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Question-104207

Question Number 104207 by PengagumRahasiamu last updated on 20/Jul/20 Answered by bemath last updated on 20/Jul/20 $${x}^{\mathrm{2}} −{x}+\mathrm{1}\:=\:\mathrm{0} \\ $$$${x}=\:\frac{\mathrm{1}\:\pm\:{i}\sqrt{\mathrm{3}}}{\mathrm{2}}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\pm\:\frac{{i}\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$${have}\:{no}\:{real}\:{roots}.\:{Sum}\:{of} \\ $$$${real}\:{root}\:{is}\:{nothing} \\…

solve-for-real-values-of-x-the-equation-4-3-2x-1-17-3-x-7-if-m-and-n-are-positive-real-numbers-other-than-1-show-that-the-log-n-m-log-1-m-n-0-

Question Number 104199 by hardylanes last updated on 20/Jul/20 $${solve}\:{for}\:{real}\:{values}\:{of}\:{x}\:{the}\:{equation} \\ $$$$\mathrm{4}\left(\mathrm{3}^{\mathrm{2}{x}+\mathrm{1}} \right)+\mathrm{17}\left(\mathrm{3}^{{x}} \right)=\mathrm{7}. \\ $$$${if}\:{m}\:{and}\:{n}\:{are}\:{positive}\:{real}\:{numbers}\:{other} \\ $$$${than}\:\mathrm{1},\:{show}\:{that}\:{the}\:\mathrm{log}_{{n}} {m}+\mathrm{log}_{\frac{\mathrm{1}}{{m}}} {n}=\mathrm{0} \\ $$ Answered by bemath…

n-1-n-n-1-2-2-n-1-1-

Question Number 104176 by Dwaipayan Shikari last updated on 19/Jul/20 $$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(\left(\frac{\mathrm{n}}{\mathrm{n}+\mathrm{1}}\right)^{\mathrm{2}} −\frac{\mathrm{2}}{\mathrm{n}+\mathrm{1}}−\mathrm{1}\right) \\ $$ Answered by OlafThorendsen last updated on 19/Jul/20 $${u}_{{n}} \:=\:\left(\frac{\mathrm{n}}{\mathrm{n}+\mathrm{1}}\right)^{\mathrm{2}}…

n-1-n-n-1-2-

Question Number 104174 by Dwaipayan Shikari last updated on 19/Jul/20 $$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\prod}}\left(\frac{\mathrm{n}}{\mathrm{n}+\mathrm{1}}\right)^{\mathrm{2}} \\ $$ Answered by OlafThorendsen last updated on 19/Jul/20 $$\mathrm{S}_{{n}} \:=\:\underset{{k}=\mathrm{1}} {\overset{{n}}…

For-fun-S-n-1-2-3-4-5-6-7-2S-n-2-4-6-S-n-1-3-5-7-9-11-1-12-1-3-5-7-9-11-1-3-5-7-9-1-12-S-n-1-2-3-4-5-6-7-S-n-1-1-1-1-2-1-3-

Question Number 104173 by Dwaipayan Shikari last updated on 19/Jul/20 $$\:\mathrm{For}\:\mathrm{fun}! \\ $$$$\mathrm{S}_{\mathrm{n}} =\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}+\mathrm{5}+\mathrm{6}+\mathrm{7}+… \\ $$$$\mathrm{2S}_{\mathrm{n}} =\:\:\:\:\mathrm{2}\:\:+\:\:\:\mathrm{4}\:\:\:\:\:\:+\:\:\mathrm{6}\:\:\:\:\:\:+.. \\ $$$$−\mathrm{S}_{\mathrm{n}} =\mathrm{1}+\mathrm{3}+\mathrm{5}+\mathrm{7}+\mathrm{9}+\mathrm{11}+….. \\ $$$$−\left(−\frac{\mathrm{1}}{\mathrm{12}}\right)=\mathrm{1}+\mathrm{3}+\mathrm{5}+\mathrm{7}+\mathrm{9}+\mathrm{11}+… \\ $$$$\mathrm{1}+\mathrm{3}+\mathrm{5}+\mathrm{7}+\mathrm{9}+….=\frac{\mathrm{1}}{\mathrm{12}} \\…

Question-169658

Question Number 169658 by Tawa11 last updated on 05/May/22 Commented by mr W last updated on 05/May/22 $${frictional}\:{force}={active}\:{force}\:{applied} \\ $$$${on}\:{carton} \\ $$$$\Rightarrow{frictional}\:{force}\:=\mathrm{150}\:{N} \\ $$$${Answer}\:{A}\:{is}\:{correct}. \\…