Question Number 29048 by $@ty@m last updated on 03/Feb/18 Commented by ajfour last updated on 04/Feb/18 $${thanks}\:{for}\:{verifying}\:{Sir}! \\ $$ Commented by $@ty@m last updated on…
Question Number 28991 by abdo imad last updated on 02/Feb/18 $${prove}\:{that}\:{L}\left(\mathrm{1}\right)\left({s}\right)=\:\frac{\mathrm{1}}{{s}}\:\:{and}\:{L}\left({t}^{{n}} \right)\left({s}\right)=\:\frac{{n}!}{{s}^{{n}+\mathrm{1}} }\:.{L}\:{means} \\ $$$${laplace}\:{transform}. \\ $$ Commented by abdo imad last updated on 03/Feb/18…
Question Number 28987 by abdo imad last updated on 02/Feb/18 $${find}\:\:\int_{\mathrm{0}} ^{\mathrm{2}\pi} \:\:\:\:\:\frac{{dt}}{\left({a}+{bcost}\right)^{\mathrm{2}} }.{with}\:\:{a}>{b}>\mathrm{0}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 28930 by rita1608 last updated on 01/Feb/18 Commented by rita1608 last updated on 01/Feb/18 $${pls}\:{ans}\:{the}\:\mathrm{4}\:{th}\:{question}\:\mathrm{3}{rd}\:{and}\:\mathrm{4}\:{th}\: \\ $$$${part}\: \\ $$ Terms of Service Privacy…
Question Number 94455 by mhmd last updated on 18/May/20 $${Solve}\:\left({D}^{\mathrm{2}} −\mathrm{2}{D}+\mathrm{1}\right){y}={xe}^{{x}} {sinx}\: \\ $$$${pleas}\:{help}\:{me}\:{sir}\: \\ $$ Commented by mhmd last updated on 19/May/20 $$?? \\…
Question Number 28905 by tawa tawa last updated on 01/Feb/18 $$\mathrm{A}\:\mathrm{body}\:\mathrm{rolls}\:\mathrm{down}\:\mathrm{a}\:\mathrm{slope}\:\mathrm{from}\:\mathrm{a}\:\mathrm{height}\:\mathrm{of}\:\:\mathrm{100m}.\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{at}\:\mathrm{the}\:\mathrm{foot}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{slope}\:\mathrm{is}\:\:\mathrm{20}\:\mathrm{m}/\mathrm{s}.\:\:\mathrm{What}\:\mathrm{percentage}\:\mathrm{of}\:\mathrm{the}\:\boldsymbol{\mathrm{P}}.\boldsymbol{\mathrm{E}}\:\:\mathrm{is}\:\mathrm{converted}\:\mathrm{in}\:\:\boldsymbol{\mathrm{K}}.\boldsymbol{\mathrm{E}}\:\:? \\ $$$$ \\ $$$$\boldsymbol{\mathrm{A}}\mathrm{nswer}:\:\:\:\:\:\mathrm{20\%} \\ $$ Answered by mrW2 last updated on…
Question Number 94419 by sorour87.d last updated on 18/May/20 $${Let}\:{G}\:{be}\:{a}\:{connected}\:{graph}\:{and}\:{let}\:{X}\:{be}\:{the}\:{set}\:{of}\:{vertices}\:{of}\:{G}\:{of}\:{odd}\:{degree}.\:{suppose}\:{that}\:\mid{X}\mid=\mathrm{2}{k},\:{where}\:{k}\geqslant\mathrm{1}\: \\ $$$${show}\:{that}\:{there}\:{are}\:{k}\:{edge}-{disjoint}\:{trail}\:{Q}_{\mathrm{1}} ,\:{Q}_{\mathrm{2}} ,…,{Q}_{{k}} \:{in}\:{G}\:{such}\:{that} \\ $$$${E}\left({G}\right)={E}\left({Q}_{\mathrm{1}} \right)\cup{E}\left({Q}_{\mathrm{2}} \right)\cup….\cup{E}\left({Q}_{{k}} \right) \\ $$ Terms of Service…
Question Number 28854 by tawa tawa last updated on 31/Jan/18 $$\mathrm{The}\:\mathrm{arms}\:\mathrm{of}\:\mathrm{an}\:\mathrm{ac}\:\mathrm{maxwell}\:\mathrm{bridge}\:\mathrm{are}\:\mathrm{arranged}\:\mathrm{as}\:\mathrm{follows}:\:\:\mathrm{AB}\:\:\mathrm{is}\:\mathrm{a}\:\mathrm{non}\:-\:\mathrm{active} \\ $$$$\mathrm{resistance}\:\mathrm{of}\:\:\:\mathrm{1000}\:\Omega\:\:\mathrm{in}\:\mathrm{parallel}\:\mathrm{with}\:\mathrm{a}\:\mathrm{capacitor}\:\mathrm{of}\:\mathrm{capacitance}\:\mathrm{of}\:\:\:\mathrm{0}.\mathrm{5}\mu\mathrm{F}\:, \\ $$$$\mathrm{BC}\:\:\mathrm{is}\:\mathrm{a}\:\mathrm{non}\:-\:\mathrm{inductive}\:\mathrm{resistance}\:\mathrm{of}\:\:\mathrm{600}\:\Omega,\:\:\:\mathrm{CD}\:\mathrm{is}\:\mathrm{inductive}\:\mathrm{impedance}\:\left(\mathrm{unknown}\right) \\ $$$$\mathrm{and}\:\mathrm{DA}\:\:\mathrm{is}\:\mathrm{a}\:\mathrm{non}\:-\:\mathrm{inductive}\:\mathrm{resustance}\:\mathrm{of}\:\:\mathrm{400}\:\Omega.\:\:\mathrm{If}\:\mathrm{balance}\:\mathrm{is}\:\mathrm{obtained}\:\mathrm{under} \\ $$$$\mathrm{these}\:\mathrm{conditions}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{resistance}\:\mathrm{and}\:\mathrm{the}\:\mathrm{inductance}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{branch}\:\:\mathrm{CD}\:\:\mathrm{and}\:\mathrm{show}\:\mathrm{the}\:\mathrm{circuit}\:\mathrm{diagram}. \\ $$ Terms of…
Question Number 94360 by Ahad last updated on 18/May/20 Commented by i jagooll last updated on 18/May/20 $$\mathrm{what}\:\mathrm{do}\:\mathrm{you}\:\mathrm{ask}\:? \\ $$ Commented by mr W last…
Question Number 94359 by Emelite last updated on 18/May/20 $${If}\:\:\mathrm{32}\:{men}\:{can}\:{reap}\:{a}\:{field}\:{in}\:\mathrm{15}\:{days}\:.{In}\:{howmany}\:{days}\:{can}\:\mathrm{20}\:{men}\:{reap}\:{the}\:{same}\:{fied}? \\ $$ Commented by MJS last updated on 18/May/20 $$\mathrm{15}×\mathrm{32}/\mathrm{20}=\mathrm{24} \\ $$ Terms of Service…