Question Number 203387 by Noorzai last updated on 18/Jan/24 Answered by Rasheed.Sindhi last updated on 18/Jan/24 $$\mathrm{S}=\frac{\underset{{n}=\mathrm{1}} {\overset{\mathrm{99}} {\sum}}\sqrt{\mathrm{10}+\sqrt{{n}}}\:}{\underset{{n}=\mathrm{1}} {\overset{\mathrm{99}} {\sum}}\sqrt{\mathrm{10}−\sqrt{{n}}}\:} \\ $$$$\mathrm{S}=\frac{\underset{{n}=\mathrm{1}} {\overset{\mathrm{99}} {\sum}}\frac{\sqrt{\mathrm{100}−{n}}\:}{\:\sqrt{\mathrm{10}−\sqrt{{n}}}}}{\underset{{n}=\mathrm{1}}…
Question Number 203308 by talminator2856792 last updated on 15/Jan/24 $$\:\:\mathrm{my}\:\mathrm{iq}\:\mathrm{is}\:\mathrm{not}\:\mathrm{good}\:\mathrm{enough}\:\mathrm{to}\:\mathrm{be}\:\mathrm{a}\:\mathrm{mathematician}.\:\: \\ $$$$\:\:\mathrm{i}\:\mathrm{dont}\:\mathrm{know}\:\mathrm{what}\:\mathrm{to}\:\mathrm{do}\:\mathrm{with}\:\mathrm{my}\:\mathrm{life}\:\mathrm{now}.\:\: \\ $$$$\:\:\mathrm{what}\:\mathrm{is}\:\mathrm{there}\:\mathrm{for}\:\mathrm{me}.\:\: \\ $$ Answered by behi834171 last updated on 16/Jan/24 $${hi} \\…
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Question Number 202820 by a.lgnaoui last updated on 04/Jan/24 $$\boldsymbol{\mathrm{U}}\mathrm{ne}\:\mathrm{dette}\:\:\mathrm{de}\:\mathrm{100}\:\mathrm{000}\:\mathrm{Euros}\:\mathrm{a}\:\mathrm{ete}\:\mathrm{acorde}\:\mathrm{a}\:\mathrm{une}\:\mathrm{personne}\: \\ $$$$\mathrm{pour}\:\mathrm{une}\:\mathrm{duree}\:\boldsymbol{\mathrm{de}}\:\mathrm{3}\:\boldsymbol{\mathrm{mois}}\:\mathrm{sans}\:\mathrm{interet}\:\mathrm{suiuvant}\: \\ $$$$\mathrm{condions}\:\mathrm{suivantes} \\ $$$$\bullet\mathrm{un}\:\mathrm{capital}\:\mathrm{de}\:\mathrm{500}\:\mathrm{000}\:\mathrm{euros}\:\mathrm{au}\:\mathrm{moins}\: \\ $$$$\:\mathrm{dans}\:\mathrm{le}\:\mathrm{compte}\:\mathrm{du}\:\mathrm{debiteur}. \\ $$$$\bullet\mathrm{un}\:\mathrm{specimen}\:\mathrm{de}\:\mathrm{cheque}\:\mathrm{barre}\: \\ $$$$\bullet\mathrm{un}\:\mathrm{interet}\:\mathrm{de}\:\mathrm{5\%}\:\mathrm{aplique}\:\:\mathrm{a}\:\mathrm{partir}\:\mathrm{du}\: \\ $$$$\boldsymbol{\mathrm{deuxieme}}\:\boldsymbol{\mathrm{mois}}\:\:\mathrm{et}\:\mathrm{pendant}\:\mathrm{1}\:\mathrm{mois}\: \\…
Question Number 202765 by Mastermind last updated on 02/Jan/24 Answered by aleks041103 last updated on 02/Jan/24 $$\frac{{x}+{x}^{\mathrm{2}} +…+{x}^{{n}} −{n}}{{x}−\mathrm{1}}= \\ $$$$=\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{x}^{{k}} −\mathrm{1}}{{x}−\mathrm{1}}= \\…
Question Number 202737 by Rasheed.Sindhi last updated on 02/Jan/24 $$\:\:\:\:\:\:\:\:\:\begin{array}{|c|}{\underset{\overset{\overset{\mathrm{2}} {\mathrm{0}}} {\mathrm{24}}} {\mathbb{H}^{\mathbb{A}^{\mathbb{P}^{\mathbb{P}^{\mathbb{Y}^{\mathbb{N}^{\mathbb{E}} \mathbb{W}} \mathbb{Y}} \mathbb{E}} \mathbb{A}} \mathbb{R}} \:!}}\\\hline\end{array} \\ $$ Answered by witcher3 last…
Question Number 202760 by Mastermind last updated on 02/Jan/24 Answered by ajfour last updated on 02/Jan/24 $$\frac{\pi}{\mathrm{2}} \\ $$ Commented by Mastermind last updated on…
Question Number 202761 by Mastermind last updated on 02/Jan/24 Answered by shunmisaki007 last updated on 03/Jan/24 $${g}\left({x}\right)={f}^{−\mathrm{1}} \left({x}\right) \\ $$$${f}\left({x}\right)={g}^{−\mathrm{1}} \left({x}\right) \\ $$$${f}'\left({x}\right)=\mathrm{sin}\left({x}\right) \\ $$$${f}\left({x}\right)={c}−\mathrm{cos}\left({x}\right)\:\mathrm{where}\:{c}\:\mathrm{is}\:\mathrm{constant}.…