Question Number 112245 by Dwaipayan Shikari last updated on 06/Sep/20 $$\frac{\mathrm{1}}{\mathrm{1}+{x}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{1}+{x}^{\mathrm{4}} }+\frac{\mathrm{1}}{\mathrm{1}+{x}^{\mathrm{8}} }+…..\:\:\:\:\:\:\:\:\:\:\left(\:{x}>\mathrm{1}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 46697 by KMA last updated on 30/Oct/18 $${Find}\:{the}\:{sum}\:{of}\:{the}\:{first}\:{nterms}\: \\ $$$${of}\:{the}\:{G}.{P}\:\mathrm{3}+\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}}+…{and}\:{show}\:{that} \\ $$$${the}\:{sum}\:{cannot}\:{exceed}\:\frac{\mathrm{9}}{\mathrm{2}}\:{however} \\ $$$${great}\:{n}\:{may}\:{be}. \\ $$ Answered by Joel578 last updated on 30/Oct/18…
Question Number 46674 by Nabraj Awasthi last updated on 30/Oct/18 $${why}\:{slope}\:{is}\:{represented}\:{by}\:{m} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 30/Oct/18 $${it}\:{is}\:{a}\:{symbol}\:{only}…{you}\:{can}\:{put}\:{any}\:{alphabet}\: \\ $$$${out}\:{of}\:\mathrm{26}…{but}\:{you}\:{have}\:{to}\:{mention}\:{that}\:{the} \\ $$$${alphabet}\:{represent}\:{slope}……
Question Number 46651 by gunay last updated on 29/Oct/18 $$\mathrm{3}\frac{\mathrm{8}}{\mathrm{19}}−\mathrm{2x}=\mathrm{1}\frac{\mathrm{6}}{\mathrm{19}} \\ $$$$\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 29/Oct/18 $$\left(\mathrm{3}+\frac{\mathrm{8}}{\mathrm{19}}\right)−\left(\mathrm{1}+\frac{\mathrm{6}}{\mathrm{19}}\right)=\mathrm{2}{x} \\ $$$$\left(\mathrm{3}−\mathrm{1}+\frac{\mathrm{8}}{\mathrm{19}}−\frac{\mathrm{6}}{\mathrm{19}}\right)=\mathrm{2}{x} \\…
Question Number 112162 by 175mohamed last updated on 06/Sep/20 Commented by JDamian last updated on 06/Sep/20 $${Please},\:{define}\:{n}!! \\ $$ Commented by mnjuly1970 last updated on…
Question Number 46558 by azharkhan250963@gmail.com last updated on 28/Oct/18 $${calculate}\:{the}\:{uncertainty}\:{in}\:{velocity}\:{of}\:{an}\:{electron}\:{which}\:{is}\:{confined}\:{in}\:{a}\:\mathrm{10}^{−\mathrm{10}\:} {meter} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 28/Oct/18 $$\bigtriangleup{x}\bigtriangleup{p}_{{x}} =\frac{{h}}{\mathrm{4}\pi} \\ $$$$\bigtriangleup{x}\left({m}\bigtriangleup{v}_{{x}} \right)=\frac{{h}}{\mathrm{4}\pi}…
Question Number 46502 by Ac Kesharwani last updated on 27/Oct/18 $$\int_{\mathrm{0}} ^{\infty} \left(\frac{\mathrm{sin}\:\left(\boldsymbol{\mathrm{x}}\right)}{\boldsymbol{\mathrm{x}}}\right)\boldsymbol{\mathrm{dx}} \\ $$ Commented by math khazana by abdo last updated on 27/Oct/18…
Question Number 46474 by peter frank last updated on 28/Oct/18 $$\left.\mathrm{a}\right)\left[\mathrm{If}\:\mathrm{tan}^{−\mathrm{1}} \mathrm{a}+\mathrm{tan}^{−\mathrm{1}} \mathrm{b}+\mathrm{tan}^{−\mathrm{1}} \mathrm{c}=\pi\:\:\mathrm{show}\:\mathrm{that}\:\frac{\mathrm{a}+\mathrm{b}+\mathrm{c}}{\mathrm{abc}}=\mathrm{1}\right. \\ $$$$\left.\mathrm{b}\right)\left[\:\:\mathrm{If}\:\:\mathrm{tanx}=\frac{\mathrm{nsinycosy}}{\mathrm{1}−\mathrm{nsin}^{\mathrm{2}} \mathrm{y}}\right. \\ $$$$\mathrm{show}\:\mathrm{that}\:\mathrm{tan}\left(\mathrm{y}−\mathrm{x}\right)=\left(\mathrm{1}−\mathrm{n}\right)\mathrm{tany} \\ $$$$ \\ $$$$ \\ $$$$…
Question Number 46473 by peter frank last updated on 27/Oct/18 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\theta \\ $$$$\mathrm{which}\:\mathrm{satisfy}\:\mathrm{the}\: \\ $$$$\mathrm{equation} \\ $$$$\mathrm{cos}\theta\mathrm{x}+\mathrm{cos}\left(\mathrm{x}+\mathrm{2}\right)\theta=\mathrm{cos}\theta \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
Question Number 111975 by 175mohamed last updated on 05/Sep/20 Answered by mathmax by abdo last updated on 05/Sep/20 $$\mathrm{f}\left(\mathrm{0}\right)=\mathrm{d}=\mathrm{k} \\ $$$$\mathrm{f}\left(−\mathrm{2}\right)=\mathrm{0}\:\Rightarrow−\mathrm{8a}+\mathrm{4b}−\mathrm{2c}+\mathrm{d}=\mathrm{0}\:\:\:\:\left(\mathrm{1}\right) \\ $$$$\mathrm{f}\left(−\mathrm{4}\right)\:=−\mathrm{16}\:\Rightarrow−\mathrm{64a}+\mathrm{16b}−\mathrm{4c}+\mathrm{d}\:=−\mathrm{16}\:\:\left(\mathrm{2}\right) \\ $$$$\mathrm{f}^{'}…