Question Number 31671 by gunawan last updated on 12/Mar/18 $$\mathrm{let}\:{f}\:\mathrm{diferensiabel}\:\mathrm{on}\:\mathrm{continues} \\ $$$${x}={a}\:\mathrm{and}\:{f}\left({a}\right)\neq\:\mathrm{0} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\left[\frac{{f}\left({a}+\frac{\mathrm{1}}{{n}}\right)}{{f}\left({a}\right)}\right]^{{n}} \\ $$$$\mathrm{value}\:\mathrm{is}\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 162726 by LEKOUMA last updated on 31/Dec/21 $$\left.\mathrm{1}\right)\:{Calculate} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{tgx}^{{m}} }{\left(\mathrm{sin}\:{x}\right)^{{n}} },\:\:\left({m},\:{n}\in\: {N}\right) \\ $$$$\left.\mathrm{2}\right)\:{f}'\left({a}\right)\:{e}\mathrm{xiste},\:{calculate} \\ $$$$\underset{{x}\rightarrow+\infty} {\mathrm{lim}}{x}\left[{f}\left({a}+\frac{{a}}{{x}}\right)−{f}\left({a}−\frac{\beta}{{x}}\right)\right],\: \\ $$$$\left(\alpha,\:\beta\:\in\: {R}\right) \\…
Question Number 162672 by LEKOUMA last updated on 31/Dec/21 $${Calculate} \\ $$$$\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\left(\sqrt[{\mathrm{3}}]{{x}^{\mathrm{3}} +\mathrm{3}{x}^{\mathrm{2}} }−\sqrt{{x}^{\mathrm{2}} −\mathrm{2}{x}}\right) \\ $$$$\underset{{x}\rightarrow\mathrm{7}} {\mathrm{lim}}\frac{\sqrt{{x}+\mathrm{2}}−\sqrt[{\mathrm{3}}]{{x}+\mathrm{20}}}{\:\sqrt[{\mathrm{4}}]{{x}+\mathrm{9}}−\mathrm{2}} \\ $$ Answered by tounghoungko last…
Question Number 97129 by Ar Brandon last updated on 06/Jun/20 $$\mathrm{Given}\:\:\mathrm{z}=\mathrm{x}+\mathrm{iy}\:\:\mathrm{z}\in\mathbb{C}\:\:\mathrm{z}\neq\mathrm{0} \\ $$$$\mathrm{1}\backslash\:\mathrm{A},\:\mathrm{B},\:\mathrm{and}\:\mathrm{C}\:\mathrm{are}\:\mathrm{the}\:\mathrm{images}\:\mathrm{of}\:\mathrm{z},\:\mathrm{iz},\:\mathrm{and}\:\left(\mathrm{2}−\mathrm{i}\right)+\mathrm{z} \\ $$$$\mathrm{a}\backslash\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{lengths}\:\mathrm{AB},\:\mathrm{AC},\:\mathrm{and}\:\mathrm{BC}. \\ $$$$\mathrm{b}\backslash\:\mathrm{Deduce}\:\mathrm{that}\:\mathrm{the}\:\mathrm{triangle}\:\mathrm{ABC}\:\mathrm{is}\:\mathrm{isosceles}\:\mathrm{and}\:\mathrm{not} \\ $$$$\mathrm{equilateral}. \\ $$$$\mathrm{2}\backslash\mathrm{Find}\:\mathrm{z},\:\mathrm{such}\:\mathrm{that}\:\mid\mathrm{z}\mid=\mid\frac{\mathrm{2}+\mathrm{i}}{\mathrm{z}}\mid=\mid\mathrm{z}−\mathrm{1}\mid \\ $$$$\mathrm{3}\backslash\mathrm{Given}\:\mathrm{Z},\:\mathrm{Z}\in\mathbb{C}\:\mathrm{such}\:\mathrm{that}\:\frac{\mathrm{Z}−\mathrm{1}}{\mathrm{Z}+\mathrm{1}}=\left(\frac{\mathrm{z}−\mathrm{1}}{\mathrm{z}+\mathrm{1}}\right)^{\mathrm{2}} \\ $$$$\mathrm{a}\backslash\mathrm{Express}\:\mathrm{Z}\:\mathrm{in}\:\mathrm{terms}\:\mathrm{of}\:\mathrm{z}…
Question Number 31583 by BEVARA NARASIMHULU last updated on 10/Mar/18 $${how}\:{to}\:{read}\:{this}\:\langle{x}\rangle.\:{p} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 31569 by momo last updated on 10/Mar/18 $$\left({a},\frac{\mathrm{1}}{{a}}\right),\left({b},\frac{\mathrm{1}}{{b}}\right),\left({c},\frac{\mathrm{1}}{{c}}\right),\left({d},\frac{\mathrm{1}}{{d}}\right)\:{are}\:{four} \\ $$$${distinct}\:{points}\:{on}\:{a}\:{circle}\:{of}\:{radius} \\ $$$${is}\:\mathrm{4}\:{units}\:{then}\:{abcd}\:{is}\:{equal}\:{to}\:? \\ $$ Answered by MJS last updated on 10/Mar/18 $$\mathrm{center}=\left(\mathrm{0};\mathrm{0}\right): \\…
Question Number 31543 by Cheyboy last updated on 09/Mar/18 $$\int\frac{{x}^{\mathrm{3}} +{x}+\mathrm{1}}{{x}^{\mathrm{2}} +\mathrm{1}}\:{dx} \\ $$$$ \\ $$$$ \\ $$ Commented by prof Abdo imad last updated…
Question Number 31502 by abdo imad last updated on 09/Mar/18 $${find}\:{f}\left({x}\right)=\:\int_{\mathrm{0}} ^{\mathrm{1}} {ln}\left(\mathrm{1}+{xt}^{\mathrm{2}} \right){dt}\:\:{with}\:{x}>\mathrm{0}. \\ $$$$\left.\mathrm{2}\right)\:{give}\:{thevalue}\:{of}\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \:{ln}\left(\mathrm{1}+{t}^{\mathrm{2}} \right){dt}\:{and}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:{ln}\left(\mathrm{1}+\mathrm{2}{t}^{\mathrm{2}} \right){dt}. \\ $$ Commented…
Question Number 162539 by LEKOUMA last updated on 30/Dec/21 $${Calculate}\: \\ $$$$\underset{{h}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{f}\left(\mathrm{3}−{h}\right)−{f}\left(\mathrm{3}\right)}{\mathrm{2}{h}},\:{with}\:{f}'\left(\mathrm{3}\right)=\mathrm{2} \\ $$ Answered by Ar Brandon last updated on 30/Dec/21 $$\underset{{h}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{f}\left(\mathrm{3}−{h}\right)−{f}\left(\mathrm{3}\right)}{\mathrm{2}{h}}=\frac{\mathrm{0}}{\mathrm{0}}\:\rightarrow{LH}…
Question Number 31369 by tawa tawa last updated on 07/Mar/18 Terms of Service Privacy Policy Contact: info@tinkutara.com