}\:{who} \\ $$$${will}\:{answer}… \\ $$$${so}\:{pls}\:{limit}\:{questions}… \\ $$ Terms of Service Privacy Policy…