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An-object-is-said-to-cross-a-thousand-kilimeters-in-planks-constant-How-many-times-faster-is-the-object-to-the-speed-of-light-plank-s-time-10-44-sec-

Question Number 195948 by Mastermind last updated on 13/Aug/23 $$\mathrm{An}\:\mathrm{object}\:\mathrm{is}\:\mathrm{said}\:\mathrm{to}\:\mathrm{cross}\:\mathrm{a}\:\mathrm{thousand}\: \\ $$$$\mathrm{kilimeters}\:\mathrm{in}\:\mathrm{planks}\:\mathrm{constant}.\:\mathrm{How}\:\mathrm{many} \\ $$$$\mathrm{times}\:\mathrm{faster}\:\mathrm{is}\:\mathrm{the}\:\mathrm{object}\:\mathrm{to}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of} \\ $$$$\mathrm{light}.\:\mathrm{plank}'\mathrm{s}\:\mathrm{time}\:=\:\mathrm{10}^{−\mathrm{44}} \mathrm{sec}. \\ $$ Terms of Service Privacy Policy Contact:…

Please-how-did-z-a-r-became-z-a-re-i-

Question Number 195848 by pete last updated on 11/Aug/23 $$\mathrm{Please}\:\mathrm{how}\:\mathrm{did}\:\mid\mathrm{z}−\mathrm{a}\mid=\mathrm{r}\:\mathrm{became}\: \\ $$$$\mathrm{z}=\:\mathrm{a}\:+\:\mathrm{re}^{\mathrm{i}\theta} ? \\ $$ Answered by Frix last updated on 11/Aug/23 $$\mid{z}−{a}\mid={r}\:\Rightarrow\:{z}−{a}={r}\mathrm{e}^{\mathrm{i}\theta} \\ $$$$\mathrm{This}\:\mathrm{step}\:\mathrm{is}\:\mathrm{always}\:\mathrm{true},\:\mathrm{even}\:\mathrm{for}\:{z}−{a}\in\mathbb{R}…

Question-195747

Question Number 195747 by Mastermind last updated on 09/Aug/23 Commented by AST last updated on 09/Aug/23 $${The}\:{total}\:{amount}\:{spent}\:{does}\:{not}\:{have}\:{to}\:{be} \\ $$$${necessarily}\:{equal}\:{to}\:{the}\:{sum}\:{of}\:{the}\:{remaining} \\ $$$${amount}\:{at}\:{each}\:{step}\:{of}\:{your}\:{spending}.\:{In}\:{fact}, \\ $$$${we}\:{can}\:{make}\:{that}\:{N}\mathrm{51}\:{grow}\:{arbitrarily}\:{large} \\ $$$${by}\:{spending}\:\epsilon\left({such}\:{as}\:\mathrm{0}.\mathrm{000000001}\right)\:{at}\:{every}\:{step}.…

Question-195612

Question Number 195612 by Mastermind last updated on 05/Aug/23 Answered by a.lgnaoui last updated on 05/Aug/23 $$\mathrm{r}−\mathrm{73}=\pm\mathrm{16} \\ $$$$\begin{cases}{\mathrm{r}−\mathrm{73}=\mathrm{16}\:\:\:\:\:\:\:\:\Rightarrow\:\:\boldsymbol{\mathrm{r}}=\mathrm{89}}\\{\boldsymbol{\mathrm{r}}−\mathrm{73}=−\mathrm{16}\:\:\:\Rightarrow\:\:\boldsymbol{\mathrm{r}}=\mathrm{57}}\end{cases} \\ $$$$\:\:\:\:\boldsymbol{\mathrm{r}}=\left\{\mathrm{57},\mathrm{89}\right\} \\ $$ Terms of…

Question-195412

Question Number 195412 by Calculusboy last updated on 02/Aug/23 Answered by AST last updated on 02/Aug/23 $${v}_{\mathrm{2}} \left({a}^{\mathrm{2}^{{n}} } −\mathrm{1}\right)={v}_{\mathrm{2}} \left({a}−\mathrm{1}\right)+{n}+{v}_{\mathrm{2}} \left({a}+\mathrm{1}\right)−\mathrm{1}\geqslant{n}+\mathrm{2} \\ $$$$\Rightarrow\mathrm{2}^{{n}+\mathrm{2}} \mid{a}^{\mathrm{2}^{{n}}…