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Question Number 37249 by Rio Mike last updated on 11/Jun/18 $${a}\:{triangle}\:{with}\:{vertices}\: \\ $$$$\:{A}\left(\mathrm{2},\mathrm{1}\right),{B}\left(\mathrm{6},\mathrm{1}\right)\:{and}\:\left(\mathrm{3},\mathrm{3}\right)\:{is}\:{transformed} \\ $$$${by}\:\begin{pmatrix}{\mathrm{2}\:\:\:\:\:\:\:\:\:\mathrm{0}}\\{\mathrm{0}\:\:\:\:\:\:\:\:\:\:\mathrm{2}}\end{pmatrix}\: \\ $$$$\left.{a}\right){find}\:{the}\:{image}\:{A}'{B}'{C}'\:{after}\: \\ $$$${this}\:{transformstion} \\ $$$$\left.{b}\right)\:{state}\:{the}\:{type}\:{of}\:{transformation} \\ $$ Terms of…

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Question Number 37218 by Rio Mike last updated on 10/Jun/18 $$\:{Proove}\:{that} \\ $$$$\left.{a}\right)\:\:\frac{\mathrm{1}−{cosA}\:+\:{cos}\:{B}\:−\:{cos}\left({A}+{B}\right)}{\mathrm{1}+{cos}\:{A}\:−\:{cosB}−{cos}\left({A}+{B}\right)}=\:{tan}\frac{{A}}{\mathrm{2}}.{cot}\:\frac{{B}}{\mathrm{2}} \\ $$$$\left.{b}\right)\:{cos}\alpha\:{cos}\left(\mathrm{60}−\alpha\right){cos}\left(\mathrm{60}+\alpha\right)=\:\frac{\mathrm{1}}{\mathrm{4}}{cos}\mathrm{3}\alpha \\ $$$$ \\ $$ Answered by $@ty@m last updated on…

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Question Number 102745 by Dwaipayan Shikari last updated on 10/Jul/20 $$\mathrm{1}−\mathrm{1}+\mathrm{1}−\mathrm{1}+\mathrm{1}−\mathrm{1}+\mathrm{1}−\mathrm{1}+…..=\frac{\mathrm{1}}{\mathrm{2}}\:\:\:\left\{{But}\:{it}\:{diverges}\right. \\ $$$$\mathrm{1}+\mathrm{1}+\mathrm{1}+\mathrm{1}+\mathrm{1}+\mathrm{1}+\mathrm{1}+……=−\frac{\mathrm{1}}{\mathrm{2}}\:\:\:\:\:\:\left\{{But}\:{it}\:{diverges}\right. \\ $$$$\mathrm{1}+\mathrm{2}+\mathrm{4}+\mathrm{8}+\mathrm{16}+…..=−\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left\{{But}\:{it}\:{diverges}\right. \\ $$$$\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}+\mathrm{5}+\mathrm{6}+\mathrm{7}=−\frac{\mathrm{1}}{\mathrm{12}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left\{{But}\:{it}\:{diverges}\right. \\ $$$$\mathrm{1}−\mathrm{2}+\mathrm{4}−\mathrm{8}+…..=\frac{\mathrm{1}}{\mathrm{3}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left\{{But}\:{it}\:{diverges}\right. \\ $$$$\mathrm{1}−\mathrm{2}+\mathrm{3}−\mathrm{4}+\mathrm{5}−\mathrm{6}+…..=\frac{\mathrm{1}}{\mathrm{4}}\:\:\:\:\:\:\:\left\{{Is}\:{it}\:{a}\:{divergent}?????\right. \\ $$ Commented by…

Question-168264

Question Number 168264 by Mastermind last updated on 07/Apr/22 Answered by som(math1967) last updated on 07/Apr/22 $${let}\:{speed}\:={xkm}/{hr} \\ $$$$\therefore\frac{\mathrm{240}}{{x}−\mathrm{4}}\:−\frac{\mathrm{240}}{{x}}=\mathrm{2} \\ $$$$\Rightarrow\mathrm{240}\left\{\frac{{x}−{x}+\mathrm{4}}{{x}\left({x}−\mathrm{4}\right)}\right\}=\mathrm{2} \\ $$$$\Rightarrow\frac{\mathrm{240}×\mathrm{4}}{{x}^{\mathrm{2}} −\mathrm{4}{x}}=\mathrm{2} \\…

Question-168274

Question Number 168274 by Mastermind last updated on 07/Apr/22 Answered by MikeH last updated on 07/Apr/22 $$\mathrm{width}\:=\:{x} \\ $$$$\mathrm{length}\:={x}\:+\:\mathrm{11} \\ $$$$\mathrm{area}\:=\:{x}\left({x}+\mathrm{11}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:=\:{x}^{\mathrm{2}} +\mathrm{11}{x} \\…