Question Number 27399 by Rasheed.Sindhi last updated on 06/Jan/18 $$\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{are}\:\mathrm{walking}\:\mathrm{along}\:\mathrm{a} \\ $$$$\mathrm{circular}\:\mathrm{track}.\mathrm{They}\:\mathrm{start}\:\mathrm{from} \\ $$$$\mathrm{same}\:\mathrm{point}\:\mathrm{at}\:\mathrm{8}:\mathrm{00}\:\mathrm{am}. \\ $$$$\mathrm{A}\:\mathrm{can}\:\mathrm{walk}\:\mathrm{2}\:\mathrm{rounds}\:\mathrm{per}\:\mathrm{hour} \\ $$$$\mathrm{and}\:\mathrm{B}\:\mathrm{can}\:\mathrm{walk}\:\mathrm{3}\:\mathrm{rounds}\:\mathrm{per}\:\mathrm{hour}. \\ $$$$\mathrm{How}\:\mathrm{many}\:\mathrm{times}\:\mathrm{they}\:\mathrm{cross}\:\mathrm{each} \\ $$$$\mathrm{other}\:\mathrm{before}\:\mathrm{9}:\mathrm{30}\:\mathrm{am}\:\mathrm{if}\:\mathrm{they}\:\mathrm{walk} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{Opposite}\:\mathrm{to}\:\mathrm{each}\:\mathrm{other}. \\…
Question Number 92910 by s.ayeni14@yahoo.com last updated on 09/May/20 $$\int\frac{\mathrm{dt}}{\mathrm{3sint}+\mathrm{4cost}} \\ $$ Commented by msup by abdo last updated on 09/May/20 $${I}=\int\:\frac{{dt}}{\mathrm{3}{sint}\:+\mathrm{4}{cost}}\:{vhangement} \\ $$$${tan}\left(\frac{{t}}{\mathrm{2}}\right)={x}\:{give} \\…
Question Number 92898 by Joel578 last updated on 09/May/20 $$\mathrm{Find}\:{a},{b},{c}\:\in\:\mathbb{Z}\:\mathrm{that}\:\mathrm{satisfy} \\ $$$$\left(\mathrm{7}{a}\:+\:\mathrm{15}{b}\:+\:\mathrm{0}{c}\right)\:\mathrm{mod}\:\mathrm{26}\:=\:\mathrm{8} \\ $$$$\left(\mathrm{5}{a}\:+\:\mathrm{16}{b}\:+\:\mathrm{6}{c}\right)\:\mathrm{mod}\:\mathrm{26}\:=\:\mathrm{21} \\ $$$$\left(\mathrm{6}{a}\:+\:\mathrm{3}{b}\:+\:\mathrm{20}{c}\right)\:\mathrm{mod}\:\mathrm{26}\:=\:\mathrm{14} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 92888 by s.ayeni14@yahoo.com last updated on 09/May/20 $$\int\frac{\mathrm{5}−\mathrm{t}}{\mathrm{1}+\sqrt{\left(\mathrm{t}−\mathrm{4}\right)}}\mathrm{dt} \\ $$$$ \\ $$ Commented by mathmax by abdo last updated on 09/May/20 $${I}\:=\int\frac{\mathrm{5}−{t}}{\mathrm{1}+\sqrt{{t}−\mathrm{4}}}{dt}\:{we}\:{do}\:{the}\:{changement}\:\sqrt{{t}−\mathrm{4}}={x}\:\Rightarrow{t}−\mathrm{4}={x}^{\mathrm{2}} \:\Rightarrow…
Question Number 158421 by tebohlouis last updated on 03/Nov/21 Answered by 1549442205PVT last updated on 04/Nov/21 $${In}\:{three}\:{consecutive}\:{integers}\:{there}\:{is}\:{always}\:{a}\:{number}\:{divisible} \\ $$$${by}\:\mathrm{3}\:{and}\:{least}\:{at}\:{an}\:{integer}\:{to}\:{be}\:{even} \\ $$$${Hence}\:\left({n}−\mathrm{2}\right)\left({n}−\mathrm{1}\right){n}\:{is}\:{divisible}\:{by}\:\mathrm{6} \\ $$$$,{so}\:\frac{\left({n}−\mathrm{2}\right)\left({n}−\mathrm{1}\right){n}}{\mathrm{6}}\:{is}\:{an}\:{integer} \\ $$…
Question Number 158419 by tebohlouis last updated on 03/Nov/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 27334 by darkalestero1@gmail.com last updated on 05/Jan/18 $$\frac{\mathrm{q}_{\mathrm{1}} }{\mathrm{q}_{\mathrm{2}} }=\left(\frac{\mathrm{x}}{\mathrm{0}.\mathrm{8}−\mathrm{x}}\right)^{\mathrm{2}} \:\:\:\:;\:\boldsymbol{\mathrm{x}}=? \\ $$ Answered by mrW1 last updated on 05/Jan/18 $$\frac{{x}}{\mathrm{0}.\mathrm{8}−{x}}=\pm\sqrt{\frac{{q}_{\mathrm{1}} }{{q}_{\mathrm{2}} }}…
Question Number 27335 by bsayani309@gmail.com last updated on 05/Jan/18 $${if}\:\mathrm{2}\:{chords}\:{of}\:{ellipse}\:{have}\:{the}\:{same} \\ $$$${distance}\:{from}\:{the}\:{centre}\:{of}\:{ellipse} \\ $$$${and}\:{the}\:{eccentric}\:{angle}\:{of}\:{the}\:{end}\:{points}\:{of}\:{the}\:{chords} \\ $$$${are}\:{respectivly}\:\alpha\:\beta\:\gamma\:\delta\:{then}\:{prove}\:{that} \\ $$$$\mathrm{tan}\:\frac{\alpha}{\mathrm{2}}×\mathrm{tan}\:\frac{\beta}{\mathrm{2}}×\mathrm{tan}\:\frac{\gamma}{\mathrm{2}}×\mathrm{tan}\:\frac{\delta}{\mathrm{2}}=\mathrm{1} \\ $$ Commented by bsayani309@gmail.com last updated…
Question Number 27332 by ajfour last updated on 05/Jan/18 Commented by ajfour last updated on 05/Jan/18 $${Find}\:{acceleration}\:{of}\:{blue}\:{and} \\ $$$${brown}\:{blocks}.\:{Friction}\:{coefficient} \\ $$$${is}\:\boldsymbol{\mu}\:{everywhere}\:\left({sufficiently}\:{less},\right. \\ $$$$\left.{and}\:{permits}\:{motion}\right). \\ $$…
Question Number 27293 by sorour87 last updated on 04/Jan/18 $${L}^{−\mathrm{1}} \left(\frac{{s}^{\mathrm{3}} }{{s}^{\mathrm{4}} +\mathrm{4}}\right)=? \\ $$ Answered by sma3l2996 last updated on 04/Jan/18 $$\frac{{s}^{\mathrm{3}} }{{s}^{\mathrm{4}} +\mathrm{4}}=\frac{{a}}{{s}−\left(\mathrm{1}+{i}\right)}+\frac{{b}}{{s}+\left(\mathrm{1}−{i}\right)}+\frac{{c}}{{s}+\left(\mathrm{1}+{i}\right)}+\frac{{d}}{{s}−\left(\mathrm{1}−{i}\right)}…