Question Number 36867 by tanmay.chaudhury50@gmail.com last updated on 06/Jun/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 36862 by tanmay.chaudhury50@gmail.com last updated on 06/Jun/18 Commented by Joel579 last updated on 06/Jun/18 $$\mathrm{blackpenredpen} \\ $$$$\mathrm{Dr}.\:\mathrm{Peyam}'\mathrm{s}\:\mathrm{show} \\ $$$$\mathrm{LetsSolveMathProblem} \\ $$ Terms of…
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Question Number 167928 by Mastermind last updated on 29/Mar/22 $${Show}\:{that}\:\mid\mathrm{1}−{i}\mid^{{x}} =\mathrm{2}^{{x}} \:{has}\:{no}\:{nonzero}\:{integral}\:{solution}\: \\ $$ Answered by MJS_new last updated on 30/Mar/22 $$\mid\mathrm{1}−\mathrm{i}\mid=\sqrt{\mathrm{2}};\:\mid\mathrm{1}−\mathrm{i}\mid^{{x}} =\left(\sqrt{\mathrm{2}}\right)^{{x}} =\mathrm{2}^{\frac{{x}}{\mathrm{2}}} \\…
Question Number 36853 by tawa tawa last updated on 06/Jun/18 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{laplace}\:\mathrm{of}\:\:\:\:\:\mathrm{L}\left\{\frac{\mathrm{e}^{−\mathrm{at}} \:−\:\mathrm{e}^{−\mathrm{bt}} }{\mathrm{t}}\right\} \\ $$ Commented by prof Abdo imad last updated on 06/Jun/18 $${L}\left\{\:\frac{{e}^{−{ax}}…
Question Number 36837 by Rio Mike last updated on 06/Jun/18 $$\underset{{r}=\mathrm{0}} {\overset{\infty} {\sum}}\mathrm{2}^{\mathrm{4}{r}−\mathrm{2}} \: \\ $$ Commented by prof Abdo imad last updated on 06/Jun/18…
Question Number 102362 by 4635 last updated on 08/Jul/20 $${please}\:{how}\:{calculate}\:{the}\:{development}\:\:{limity}\:{of}\:{f}\left({x},{y}\right)={x}^{{y}} \\ $$$$\:,{take}\:{a}\left(\:\mathrm{3},\mathrm{2}\right)\:{at}\:{order}\:{one}\:{and}\:{two} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 36814 by MJS last updated on 06/Jun/18 $$\mathrm{now}\:\mathrm{the}\:\mathrm{way}\:\mathrm{is}\:\mathrm{clear},\:\mathrm{also}\:\mathrm{try}\:\mathrm{this}\:\mathrm{one}: \\ $$$$\int\frac{\mathrm{cos}\:{x}}{\mathrm{sin}^{\mathrm{2}} \:{x}\:\sqrt{\mathrm{sin}\:\mathrm{2}{x}}}{dx} \\ $$ Answered by math1967 last updated on 06/Jun/18 $$\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\int\frac{{cosx}}{{sin}^{\mathrm{2}} {x}\sqrt{\mathrm{sin}\:{x}\mathrm{cos}\:{x}}}{dx} \\…
Question Number 167882 by LEKOUMA last updated on 28/Mar/22 $${Calculate} \\ $$$${I}=\int\frac{\mathrm{1}}{{x}}\left(\sqrt{\frac{\mathrm{1}−{x}}{\mathrm{1}+{x}}}\right){dx} \\ $$$${Indication}\:{poser}\:{t}=\sqrt{\frac{\mathrm{1}−{x}}{\mathrm{1}+{x}}} \\ $$ Answered by ArielVyny last updated on 29/Mar/22 $${t}=\sqrt{\frac{\mathrm{1}−{x}}{\mathrm{1}+{x}}}\rightarrow{dt}=\frac{−\frac{\mathrm{2}}{\left(\mathrm{1}+{x}\right)^{\mathrm{2}} }}{\mathrm{2}{t}}{dx}=−\frac{\mathrm{1}}{\left(\mathrm{1}+{x}\right)^{\mathrm{2}}…