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Question-168274

Question Number 168274 by Mastermind last updated on 07/Apr/22 Answered by MikeH last updated on 07/Apr/22 $$\mathrm{width}\:=\:{x} \\ $$$$\mathrm{length}\:={x}\:+\:\mathrm{11} \\ $$$$\mathrm{area}\:=\:{x}\left({x}+\mathrm{11}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:=\:{x}^{\mathrm{2}} +\mathrm{11}{x} \\…