Question Number 34142 by Rio Mike last updated on 01/May/18 $${what}\:{is}\:{the}\:{derivative}\:{of}\: \\ $$$$\:\:\:\:\:\left(\boldsymbol{{x}}+\mathrm{3}\right)\left(\boldsymbol{{x}}^{\mathrm{2}} +\:\mathrm{5}\right) \\ $$$${and}\:{find}\:{the}\:{n}\:{sequence}\:{of}\: \\ $$$$\:\:\:\underset{{r}={n}+\mathrm{1}\:} {\overset{\mathrm{2}{n}} {\sum}}\:\:\left(\mathrm{4}{r}^{\mathrm{3}} −\mathrm{3}\right) \\ $$ Commented by…
Question Number 99670 by 175 last updated on 22/Jun/20 Commented by maths mind last updated on 22/Jun/20 $${wrong}\:{notation} \\ $$ Commented by 20092104 last updated…
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Question Number 34119 by Rio Mike last updated on 30/Apr/18 $${if}\:{u}\:{and}\:{v}\:{are}\:{real}\:{valued}\:{functions} \\ $$$${of}\:{x},\:{then}\:\:\frac{{d}}{{dx}}\left(\frac{{u}}{{v}}\right)= \\ $$$${A}.\:\frac{{v}\frac{{du}}{{dx}}−\:{u}\frac{{dv}}{{dx}}}{{u}^{\mathrm{2}} }\:\:\:\:\:\:\:\:{B}.\:\:\frac{{v}\frac{{du}}{{dx}}−\:{u}\frac{{dv}}{{dx}}}{{u}^{\mathrm{2}} } \\ $$$${C}.\:\frac{{v}\frac{{du}}{{dx}}−{u}\:\frac{{dv}}{{dx}}}{{v}^{\mathrm{2}} }\:\:\:\:\:\:\:\:\:\:{D}.\:\frac{{u}\frac{{dv}}{{dx}}\:−\:{v}\frac{{du}}{{dx}}}{{v}^{\mathrm{2}} } \\ $$ Answered by…
Question Number 34098 by Rasheed.Sindhi last updated on 01/May/18 $$\mathrm{Since}\:\mathrm{the}\:\mathrm{beginning}\: \\ $$$$\mathrm{several}\:\mathrm{persons}\:\mathrm{with}\:\mathrm{their}\:\mathrm{experties} \\ $$$$\mathrm{had}\:\mathrm{left}\:\mathrm{the}\:\mathrm{forum}… \\ $$$$\mathrm{Newcommers}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{them},\mathrm{but} \\ $$$$\mathrm{they}\:\mathrm{can}\:\mathrm{explore}\:\mathrm{the}\:\mathrm{past}\:\mathrm{of}\:\mathrm{the}\:\mathrm{forum} \\ $$$$\mathrm{and}\:\mathrm{recognise}\:\mathrm{their}\:\mathrm{precious}\:\mathrm{work}! \\ $$$$\mathrm{Think}\:\mathrm{the}\:\mathrm{forum}\:\mathrm{as}\:\mathrm{cricket}. \\ $$$$\mathrm{Some}\:\mathrm{were}\:'\mathrm{bowlers}'\:\mathrm{and}\:\mathrm{others}\:\mathrm{were} \\…
Question Number 99623 by hardylanes last updated on 22/Jun/20 $${obtain}\:{the}\:{modulus}\:{and}\:{arguement}\:{of} \\ $$$$\frac{\left(\mathrm{1}−{i}\right)^{\mathrm{4}} }{\left(\mathrm{2}+\mathrm{2}\sqrt{\left.\mathrm{3}{i}\right)^{\mathrm{3}} }\right.} \\ $$ Commented by Dwaipayan Shikari last updated on 22/Jun/20 $$=\frac{\left(\mathrm{1}−{i}\right)^{\mathrm{2}.\mathrm{2}}…
Question Number 99568 by Dwaipayan Shikari last updated on 22/Jun/20 $${Find}\:{the}\:{value}\:{of}\:\:\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+}}}}}}…\infty\:\:\:\:\:{by}\:{cos}\:{function} \\ $$ Commented by bemath last updated on 22/Jun/20 $${x}\:=\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{…}}}}} \\ $$$${x}^{\mathrm{2}} \:=\:\mathrm{2}+{x}\: \\…
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Question Number 99485 by Dwaipayan Shikari last updated on 21/Jun/20 $$\int{tan}^{\frac{\mathrm{1}}{\mathrm{5}}} {xdx} \\ $$ Answered by MJS last updated on 21/Jun/20 $${t}=\mathrm{tan}^{\mathrm{2}/\mathrm{5}} \:{x} \\ $$$$\int\mathrm{tan}^{\mathrm{1}/\mathrm{5}}…
Question Number 33907 by RoachDN last updated on 27/Apr/18 Commented by RoachDN last updated on 27/Apr/18 $$\mathrm{no}.\:\mathrm{3} \\ $$ Terms of Service Privacy Policy Contact:…