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Question-40917

Question Number 40917 by Tawa1 last updated on 29/Jul/18 Answered by tanmay.chaudhury50@gmail.com last updated on 30/Jul/18 $$\mathrm{3}−\mathrm{1}×{i}_{\mathrm{3}} +\mathrm{1}×{i}_{\mathrm{2}} −\mathrm{4}×{i}_{\mathrm{3}} −\mathrm{15}=\mathrm{0} \\ $$$${i}_{\mathrm{2}} −\mathrm{5}{i}_{\mathrm{3}} =\mathrm{12}…{eqn}\mathrm{1} \\…

Question-40918

Question Number 40918 by Tawa1 last updated on 29/Jul/18 Answered by tanmay.chaudhury50@gmail.com last updated on 30/Jul/18 $${i}\:{am}\:{using}\:{another}\:{mdthod}\:{to}\:{find}\:{current}\:{through}\:{R}_{{L}} \\ $$$${let}\:{i}_{\mathrm{1}} \:{current}\:{confined}\:{infirst}\:{mesh} \\ $$$${i}_{\mathrm{2}} \:\:{in}\:{second}\:{mesh} \\ $$$${i}_{\mathrm{3}}…

A-ladder-placed-against-a-vertical-walls-ubtends-an-angle-of-45-degree-with-thewall-The-distance-between-the-footo-f-the-ladder-and-the-wall-is-15mt-calculae-the-length-of-the-ladder-correctto-the-

Question Number 106373 by chichi last updated on 04/Aug/20 $$ \\ $$$$\mathrm{A}\:\mathrm{ladder}\:\mathrm{placed}\:\mathrm{against}\:\mathrm{a}\:\mathrm{vertical}\:\mathrm{walls} \\ $$$$\mathrm{ubtends}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{45}\:\mathrm{degree}\:\mathrm{with}\: \\ $$$$\mathrm{thewall}\:\mathrm{The}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{the}\:\mathrm{footo} \\ $$$$\mathrm{f}\:\mathrm{the}\:\mathrm{ladder}\:\mathrm{and}\:\mathrm{the}\:\mathrm{wall}\:\mathrm{is}\:\mathrm{15mt} \\ $$$$\mathrm{calculae}\:\mathrm{the}\:\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{ladder}\: \\ $$$$\mathrm{correctto}\:\mathrm{the}\:\mathrm{nearest}\:\mathrm{whole}\:\mathrm{number}. \\ $$ Answered…

Question-106366

Question Number 106366 by 175mohamed last updated on 04/Aug/20 Answered by mathmax by abdo last updated on 05/Aug/20 $$\mathrm{cosx}\:=\mathrm{1}−\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{2}}\:+\frac{\mathrm{x}^{\mathrm{4}} }{\mathrm{4}!}\:+…\:\Rightarrow\mathrm{1}−\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{2}}\leqslant\mathrm{cosx}\:\leqslant\mathrm{1}\:\Rightarrow \\ $$$$\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{k}} }\right)\leqslant\mathrm{cos}\left(\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{k}}…

1-5-2-9-4-13-8-17-16-

Question Number 106337 by Dwaipayan Shikari last updated on 04/Aug/20 $$\mathrm{1}+\frac{\mathrm{5}}{\mathrm{2}}+\frac{\mathrm{9}}{\mathrm{4}}+\frac{\mathrm{13}}{\mathrm{8}}+\frac{\mathrm{17}}{\mathrm{16}}+…… \\ $$ Commented by Dwaipayan Shikari last updated on 04/Aug/20 $$\mathrm{1}+\mathrm{5}{x}+\mathrm{9}{x}^{\mathrm{2}} +\mathrm{13}{x}^{\mathrm{3}} +\mathrm{17}{x}^{\mathrm{4}} +……\:\:\:\:\:\left({x}=\frac{\mathrm{1}}{\mathrm{2}}\right)…