Question Number 215975 by Tawa11 last updated on 23/Jan/25 Answered by Tawa11 last updated on 23/Jan/25 $$\mathrm{v}\:\:=\:\:\mathrm{1}.\mathrm{98}\:\mathrm{m}/\mathrm{s}\:\:\:\:\:\mathrm{at}\:\mathrm{the}\:\mathrm{back}\:\mathrm{of}\:\mathrm{the}\:\mathrm{book}. \\ $$ Answered by mr W last updated…
Question Number 215943 by sitholenonto last updated on 22/Jan/25 Answered by MathematicalUser2357 last updated on 23/Jan/25 $$\mathrm{Q}.\mathrm{2}.\mathrm{1} \\ $$$$\sqrt{\left(\mathrm{30}−\mathrm{10}×\mathrm{tan}\:\mathrm{60}°\right)^{\mathrm{2}} +\mathrm{10}^{\mathrm{2}} } \\ $$$$\mathrm{16}.\mathrm{14836}\checkmark \\ $$$$\mathrm{Q}.\mathrm{2}.\mathrm{2}…
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Question Number 215746 by Tawa11 last updated on 16/Jan/25 A particle of mass 98kg is suspended by two light inelastic strings of lengths 9m and…
t-33-ab-t-00-ab-Clearing-up-defintions-t-33-a-a-36-3-t-00-a-a-36-0-t-a-a-36-t-a-transformation-of-a-
Question Number 215527 by alephnull last updated on 09/Jan/25 $${t}_{\mathrm{33}} '{ab}+{t}_{\mathrm{00}} '{ab}=? \\ $$$$ \\ $$$$\mathrm{Clearing}\:\mathrm{up}\:\mathrm{defintions}: \\ $$$${t}_{\mathrm{33}} '{a}=\left({a}−\sqrt{\mathrm{36}}\right)×\mathrm{3} \\ $$$${t}_{\mathrm{00}} '{a}=\left({a}−\sqrt{\mathrm{36}}\right)×\mathrm{0} \\ $$$${t}'{a}={a}−\sqrt{\mathrm{36}} \\…
Question Number 215255 by Rasheed.Sindhi last updated on 01/Jan/25 $${a},{b},{c}\:{are}\:{pythagorean}\:{triples} \\ $$$${For}\:{the}\:{following}\:{values}: \\ $$$$\begin{array}{|c|c|}{{a}}&\hline{{b}}&\hline{\:{c}}\\{\mathrm{5}}&\hline{\mathrm{12}}&\hline{\mathrm{13}}\\\hline\end{array}\:\:\underset{\Rightarrow\mathrm{5}^{\mathrm{2}} =\mathrm{12}+\mathrm{13}=\mathrm{25}} {{a}^{\mathrm{2}} ={b}+{c}\:\:} \\ $$$$\begin{array}{|c|c|}{{a}}&\hline{{b}}&\hline{\:{c}}\\{\mathrm{45}}&\hline{\mathrm{1012}}&\hline{\mathrm{1013}}\\\hline\end{array}\underset{\:\:\:\:\:\:\:\Rightarrow\mathrm{45}^{\mathrm{2}} =\mathrm{1012}+\mathrm{1013}=\mathrm{2025}} {{a}^{\mathrm{2}} ={b}+{c}} \\ $$$$\Rightarrow\mathrm{45}^{\mathrm{2}} =\mathrm{1012}+\mathrm{1013}=\mathrm{2025}…
Question Number 215224 by ppch145 last updated on 31/Dec/24 $$\mathrm{I}\:\mathrm{have}\:\mathrm{just}\:\mathrm{discovered}\:\mathrm{that}\:\mathrm{it}\: \\ $$$$\mathrm{is}\:\mathrm{only}\:\mathrm{alphabetic}\:\mathrm{letters}\:\mathrm{that} \\ $$$$\mathrm{can}\:\mathrm{be}\:\mathrm{made}\:\mathrm{bold}\:\mathrm{while}\: \\ $$$$\mathrm{typing}\:\mathrm{with}\:\mathrm{the}\:\mathrm{keyboard}\:\mathrm{of}\: \\ $$$$\mathrm{this}\:\mathrm{app}.\:\mathrm{Numbers}\:\mathrm{0}\:-\:\mathrm{9}\:\mathrm{can}'\mathrm{t} \\ $$$$\mathrm{be}\:\mathrm{made}\:\mathrm{bold},\:\mathrm{after}\:\mathrm{being}\: \\ $$$$\mathrm{selected}.\: \\ $$$$ \\…
Question Number 215067 by Tawa11 last updated on 27/Dec/24 Commented by ajfour last updated on 27/Dec/24 https://youtu.be/X7ruXB1nU18?si=Qa91ch5ybcVcATkh Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 215032 by Tawa11 last updated on 26/Dec/24 Commented by Tawa11 last updated on 26/Dec/24 $$\mathrm{I}\:\mathrm{got}\:\:\mathrm{10}.\mathrm{3}\:\mathrm{m}/\mathrm{s} \\ $$ Answered by mr W last updated…
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