Question Number 198869 by Tawa11 last updated on 25/Oct/23 Commented by mr W last updated on 25/Oct/23 $$\mathrm{26}.\mathrm{8}\:\mathrm{cos}\:\mathrm{10}°\neq\mathrm{28}.\mathrm{2}\:\mathrm{cos}\:\mathrm{20}° \\ $$$$\Rightarrow{something}\:{in}\:{question}\:{is}\:{wrong}! \\ $$ Commented by Tawa11…
Question Number 198860 by cherokeesay last updated on 25/Oct/23 Answered by mr W last updated on 25/Oct/23 $$\left.{D}\right)\:{is}\:{correct}. \\ $$$${the}\:{force}\:{moved}\:{the}\:{block}\:{to}\:{a}\:{height} \\ $$$${a}\:\mathrm{sin}\:\theta,\:{the}\:{work}\:{done}\:{is}\:{wa}\:\mathrm{sin}\:\theta. \\ $$$${the}\:{force}\:{pulled}\:{the}\:{spring}\:{to}\:{a}\:{length} \\…
Question Number 198566 by tri26112004 last updated on 22/Oct/23 $$\frac{\mathrm{3}{x}^{\mathrm{2}} −\mathrm{1}}{{x}}+\frac{\mathrm{5}{x}}{\mathrm{3}{x}^{\mathrm{2}} −{x}−\mathrm{1}}=\frac{\mathrm{119}}{\mathrm{18}} \\ $$ Answered by Rasheed.Sindhi last updated on 22/Oct/23 $$\frac{\mathrm{3}{x}^{\mathrm{2}} −\mathrm{1}}{{x}}+\frac{\mathrm{5}{x}}{\mathrm{3}{x}^{\mathrm{2}} −{x}−\mathrm{1}}=\frac{\mathrm{119}}{\mathrm{18}} \\…
Question Number 198555 by Tawa11 last updated on 21/Oct/23 Commented by ajfour last updated on 23/Oct/23 $${both}\:{answers}\:\:\:{t}=\frac{\mathrm{17}}{\mathrm{3}}\:{s}\:\:\:{or}\:\:{t}=\mathrm{5}{s} \\ $$$${i}\:{would}\:{consider}\:{right}. \\ $$ Commented by Tawa11 last…
Question Number 198465 by BHOOPENDRA last updated on 20/Oct/23 $${The}\:{furier}\:{series}\:{approximation}\:{to}\: \\ $$$${the}\:{forcing}\:{function}\:{is}\:{given}\:{by}\: \\ $$$${f}\left({t}\right)=\mathrm{5}\left[\mathrm{1}+\frac{\mathrm{4}}{\pi}\left(\frac{}{}\frac{{sin}\mathrm{120}\pi{t}}{\mathrm{1}}+\frac{{sin}\mathrm{360}\pi{t}}{\mathrm{2}}+\frac{{sin}\mathrm{600}\pi{t}}{\mathrm{3}}\right.\right. \\ $$$$\left.\:\left.\:\:\:\:\:+………\right)\right] \\ $$$${The}\:{transfer}\:{function}\:{for}\:{this} \\ $$$${problem}\:\:{T}\left({s}\right)=\frac{{X}\left({s}\right)}{{f}\left({s}\right)}=\frac{\mathrm{1}}{{ms}^{\mathrm{2}} +{cs}+{k}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{1}}{\mathrm{0}.\mathrm{001}{s}+\mathrm{1}} \\ $$$$\mathrm{1}.\:{plot}\:{the}\:{amplitude}\:{spectrum}\:…
Question Number 198426 by BHOOPENDRA last updated on 19/Oct/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198309 by BHOOPENDRA last updated on 17/Oct/23 Commented by BHOOPENDRA last updated on 17/Oct/23 $${Sketch}\:{the}\:{partial}\:{auxiliary}\:{view}\:{for}\: \\ $$$${the}\:{auxiliary}\:{surface}\:{object}\:,{given}\: \\ $$$${the}\:{front}\:{and}\:{right}\:{view}. \\ $$ Commented by…
Question Number 198186 by Tawa11 last updated on 13/Oct/23 Answered by mr W last updated on 13/Oct/23 $${y}\left({t}\right)=\mathrm{2}\:\mathrm{sin}\:\left(\frac{\mathrm{2}\pi{t}}{{T}}\right) \\ $$$${y}\left(\mathrm{0}.\mathrm{4}\right)=\mathrm{2}\:\mathrm{sin}\:\left(\frac{\mathrm{2}\pi×\mathrm{0}.\mathrm{4}}{\mathrm{1}.\mathrm{0}}\right)=\mathrm{0}.\mathrm{09}\:{cm} \\ $$ Commented by Tawa11…
Question Number 198187 by Tawa11 last updated on 13/Oct/23 Commented by Blackpanther last updated on 13/Oct/23 $$\mathrm{0}.\mathrm{1} \\ $$ Answered by mr W last updated…
Question Number 198146 by necx122 last updated on 11/Oct/23 $${Please}\:{suggest}\:{youtube}\:{playlist}\:{to} \\ $$$${prepare}\:{one}\:{for}\:{mathematics}\:{olympiad}. \\ $$$${Thanks}\:{in}\:{advance}. \\ $$$$ \\ $$ Commented by TheHoneyCat last updated on 13/Oct/23…