Category: Others

Question Number 209430 by Tawa11 last updated on 09/Jul/24 Answered by mr W last updated on 10/Jul/24 $$1)$$$${\omega }_0=\sqrt{\frac{k}{m}}$$$$\zeta =\frac{c}{2\sqrt{mk}}$$$$\omega_{{r}}…

Question Number 209193 by Tawa11 last updated on 03/Jul/24 A pin 6cm high is placed in front of a diverging lens of focal length 15cm,…

Question Number 209023 by Spillover last updated on 30/Jun/24 Commented by Spillover last updated on 01/Jul/24 $$letu=\frac{4x}{1+5x}\frac{du}{dx}=\frac{4}{{(1+5x)}^2}$$$$\frac{{d}}{{dx}}\left(\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{4}{x}}{\mathrm{1}+\mathrm{5}{x}}\right)=\frac{\frac{\mathrm{4}}{\left(\mathrm{1}+\mathrm{5}{x}\right)^{\mathrm{2}} }}{\mathrm{1}+\left(\frac{\mathrm{4}{x}}{\mathrm{1}+\mathrm{5}{x}}\right)^{\mathrm{2}} }=\frac{\mathrm{4}}{\mathrm{1}+\mathrm{10}{x}+\mathrm{25}{x}^{\mathrm{2}} } \…

Question Number 209016 by Spillover last updated on 30/Jun/24 Answered by Spillover last updated on 02/Jul/24 Answered by Spillover last updated on 02/Jul/24 Terms of…

Question Number 209026 by Spillover last updated on 30/Jun/24 Answered by Spillover last updated on 07/Jul/24 $$f\left(x\right)=\left(\frac{4}{x}\right){\left(\frac{1}{4}\right)}^x{\left(\frac{3}{4}\right)}^{4-x}$$$$x=0,1,2,3,4$$$${f}\left(\mathrm{1}\right)=\left(\frac{\mathrm{4}}{\mathrm{1}}\right)\left(\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{1}} \left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{4}−\mathrm{1}} =\left(\frac{\mathrm{4}}{\mathrm{1}}\right)\left(\frac{\mathrm{1}}{\mathrm{4}}\right)\left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{3}}…