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Is-complex-infinity-big-1-i-Their-absolute-value-is-big-gt-

Question Number 197459 by MathematicalUser2357 last updated on 18/Sep/23 $$\mathrm{Is}\:\mathrm{complex}\:\mathrm{infinity}\:\mathrm{big}? \\ $$$$\overset{\sim} {\infty}=\infty\centerdot\left(\mathrm{1}+{i}\right) \\ $$$$\mathrm{Their}\:\mathrm{absolute}\:\mathrm{value}\:\mathrm{is}\:\mathrm{big} \\ $$$$\mid\overset{\sim} {\infty}\mid>\mid\infty\mid \\ $$ Commented by TheHoneyCat last updated…

Question-197371

Question Number 197371 by Mastermind last updated on 15/Sep/23 Answered by Rasheed.Sindhi last updated on 15/Sep/23 $${d}:{dog},\:{c}:{cat},\:{r}:{rat} \\ $$$${d}+{r}=\mathrm{20}…\left({i}\right) \\ $$$${c}+{r}=\mathrm{10}…\left({ii}\right) \\ $$$${d}+{c}=\mathrm{24}…\left({iii}\right) \\ $$$$\left({i}\right)+\left({ii}\right)+\left({iii}\right):…

Show-that-log-logi-log-pi-2-i-pi-2-

Question Number 197184 by pete last updated on 10/Sep/23 $$\mathrm{Show}\:\mathrm{that}\:\mathrm{log}\left(−\mathrm{log}{i}\right)=\mathrm{log}\left(\frac{\pi}{\mathrm{2}}\right)−{i}\frac{\pi}{\mathrm{2}} \\ $$ Answered by Frix last updated on 10/Sep/23 $$\mathrm{ln}\:\left(−\mathrm{ln}\:\mathrm{i}\right)\:=\mathrm{ln}\:\frac{\pi}{\mathrm{2}}\:−\mathrm{i}\frac{\pi}{\mathrm{2}} \\ $$$$−\mathrm{ln}\:\mathrm{i}\:=\mathrm{e}^{\mathrm{ln}\:\frac{\pi}{\mathrm{2}}\:−\mathrm{i}\frac{\pi}{\mathrm{2}}} \\ $$$$−\mathrm{ln}\:\mathrm{i}\:=\frac{\pi}{\mathrm{2}}\mathrm{e}^{−\mathrm{i}\frac{\pi}{\mathrm{2}}} \\…

Simplify-2-3-3-2-2-12-6-2-2-3-2-1-3-2-

Question Number 197185 by MathematicalUser2357 last updated on 10/Sep/23 $$\mathrm{Simplify} \\ $$$$\sqrt[{\sqrt{\mathrm{3}}−\sqrt{\mathrm{2}}}]{\frac{\left(\sqrt{\mathrm{2}}\right)^{\sqrt{\mathrm{3}}} \centerdot\left(\sqrt{\mathrm{3}}\right)^{\sqrt{\mathrm{2}}} +\left(\sqrt{\mathrm{2}}\right)^{\sqrt{\mathrm{12}}} }{\left(\sqrt{\mathrm{6}}\right)^{\sqrt{\mathrm{2}}} +\left(\sqrt{\mathrm{2}}\right)^{\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}}} }} \\ $$ Answered by som(math1967) last updated on…

Find-all-the-values-of-sin-1-2-

Question Number 197052 by pete last updated on 07/Sep/23 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:\mathrm{sin}^{−\mathrm{1}} \sqrt{\mathrm{2}} \\ $$ Answered by Frix last updated on 07/Sep/23 $$\mathrm{sin}\:{x}\:=\sqrt{\mathrm{2}} \\ $$$${x}=\left(\mathrm{2}{n}−\frac{\mathrm{1}}{\mathrm{2}}\right)\pi\pm\mathrm{i}\:\mathrm{ln}\:\left(\mathrm{1}+\sqrt{\mathrm{2}}\right) \\ $$$$\mathrm{You}\:\mathrm{get}\:\mathrm{this}\:\mathrm{using}…

Simplify-1-3-i-1-3-i-10-

Question Number 197089 by pete last updated on 07/Sep/23 $$\mathrm{Simplify}\:\left(\frac{\mathrm{1}+\sqrt{\mathrm{3}}\mathrm{i}}{\mathrm{1}−\sqrt{\mathrm{3}}\mathrm{i}}\right)^{\mathrm{10}} \\ $$ Answered by JDamian last updated on 07/Sep/23 $$\left(\frac{{z}}{{z}^{\ast} }\right)^{{n}} =\left(\frac{\cancel{\mid{z}\mid}\centerdot{e}^{{i}\varphi} }{\cancel{\mid{z}\mid}\centerdot{e}^{−{i}\varphi} }\right)^{{n}} ={e}^{{i}\mathrm{2}{n}\varphi}…

Question-196738

Question Number 196738 by Tawa11 last updated on 30/Aug/23 Commented by Tawa11 last updated on 30/Aug/23 $$\mathrm{Please}\:\mathrm{is}\:\mathrm{this}\:\mathrm{solution}\:\mathrm{correct}???. \\ $$$$ \\ $$$$\mathrm{My}\:\mathrm{thinking}. \\ $$$$\mathrm{I}\:\mathrm{thought}\:\mathrm{it}\:\mathrm{should}\:\mathrm{be}\:\mathrm{the}\:\mathrm{horizontal}\:\mathrm{force} \\ $$$$\mathrm{that}\:\mathrm{should}\:\mathrm{accelerate}\:\mathrm{the}\:\mathrm{body},\:\mathrm{not}\:\mathrm{resultant}\:\mathrm{force}.…

A-pilot-flies-his-plane-directly-from-a-point-A-to-a-point-B-a-distance-of-450Km-The-bearing-of-B-from-A-is-030-A-wind-of-80Km-hr-is-blowing-from-the-east-Given-that-the-plane-can-travel-at-320Km

Question Number 196657 by Tawa11 last updated on 28/Aug/23 $$\mathrm{A}\:\mathrm{pilot}\:\mathrm{flies}\:\mathrm{his}\:\mathrm{plane}\:\mathrm{directly}\:\mathrm{from}\:\mathrm{a}\:\mathrm{point}\:\mathrm{A}\:\mathrm{to}\:\mathrm{a}\:\mathrm{point}\:\mathrm{B}, \\ $$$$\mathrm{a}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{450Km}.\:\mathrm{The}\:\mathrm{bearing}\:\mathrm{of}\:\mathrm{B}\:\mathrm{from}\:\mathrm{A}\:\mathrm{is}\:\mathrm{030}°.\:\mathrm{A} \\ $$$$\mathrm{wind}\:\mathrm{of}\:\mathrm{80Km}/\mathrm{hr}\:\mathrm{is}\:\mathrm{blowing}\:\mathrm{from}\:\mathrm{the}\:\mathrm{east}.\:\mathrm{Given}\:\mathrm{that}\:\mathrm{the} \\ $$$$\mathrm{plane}\:\mathrm{can}\:\mathrm{travel}\:\mathrm{at}\:\mathrm{320Km}/\mathrm{hr}\:\mathrm{in}\:\mathrm{still}\:\mathrm{air}.\:\mathrm{Find}\: \\ $$$$\left(\mathrm{i}\right)\:\mathrm{The}\:\mathrm{bearing}\:\mathrm{on}\:\mathrm{which}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{must}\:\mathrm{be}\:\mathrm{steered}. \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{The}\:\mathrm{time}\:\mathrm{taken}\:\mathrm{to}\:\mathrm{fly}\:\mathrm{from}\:\mathrm{A}\:\mathrm{to}\:\mathrm{B}. \\ $$ Terms of Service…