Question Number 170986 by Tawa11 last updated on 05/Jun/22 Commented by mr W last updated on 05/Jun/22 $${too}\:{easy}\:… \\ $$$${A}\:{covers}\:\frac{\mathrm{15}}{\mathrm{15}+\mathrm{10}}=\frac{\mathrm{3}}{\mathrm{5}} \\ $$$${B}\:{covers}\:\frac{\mathrm{10}}{\mathrm{15}+\mathrm{10}}=\frac{\mathrm{2}}{\mathrm{5}} \\ $$ Commented…
Question Number 39899 by Rio Mike last updated on 13/Jul/18 $${Given}\:{the}\:{lines}\: \\ $$$${l}_{\mathrm{1}} ;\:\mathrm{3}{y}\:=\:\mathrm{2}{x}\:,{l}_{\mathrm{2}} ;\:{y}\:=\:−\frac{\mathrm{3}{x}}{\mathrm{2}}\:+\:{p} \\ $$$${and}\:{l}_{\mathrm{3}} ;\:{y}\overset{} {\:}=\:{x}\:+\:\mathrm{1} \\ $$$$\left.{a}\right)\:{find}\:{the}\:{value}\:{of}\:{p}\:{if}\: \\ $$$${the}\:{point}\:{of}\:{intersection}\:{between} \\ $$$${l}_{\mathrm{1}}…
Question Number 39879 by Rio Mike last updated on 12/Jul/18 $${let}\: \\ $$$${p}\left({x}\right)=\:{x}^{\mathrm{3}} \:+\:\mathrm{3}{x}\:−\:\mathrm{4} \\ $$$${find}\:\alpha+\beta\:{and}\: \\ $$$$\alpha\beta \\ $$$$ \\ $$$$ \\ $$ Answered…
Question Number 170948 by Mastermind last updated on 04/Jun/22 $$\mathrm{A}^{\mathrm{x}^{\mathrm{x}} } +\mathrm{Bx}^{\mathrm{x}} +\mathrm{C}=\mathrm{R},\:\mathrm{Make}\:\mathrm{x}\:\mathrm{the}\:\mathrm{subject} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{formular} \\ $$ Commented by mr W last updated on 04/Jun/22…
Question Number 170950 by Mastermind last updated on 04/Jun/22 $$\mathrm{e}^{\mathrm{x}} =\mathrm{ln}\left(\mathrm{x}\right),\:\mathrm{Make}\:\mathrm{x}\:\mathrm{the}\:\mathrm{subject}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{formula} \\ $$$$\mathrm{moreover}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x} \\ $$ Commented by mr W last updated on 05/Jun/22…
Question Number 170946 by Mastermind last updated on 04/Jun/22 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{x}\:: \\ $$$$\mathrm{3}^{\mathrm{x}} =\mathrm{2x}+\mathrm{2} \\ $$$$ \\ $$$$\mathrm{Mastermind} \\ $$ Answered by mr W last updated…
Question Number 39851 by Raj Singh last updated on 12/Jul/18 Commented by MrW3 last updated on 12/Jul/18 $${let}\:{u}=\sqrt{{x}}\geqslant\mathrm{0},\:{v}=\sqrt{{y}}\geqslant\mathrm{0} \\ $$$${u}+{v}=\mathrm{13} \\ $$$${u}^{\mathrm{2}} +{v}^{\mathrm{2}} =\mathrm{13} \\…
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Question Number 170906 by MASANJAJJ last updated on 03/Jun/22 Answered by thfchristopher last updated on 03/Jun/22 $$\frac{\mathrm{2}}{\mathrm{5}}=\frac{\mathrm{2600}}{{S}} \\ $$$${S}=\mathrm{6500}\:\mathrm{litres}\:\left(\mathrm{The}\:\mathrm{second}\:\mathrm{tank}\:\mathrm{volume}\right) \\ $$$$\mathrm{Total}\:\mathrm{volumes}\:\mathrm{of}\:\mathrm{two}\:\mathrm{tanks} \\ $$$$=\mathrm{2600}+\mathrm{6500} \\ $$$$=\mathrm{9100}\:\mathrm{litres}…
Question Number 39827 by Rio Mike last updated on 11/Jul/18 $${if}\:{f}\left({x}\right)\:=\:\mathrm{3}{x}^{\mathrm{3}} \:+\:{px}^{\mathrm{2}} \:+\:\mathrm{4}{x}\:−\:\mathrm{8} \\ $$$${and}\:\left({x}\:−\:\mathrm{1}\right)\:{is}\:{a}\:{factor}\:{of}\: \\ $$$${f}\left({x}\right). \\ $$$$\left.{a}\right)\:{find}\:{the}\:{value}\:{of}\:{p}. \\ $$$${with}\:{these}\:{value}\:{of}\:{p} \\ $$$$\left.{b}\right)\:{solve}\:{the}\:{equation}\:{f}\left({x}\right)\:=\:\mathrm{0}. \\ $$$${if}\:\alpha\:{and}\:\beta\:{are}\:{roots}\:{of}\:…