Question Number 105488 by 175mohamed last updated on 29/Jul/20 $${if}\:{y}\:=\:{cos}\left({x}^{\mathrm{2}} \right)\:\:\:\:\:\:{then}\: \\ $$$$\:\:\:\:\:\:{y}^{\left({n}\right)} \:=\:……… \\ $$ Answered by mathmax by abdo last updated on 29/Jul/20…
Question Number 171009 by Mastermind last updated on 06/Jun/22 $${Find}\:{the}\:{inverse},\:{y}^{−\mathrm{1}} \:{of}\:{the}\:{function} \\ $$$${y}={x}^{\mathrm{3}} +\mathrm{4}. \\ $$$$ \\ $$$${Mastermind} \\ $$ Answered by a.lgnaoui last updated…
Question Number 171008 by Mastermind last updated on 06/Jun/22 $${Find}\:{the}\:{maximum}\:{and}\:{minimum} \\ $$$${values}\:{of}\:{h}\left({x}\right)=\frac{\mathrm{4}}{\mathrm{3}}{x}^{\mathrm{3}} +\frac{\mathrm{9}}{\mathrm{2}}{x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{8}. \\ $$$$ \\ $$$${Mastermind} \\ $$ Commented by mr W last…
Question Number 171005 by Mastermind last updated on 06/Jun/22 $${The}\:{distance}\:{S}\:{metre}\:{travelled}\:{in}\:{time} \\ $$$${t}\:{seconds}\:{by}\:{an}\:{object}\:{released}\:{from} \\ $$$${rest}\:{and}\:{allow}\:{to}\:{fall}\:{freely}\:{under}\:{the} \\ $$$${force}\:{of}\:{gravity}\:{is}\:{given}\:{by}\:{s}\left({t}\right)=\mathrm{4}.\mathrm{5}{t}^{\mathrm{2}} . \\ $$$${find}\: \\ $$$$\left.{a}\right)\:{the}\:{average}\:{speed}\:{of}\:{the}\:{object} \\ $$$${during}\:{the}\:{time}\:{interval}\:{from}\:\mathrm{2}\:{to} \\ $$$$\mathrm{2}.\mathrm{5}\:{seconds}.…
Question Number 171006 by Mastermind last updated on 06/Jun/22 $${Find}\:{the}\:{area}\:{enclosed}\:{by}\:{the}\:{curve} \\ $$$${y}=\mathrm{4}−\mathrm{3}{x}^{\mathrm{2}} \:{and}\:{the}\:{x}−{axis}\:{between} \\ $$$${x}_{\mathrm{1}} =−\mathrm{1}\:{and}\:{x}_{\mathrm{2}} =\mathrm{1}. \\ $$$$ \\ $$$${Mastermind} \\ $$ Commented by…
Question Number 170997 by Mastermind last updated on 06/Jun/22 $${Find}\:{the}\:{equation}\:{of}\:{the}\:{tangent}\:{to}\:{the} \\ $$$${curve}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{6}{y}−\mathrm{12}=\mathrm{0}\:{at}\:{the} \\ $$$${point}\:\left(\mathrm{2},\:\mathrm{3}\right). \\ $$$$ \\ $$$${Mastermind} \\ $$ Answered by depressiveshrek…
Question Number 170996 by Mastermind last updated on 06/Jun/22 $${Find}\:{the}\:{volume}\:{of}\:{the}\:{solid}\:{obtained} \\ $$$${by}\:{rotating}\:{about}\:{x}−{axis}\:{of}\:{the}\:{curve} \\ $$$${y}=\sqrt{{x}}\:{on}\:{the}\:{interval}\:\left[\mathrm{0},\:\mathrm{2}\right]. \\ $$$$ \\ $$$${Mastermind} \\ $$ Answered by mr W last…
Question Number 170995 by Mastermind last updated on 05/Jun/22 $${Approximate}\:{sin}\mathrm{46}°\:{by}\:“{differentials}'' \\ $$$$ \\ $$$${Mastermind} \\ $$ Commented by mr W last updated on 06/Jun/22 $$\mathrm{sin}\:\mathrm{46}°=\mathrm{sin}\:\left(\frac{\pi}{\mathrm{4}}+\frac{\pi}{\mathrm{180}}\right)…
Question Number 39914 by solihin last updated on 13/Jul/18 Commented by MrW3 last updated on 13/Jul/18 $${z}=\frac{{i}}{\mathrm{2}−{i}}=\frac{{i}\:\left(\mathrm{2}+{i}\right)}{\left(\mathrm{2}−{i}\right)\left(\mathrm{2}+{i}\right)}=\frac{−\mathrm{1}+\mathrm{2}{i}}{\mathrm{5}}=−\frac{\mathrm{1}}{\mathrm{5}}+\frac{\mathrm{2}}{\mathrm{5}}{i} \\ $$$$=\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}\left(−\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}+\frac{\mathrm{2}}{\:\sqrt{\mathrm{5}}}{i}\right) \\ $$$$={r}\left(\mathrm{cos}\:\theta+{i}\:\mathrm{sin}\:\theta\right) \\ $$$${with}\:{r}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}} \\ $$$$\theta=\pi−\mathrm{tan}^{−\mathrm{1}}…
Question Number 170994 by Mastermind last updated on 05/Jun/22 $$\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{function}\:\mathrm{h}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{5}} −\mathrm{2x} \\ $$$$\mathrm{is}\:\mathrm{an}\:\mathrm{odd}\:\mathrm{function} \\ $$$$ \\ $$$$\mathrm{Mastermind} \\ $$ Answered by Rasheed.Sindhi last updated on…