Question Number 95420 by bobhans last updated on 25/May/20 $$\mathrm{tinkutara}\:\mathrm{admint} \\ $$$$\mathrm{I}\:\mathrm{want}\:\mathrm{to}\:\mathrm{update}\:\mathrm{to}\:\mathrm{version}\:\mathrm{2}.\mathrm{074} \\ $$ Commented by Tinku Tara last updated on 25/May/20 Version uploaded so far on playstore is 2.073. 2.076 is only available on www.tinkutara.com and contains fixes for problem reported by MrW. Commented by…
Question Number 29880 by tawa tawa last updated on 13/Feb/18 Commented by ajfour last updated on 13/Feb/18 Commented by ajfour last updated on 13/Feb/18 $${F}\mathrm{cos}\:\alpha−{f}−{mg}\mathrm{sin}\:\alpha={ma}…
Question Number 160917 by LEKOUMA last updated on 09/Dec/21 $${Calculate} \\ $$$$\left.{a}\right)\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\left(\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}\right)^{{x}^{\mathrm{2}} } \\ $$$$\left.{b}\right)\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{2}^{\frac{\mathrm{1}}{{x}}} −\mathrm{1}}{\mathrm{2}^{\frac{\mathrm{1}}{{x}}} +\mathrm{1}} \\ $$ Answered by jama last…
Question Number 160900 by LEKOUMA last updated on 08/Dec/21 $${Calculate} \\ $$$$\left.\mathrm{1}\right)\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{{x}+\mathrm{1}}{\mathrm{2}{x}+\mathrm{1}}\right)^{{x}^{\mathrm{2}} } \\ $$$$\underset{{x}\rightarrow{a}} {\mathrm{lim}}\left(\frac{\mathrm{sin}\:{x}}{\mathrm{sin}\:{a}}\right)^{\frac{\mathrm{1}}{{x}−{a}}} \\ $$ Commented by cortano last updated on…
Question Number 160844 by Tawa11 last updated on 07/Dec/21 Answered by mr W last updated on 08/Dec/21 Commented by mr W last updated on 08/Dec/21…
Question Number 160823 by sdfg last updated on 07/Dec/21 Commented by sdfg last updated on 07/Dec/21 $${please}\:{help}\:{me} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 95259 by mhmd last updated on 24/May/20 $${find}\:{all}\:{roots}\:\left(\sqrt{\mathrm{6}}\:−\sqrt{\mathrm{2}}{i}\right)^{\frac{\mathrm{1}}{\mathrm{3}}} {by}\:{using}\:{demover}\:{theorem}\:? \\ $$ Commented by mhmd last updated on 24/May/20 $${help}\:{me}\:? \\ $$ Answered by…
Question Number 29700 by 803jaideep@gmail.com last updated on 11/Feb/18 $$\mathrm{32}^{\mathrm{32}^{\mathrm{32}} } \:/\mathrm{7}…\mathrm{find}\:\mathrm{remainder} \\ $$ Answered by Tinkutara last updated on 13/Feb/18 Commented by Tinkutara last…
Question Number 29680 by 803jaideep@gmail.com last updated on 11/Feb/18 $$\mathrm{i}^{\mathrm{i}\:} \:\:\mathrm{what}\:\mathrm{is}\:\mathrm{iota}\:\mathrm{to}\:\mathrm{power}\:\mathrm{iota} \\ $$ Answered by sma3l2996 last updated on 11/Feb/18 $${i}^{{i}} =\left({e}^{{i}\pi/\mathrm{2}} \right)^{{i}} ={e}^{−\pi/\mathrm{2}} \\…
Question Number 29648 by byaw last updated on 11/Feb/18 $$\mathrm{How}\:\mathrm{many}\:\mathrm{arrangements}\:\mathrm{are} \\ $$$$\mathrm{there}\:\mathrm{of}\:\mathrm{4}\:\mathrm{letters}\:\mathrm{chosen}\:\mathrm{from}\: \\ $$$$\mathrm{the}\:\mathrm{word}\:{COMMUNICATION} \\ $$ Commented by Rasheed.Sindhi last updated on 11/Feb/18 $$\mathrm{4096} \\…