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It-is-given-that-the-first-term-of-a-GP-is-the-last-term-of-an-AP-the-second-term-of-the-AP-is-the-third-term-of-the-GP-detemine-the-Geometric-mean-of-the-GP-is-the-fourth-term-of-the-GP-is-16-

Question Number 38250 by Rio Mike last updated on 23/Jun/18 $$\:\:{It}\:{is}\:{given}\:{that}\:{the}\:{first}\:{term}\:{of} \\ $$$${a}\:{GP}\:\:{is}\:{the}\:{last}\:{term}\:{of}\:{an}\:{AP}. \\ $$$${the}\:{second}\:{term}\:{of}\:{the}\:{AP}\:{is}\:{the} \\ $$$${third}\:{term}\:{of}\:{the}\:{GP}..{detemine} \\ $$$${the}\:{Geometric}\:{mean}\:{of}\:{the}\:{GP}\:{is}\: \\ $$$$\:{the}\:{fourth}\:{term}\:{of}\:{the}\:{GP}\:{is}\:\mathrm{16}. \\ $$ Terms of…

if-x-2-3xy-y-2-3-find-dy-dx-at-point-1-1-hence-differentiate-sin-x-1-x-with-respect-to-x-

Question Number 38252 by Rio Mike last updated on 23/Jun/18 $${if}\:{x}^{\mathrm{2}} \:+\:\mathrm{3}{xy}\:−\:{y}^{\mathrm{2}} \:=\:\mathrm{3}\:{find}\: \\ $$$$\frac{{dy}}{{dx}}\:{at}\:{point}\:\left(\mathrm{1},\mathrm{1}\right)\:{hence} \\ $$$${differentiate}\:\frac{{sin}\:{x}}{\mathrm{1}\:+\:{x}}\:{with}\:{respect} \\ $$$${to}\:{x}. \\ $$ Commented by math khazana…

Question-169200

Question Number 169200 by Mastermind last updated on 25/Apr/22 Answered by Rasheed.Sindhi last updated on 26/Apr/22 $${x}^{\mathrm{4}} +\frac{\mathrm{1}}{{x}^{\mathrm{4}} }={a}\:;\:{a}=\mathrm{62} \\ $$$$\left({x}^{\mathrm{4}} +\frac{\mathrm{1}}{{x}^{\mathrm{4}} }\right)^{\mathrm{3}} ={a}^{\mathrm{3}} \\…

prove-that-a-3-1-x-2-dx-1-3-2x-1-dx-b-2-0-xdx-0-2-x-2-x-dx-c-1-4-x-2-2-dx-2-5-2x-5-dx-d-pi-3pi-4-cos-2x-dx-3pi-4-pi-sin-2x-dx-

Question Number 103669 by 175mohamed last updated on 16/Jul/20 $${prove}\:{that}\:: \\ $$$$\left.{a}\right)\:\int_{−\mathrm{3}} ^{−\mathrm{1}} {x}^{\mathrm{2}} {dx}\:\geqslant\int_{\mathrm{1}} ^{\mathrm{3}} \left(\mathrm{2}{x}−\mathrm{1}\right){dx} \\ $$$$\left.{b}\right)\int_{−\mathrm{2}} ^{\mathrm{0}} {xdx}\:\leqslant\int_{\mathrm{0}} ^{\mathrm{2}} \left({x}^{\mathrm{2}} \:+\:{x}\:\right){dx} \\…