Question Number 36217 by Rio Mike last updated on 30/May/18 $$\mathrm{Suppose}\:{a}_{\mathrm{1}} ,…,{a}_{{n}} ,\mathrm{are}\:\mathrm{non}−\mathrm{negative} \\ $$$$\mathrm{reals}\:\mathrm{such}\:\mathrm{that}\:{S}=\:{a}_{\mathrm{1}} +…+{a}_{{n}} < \\ $$$${proof}\:{that}\: \\ $$$$\mathrm{1}\:+\:\mathrm{S}\leqslant\:\left(\mathrm{1}\:+\:{a}_{\mathrm{1}} \right)._{…} .\left(\mathrm{1}+\:{a}_{{n}} \right)\:\leqslant\:\frac{\mathrm{1}}{\mathrm{1}−\mathrm{s}} \\…
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Question Number 36191 by prof Abdo imad last updated on 30/May/18 $${let}\:{D}\:=\:\left\{\left({x},{y}\right)\in{R}^{\mathrm{2}} \:/{x}>\mathrm{0}\:,{y}>\mathrm{0},{x}+{y}<\mathrm{1}\right\} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:\int\int_{{D}} \:\:\frac{{xy}}{{x}^{\mathrm{2}} \:+{y}^{\mathrm{2}} }{dxdy} \\ $$$$\left.\mathrm{2}\right)\:{let}\:{a}>\mathrm{0}\:,{b}>\mathrm{0}\:{calculate}\:\int\int_{{D}} \:{a}^{{x}} {b}^{{y}} {dxdy} \\ $$…
Question Number 36168 by abdo mathsup 649 cc last updated on 29/May/18 $${let}\:{A}\left({t}\right)\:=\:\int_{−\infty} ^{+\infty} \:\:\:\:\frac{{sin}\left({xt}\right)}{\left(\:{x}\:+\mathrm{1}+{i}\right)^{\mathrm{2}} }\:{dx}\:\:{with}\:{t}\:{from}\:{R} \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:{A}\left({t}\right) \\ $$$$\left.\mathrm{2}\right)\:{extract}\:{Re}\left({A}\left({t}\right)\right)\:{and}\:{Im}\left({A}\left({t}\right)\right) \\ $$$$\left.\mathrm{3}\right)\:{find}\:{the}\:{value}\:{of}\:\:\int_{−\infty} ^{+\infty} \:\:\:\:\:\frac{{cos}\left(\mathrm{3}{x}\right)}{\left({x}+\mathrm{1}+{i}\right)^{\mathrm{2}} }{dx}…
Question Number 36166 by Rio Mike last updated on 29/May/18 $$\:\mathrm{Find}\:\mathrm{the}\:\mathrm{middle}\:\mathrm{term}\:\mathrm{in}\: \\ $$$$\mathrm{the}\:\mathrm{expansion}\:\mathrm{of}\:\:\left(\mathrm{x}^{} \:+\:\frac{\mathrm{3}}{\mathrm{x}}\right)^{\mathrm{9}} \\ $$ Commented by abdo.msup.com last updated on 30/May/18 $${we}\:{have}\:\left({x}+\frac{\mathrm{3}}{{x}}\right)^{\mathrm{9}} \:=\:\sum_{{k}=\mathrm{0}}…
Question Number 36148 by Riazahmedzaib11 last updated on 29/May/18 $$ \\ $$$$\:\:\left[\overset{\mathrm{x}} {\mathrm{2}}\overset{+\:\:\mathrm{3}} {−}\mathrm{1}\:\:\:\:\overset{\mathrm{2y}+\mathrm{x}} {\mathrm{4}x6}\right]=\left[\overset{\mathrm{0}−\mathrm{7}} {\mathrm{3}}\:\mathrm{2x}\right] \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 167200 by Tawa11 last updated on 09/Mar/22 Answered by mr W last updated on 09/Mar/22 $${x}={u}\:\mathrm{cos}\:\theta\:{t} \\ $$$${y}=\mathrm{6}+{u}\:\mathrm{sin}\:\theta\:{t}−\frac{{gt}^{\mathrm{2}} }{\mathrm{2}} \\ $$$${g}=\mathrm{10}\:{m}/{s}^{\mathrm{2}} \\ $$$$\left({a}\right)…
Question Number 36092 by Rio Mike last updated on 28/May/18 $$\:\mathrm{solve}\:\mathrm{for}\:\mathrm{0}°\leqslant\:\theta\:\leqslant\:\mathrm{360}°\:\mathrm{the}\:\mathrm{equation} \\ $$$$\:\mathrm{cos}\left(\theta\:+\:\frac{\pi}{\mathrm{3}}\right)=\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Commented by abdo mathsup 649 cc last updated on 30/May/18…
Question Number 36091 by Rio Mike last updated on 28/May/18 $$\mathrm{Given}\:\mathrm{the}\:\mathrm{position}\:\mathrm{vectors} \\ $$$${v}_{\mathrm{1}} =\:\mathrm{2}{i}\:−\:\mathrm{2}{j}\:{and}\:{v}_{\mathrm{2}} =\:\mathrm{2}{j}, \\ $$$$\mathrm{show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{unit}\:\mathrm{vector}\:\mathrm{in}\: \\ $$$$\mathrm{the}\:\mathrm{direction}\:\mathrm{of}\:\mathrm{the}\:\mathrm{vector}\: \\ $$$${v}_{\mathrm{1}} −\:{v}_{\mathrm{2}\:\:\:} \mathrm{is}\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}\left(\mathrm{i}−\mathrm{2j}\right) \\ $$…
Question Number 36080 by Rio Mike last updated on 28/May/18 $$\:\mathrm{i}\:\mathrm{want}\:\mathrm{to}\:\mathrm{know}\:\mathrm{how}\: \\ $$$$\alpha^{\mathrm{2}} +\:\beta^{\mathrm{2}} =\:\left(\alpha+\beta\right)^{\mathrm{2}} −\:\mathrm{2}\alpha\beta\:\mathrm{why}\:\mathrm{not}\: \\ $$$$\alpha^{\mathrm{2}} +\beta^{\mathrm{2}} =\:\left(\alpha+\beta\right)^{\mathrm{2}} +\:\mathrm{2}\alpha\beta? \\ $$ Commented by…