Question Number 48826 by ggny last updated on 29/Nov/18 $$\mathrm{2}\frac{\mathrm{5}}{\mathrm{7}}\:\:\:\:\:\:\:\:\:\:\:\mathrm{380} \\ $$$$\mathrm{8}\frac{\mathrm{3}}{\mathrm{7}}\:\:\:\:\:\:\:\:\:\:\:\:\:×\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{plz}\:{help}\:{me} \\ $$$$ \\ $$$$ \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 29/Nov/18…
Question Number 179886 by yaojunon2t last updated on 03/Nov/22 Commented by yaojunon2t last updated on 03/Nov/22 $$\because{e}^{{i}\theta} =\mathrm{cos}\:\theta+{i}\:\mathrm{sin}\:\theta,\theta=\frac{\pi}{\mathrm{2}}+\mathrm{2}{k}\pi \\ $$$$\therefore{e}^{{i}\left(\frac{\pi}{\mathrm{2}}+\mathrm{2}{k}\pi\right)} =\mathrm{cos}\:\frac{\pi}{\mathrm{2}}+{i}\:\mathrm{sin}\:\frac{\pi}{\mathrm{2}} \\ $$$$\therefore{e}^{{i}\left(\frac{\pi}{\mathrm{2}}+\mathrm{2}{k}\pi\right)} ={i} \\…
Question Number 48815 by tanmay.chaudhury50@gmail.com last updated on 29/Nov/18 $${who}\:{red}\:{marked}\:…{better}\:{you}\:{come}\:{forwaed} \\ $$$${and}\:{say}…{it}\:{is}\:{better}\:{to}\:{show}\:{the}\:{way}\:{rather}\:{become} \\ $$$${cynic}… \\ $$$${better}\:{you}\:{solve}\:{your}\:{self}\:{and}\:{show}\:{the}\:{results} \\ $$$${rather}\:{pointing}\:{fingure}\:{to}\:{others}… \\ $$$$ \\ $$ Commented by mr…
Question Number 114343 by toa last updated on 18/Sep/20 $$\mathrm{How}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{we}\:\mathrm{place}\:\mathrm{5}\:\mathrm{identical} \\ $$$$\mathrm{books}\:\mathrm{and}\:\mathrm{another}\:\mathrm{6}\:\mathrm{identical}\:\mathrm{books} \\ $$$$\mathrm{on}\:\mathrm{a}\:\mathrm{shelf}? \\ $$ Commented by bemath last updated on 18/Sep/20 $$=\:\frac{\mathrm{11}!}{\mathrm{5}!.\mathrm{6}!} \\…
Question Number 48750 by tanmay.chaudhury50@gmail.com last updated on 28/Nov/18 $${i}\:{need}\:{explanation}\:{for}\:{the}\:{division}\:{when}\:\mathrm{20751} \\ $$$${is}\:{devided}\:{by}\:\mathrm{25} \\ $$$${answer}\:{is}\:\mathrm{830}.\mathrm{04}..{i}\:{need}\:{clarification}\:{why} \\ $$$${this}\:{red}\:{coloured}\:{zero}\:\left(\mathrm{0}\right)\:{is}\:{coming}\: \\ $$$${when}\:{division}\:{is}\:{done}\:{by}\:{simple}\:{division}… \\ $$ Answered by MJS last updated…
Question Number 48729 by Raj Singh last updated on 27/Nov/18 Answered by mr W last updated on 27/Nov/18 $${V}=\pi{R}^{\mathrm{2}} {H} \\ $$$${V}_{\mathrm{1}} =\pi{R}_{\mathrm{1}} ^{\mathrm{2}} {H}_{\mathrm{1}}…
Question Number 48724 by indalecioneves last updated on 29/Nov/18 $${Hey},\:{everyone}! \\ $$$${Could}\:\:{someone}\:{help}\:{in}\:{this}\:{question}\:{below}? \\ $$$${The}\:{vectors}\:\left(\mathrm{1},\:\mathrm{2},\:\mathrm{5}\right),\:\left(\mathrm{3},\:\mathrm{2},\:\mathrm{1}\right)\:{and}\:\left(\mathrm{9},\:\mathrm{2},\:−\mathrm{11}\right)\:{in}\:\mathbb{R}^{\mathrm{3}} \:{generate}\:{the}\:{vector}\:{subspace}\:{to}\:{wich}\:{belongs}\:{the}\:{vector}? \\ $$$$\left.{a}\right)\:\left(−\mathrm{20},\:−\mathrm{8},\:\mathrm{12}\right) \\ $$$$\left.{b}\right)\:\left(\mathrm{2},\:\mathrm{10},\:\mathrm{33}\right) \\ $$$$\left.{c}\right)\:\left(\mathrm{9},\:\mathrm{10},\:\mathrm{18}\right) \\ $$$$\left.{d}\right)\:\left(\mathrm{5},\:\mathrm{2},\:−\mathrm{2}\right) \\ $$$$\left.{e}\right)\:\left(\mathrm{31},\:\mathrm{18},\:\mathrm{0}\right)…
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Question Number 48426 by tanmay.chaudhury50@gmail.com last updated on 23/Nov/18 Commented by tanmay.chaudhury50@gmail.com last updated on 23/Nov/18 Commented by tanmay.chaudhury50@gmail.com last updated on 23/Nov/18 Commented by…
Question Number 113897 by Lordose last updated on 16/Sep/20 Answered by mathmax by abdo last updated on 17/Sep/20 $$\mathrm{let}\:\mathrm{u}_{\mathrm{n}} =\frac{\mathrm{3}^{\mathrm{n}} }{\:\sqrt{\left(\mathrm{3n}−\mathrm{2}\right)\mathrm{2}^{\mathrm{n}} }}\:\Rightarrow\mathrm{u}_{\mathrm{n}} =\frac{\left(\frac{\mathrm{3}}{\:\sqrt{\mathrm{2}}}\right)^{\mathrm{n}} }{\:\sqrt{\mathrm{3n}−\mathrm{2}}}\:\:\left(\mathrm{n}\geqslant\mathrm{1}\right)\:\Rightarrow \\…