Question Number 171614 by Tawa11 last updated on 18/Jun/22 A particle is moving along a straight line such that it's position from a fixed point…
Question Number 171599 by Mastermind last updated on 18/Jun/22 $$\Omega=\int_{\mathrm{0}} ^{\mathrm{1}} {Log}\left(\frac{{Log}^{\mathrm{2}} \left({x}\right)}{{x}^{{x}^{\mathrm{5}} −{x}^{\mathrm{4}} +{x}^{\mathrm{3}} −{x}^{\mathrm{2}} +{x}−\mathrm{1}} }\right){dx} \\ $$$$ \\ $$$${Mastermind} \\ $$ Terms…
Question Number 40523 by scientist last updated on 23/Jul/18 $${If}\:\left(\mathrm{1}+{ax}+{bx}^{\mathrm{2}} \right)\left(\mathrm{1}−\mathrm{2}{x}\right)^{\mathrm{18}} \:\:{can}\:{be}\:{expanded}\:{using} \\ $$$${binomial}\:{theorem}\:{in}\:{ascending}\:{power}\:{of}\:{x}.{Determine} \\ $$$${the}\:{value}\:{of}\:\:\:{a}\:{and}\:{b},{if}\:{the}\:{coefficient}\:{of}\:{x}^{\mathrm{3}} \:\:{and}\:{x}^{\mathrm{4}\:} \:\:{are}\:{both}\:{zero}. \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated…
Question Number 40510 by KMA last updated on 23/Jul/18 $${Given}\:{that}\:{ax}+{b}\:{is}\:{a}\:{factor}\:{of}\:{x}^{\mathrm{2}} \\ $$$$+\mathrm{2}{x}^{\mathrm{2}} −\mathrm{1}\:{and}\:−{a}\:{is}\:{a}\:{root}\:{of}\:{x}^{\mathrm{2}} +\mathrm{2}{x} \\ $$$$−\mathrm{1}=\mathrm{0}\:{show}\:{that}\:{the}\:{value}\:{of}\:{b}\:{is} \\ $$$$−\mathrm{1}\:{or}\:\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}\:.} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated…
Question Number 171575 by Furious last updated on 18/Jun/22 Commented by Furious last updated on 18/Jun/22 $${pleaseineedheopontyeitherpart} \\ $$ Commented by Furious last updated on…
Question Number 106039 by 175mohamed last updated on 02/Aug/20 $${if}\:\:\left({f}\:{o}\:{g}\:\right)\left({x}\right)\:=\:{x}\:\:{and}\:{f}'\left({x}\right)=\mathrm{1}\:+\:\left({f}\left({x}\right)\right)^{\mathrm{2}} \\ $$$${then}\:{g}'\left(\mathrm{2}\right)\:=\:…. \\ $$$$ \\ $$ Answered by bemath last updated on 02/Aug/20 $$\frac{\mathrm{d}\left(\mathrm{f}\circ\mathrm{g}\right)\left(\mathrm{x}\right)}{\mathrm{dx}}\:=\:\mathrm{g}'\left(\mathrm{x}\right).\mathrm{f}\:'\left(\mathrm{g}\left(\mathrm{x}\right)\right)=\:\mathrm{1} \\…
Question Number 40497 by uker last updated on 22/Jul/18 $${please}\:{i}\:{want}\:{to}\:{have}\:{applications}\:{of}\: \\ $$$${limits}\:{in}\:{maths}\:{and}\:{other}\:{sciences}\: \\ $$$$ \\ $$ Commented by prof Abdo imad last updated on 23/Jul/18…
Question Number 40466 by naziri2013@ last updated on 22/Jul/18 $$ \\ $$$$ \\ $$$$ \\ $$$${Q}..\mathrm{cos}^{−\mathrm{1}} \left(\mathrm{1}−\mathrm{2}{x}^{\mathrm{2}} \right)=\mathrm{2sin}^{−\mathrm{1}} {x},{prove}\:\:\: \\ $$$${please} \\ $$$$ \\ $$$$…
Question Number 171518 by Mastermind last updated on 16/Jun/22 Commented by JDamian last updated on 16/Jun/22 $${the}\:{same}\:{ever}\:{tricky}\:{puzzles}\:{again}\:{and}\:{again}… \\ $$$${Both}\:{overall}\:{figures}\:{are}\:{not}\:{triangles} \\ $$$${because}\:{the}\:{red}\:{triangle}\:{and}\:{the}\:{dark} \\ $$$${green}\:{one}\:{are}\:\boldsymbol{{not}}\:{similar}. \\ $$$$…
Question Number 171502 by LEKOUMA last updated on 16/Jun/22 $${Solve} \\ $$$$\frac{{dy}}{{dx}}\left({x}\mathrm{cos}\:{y}+{a}\mathrm{sin}\:\mathrm{2}{y}\right)=−\mathrm{1} \\ $$$$\frac{{dy}}{{dx}}=\left(\frac{{y}+\mathrm{2}}{{x}+{y}−\mathrm{1}}\right)^{\mathrm{2}} \\ $$ Commented by mokys last updated on 16/Jun/22 $$ \\…