Question Number 38419 by Rio Mike last updated on 25/Jun/18 Answered by tanmay.chaudhury50@gmail.com last updated on 25/Jun/18 $${m}_{{B}} {g}−{T}−{friction}={m}_{{B}} {a} \\ $$$${T}−\mu{m}_{{A}} {g}={m}_{{A}} {a} \\…
Question Number 38391 by gunawan last updated on 25/Jun/18 $${a}+\mathrm{2}{b}+\mathrm{3}{c}=\mathrm{12} \\ $$$$\mathrm{2}{ab}+\mathrm{3}{ac}+\mathrm{6}{bc}=\mathrm{48} \\ $$$${a}+{b}+{c}=… \\ $$ Answered by MrW3 last updated on 26/Jun/18 $${let} \\…
Question Number 169447 by Mastermind last updated on 30/Apr/22 $${The}\:{equation}\:{of}\:{the}\:{curve}\:{is}\:{given} \\ $$$${y}=\frac{{x}^{\mathrm{3}} }{\mathrm{6}}−\frac{\mathrm{5}{x}^{\mathrm{2}} }{\mathrm{2}}−\mathrm{6}{x}−\mathrm{1} \\ $$$$\left.\mathrm{1}\right)\:{Determine}\:{the}\:{critical}\:{points} \\ $$$$\left.\mathrm{2}\right)\:{Distinguish}\:{between}\:{these}\:{points} \\ $$$$\left.\mathrm{3}\right)\:{Determine}\:{the}\:{Maximum}\:{and} \\ $$$${minimum}\:{values} \\ $$$$\left.\mathrm{4}\right)\:{Determine}\:{the}\:{value}\:{of}\:{x}\:{and}\:{y} \\…
Question Number 38373 by tanmay.chaudhury50@gmail.com last updated on 24/Jun/18 Commented by tanmay.chaudhury50@gmail.com last updated on 25/Jun/18 $${I}\left({a}\right)=\int_{\mathrm{0}} ^{\infty} \frac{{tan}^{−\mathrm{1}} \left({ax}\right)}{{x}\left(\mathrm{1}+{x}^{\mathrm{2}} \right)}{dx} \\ $$$$\frac{{dI}\left({a}\right)}{{da}}=\int_{\mathrm{0}} ^{\infty} \frac{\partial}{\partial{a}}\frac{{tan}^{−\mathrm{1}}…
Question Number 38366 by Rio Mike last updated on 24/Jun/18 $${At}\:{time}\:{t},{the}\:{force}\:{acting}\:{on}\:{a}\:{particle} \\ $$$${P}\:{of}\:{mass}\:\mathrm{2}{kg}\:{is}\:\left(\mathrm{2}\boldsymbol{{ti}}\:+\:\mathrm{4}\boldsymbol{{j}}\right){N}.{P} \\ $$$${is}\:{initially}\:{at}\:{rest}\:{at}\:{the}\:{point}\:{with} \\ $$$${position}\:{vector}\:\left(\boldsymbol{{i}}\:+\:\mathrm{2}\boldsymbol{{j}}\right). \\ $$$${Find}: \\ $$$$\left.{a}\right)\:{the}\:{velocity}\:{of}\:{P}\:{when}\:{t}\:=\:\mathrm{2}. \\ $$$$\left.{b}\right)\:{the}\:{position}\:{vector}\:{when}\:{t}\:=\:\mathrm{2}. \\ $$…
Question Number 38365 by Rio Mike last updated on 24/Jun/18 $${A}\:{particle}\:{P}\:{moves}\:{on}\:{a}\:{straightline} \\ $$$${from}\:{a}\:{fixed}\:{point}\:{O}\:{and}\:{the}\:{distance} \\ $$$${x}\:{from}\:{O}\:{after}\:{t}\:{seconds}\:{is}\:{given}\:{as} \\ $$$$\:{x}\:=\:\frac{\mathrm{1}}{\mathrm{4}\:}\:{t}^{\mathrm{4}} \:−\:\frac{\mathrm{3}}{\mathrm{2}}\:{t}^{\mathrm{2}} \:+\:\mathrm{2}{t}. \\ $$$${Find}: \\ $$$$\left.{a}\right)\:{the}\:{velocity}\:{of}\:{P}\:{when}\:{t}\:=\:\mathrm{2}, \\ $$$$\left.{b}\right)\:{the}\:{acceleration}\:{of}\:{P}\:{when}\:{t}\:=\:\mathrm{2},…
Question Number 38362 by tanmay.chaudhury50@gmail.com last updated on 24/Jun/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 169396 by Mastermind last updated on 29/Apr/22 $$\sqrt{{x}}+\mathrm{1}=\mathrm{0} \\ $$$${find}\:{x} \\ $$$$ \\ $$$${Mastermind} \\ $$ Commented by mr W last updated on…
Question Number 103859 by 175mohamed last updated on 17/Jul/20 $$\:\:\: \\ $$$$\:\:\:\:\:\:{solve}\:: \\ $$$$\:\:\:\:\:\:{y}^{\mathrm{2}} \:+\:{x}^{\mathrm{2}} \:=\:−\mathrm{sin}\left(\theta\right)\:\:\:\:\:.,\:\:\:\:\frac{\pi}{\mathrm{2}}\geqslant\:\theta\geqslant−\frac{\pi}{\mathrm{2}} \\ $$ Answered by mathmax by abdo last updated…
Question Number 169364 by Mastermind last updated on 29/Apr/22 $${Show}\:{that}\:{the}\:{differential}\:{equation} \\ $$$${y}''\:−\mathrm{4}{y}'+\mathrm{4}{y}=\mathrm{0}\:{is}\:{satisfied}\:{when} \\ $$$${y}={xe}^{\mathrm{2}{x}} \\ $$$$ \\ $$$${Mastermind} \\ $$ Answered by Mathspace last updated…