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x-2-x-5xy-6y-2-2y-2-0-

Question Number 155400 by TVTA last updated on 30/Sep/21 $${x}^{\mathrm{2}} +{x}+\mathrm{5}{xy}+\mathrm{6}{y}^{\mathrm{2}} +\mathrm{2}{y}−\mathrm{2}=\mathrm{0} \\ $$ Commented by MJS_new last updated on 30/Sep/21 $$\mathrm{hyperbola}\:\mathrm{with}\:\mathrm{center}\:\begin{bmatrix}{\mathrm{2}}\\{−\mathrm{1}}\end{bmatrix}\:\mathrm{and}\:\mathrm{axes} \\ $$$${a}=\mathrm{2}\sqrt{−\mathrm{7}+\mathrm{5}\sqrt{\mathrm{2}}} \\…

In-the-figure-shown-below-all-surfaces-are-smooth-strings-and-pulley-are-ideal-If-the-wedge-is-moving-with-acceleration-a-towards-the-right-then-the-acceleration-of-the-block-with-respect-to-the-w

Question Number 24301 by Tinkutara last updated on 15/Nov/17 $$\mathrm{In}\:\mathrm{the}\:\mathrm{figure}\:\mathrm{shown}\:\mathrm{below},\:\mathrm{all}\:\mathrm{surfaces} \\ $$$$\mathrm{are}\:\mathrm{smooth},\:\mathrm{strings}\:\mathrm{and}\:\mathrm{pulley}\:\mathrm{are}\:\mathrm{ideal}. \\ $$$$\mathrm{If}\:\mathrm{the}\:\mathrm{wedge}\:\mathrm{is}\:\mathrm{moving}\:\mathrm{with}\:\mathrm{acceleration} \\ $$$${a}\:\mathrm{towards}\:\mathrm{the}\:\mathrm{right},\:\mathrm{then}\:\mathrm{the}\:\mathrm{acceleration} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{block}\:\mathrm{with}\:\mathrm{respect}\:\mathrm{to}\:\mathrm{the}\:\mathrm{wedge} \\ $$$$\mathrm{at}\:\mathrm{that}\:\mathrm{instant}\:\mathrm{is} \\ $$ Commented by Tinkutara…

In-a-fuel-cell-methanol-is-used-as-a-fuel-and-O-2-is-used-as-oxidizer-The-standard-enthalpy-of-combustion-of-methanol-is-726-kJ-mol-1-The-standard-free-energies-of-formation-of-CH-3-OH-l-CO

Question Number 24287 by Tinkutara last updated on 15/Nov/17 $$\mathrm{In}\:\mathrm{a}\:\mathrm{fuel}\:\mathrm{cell},\:\mathrm{methanol}\:\mathrm{is}\:\mathrm{used}\:\mathrm{as}\:\mathrm{a}\:\mathrm{fuel} \\ $$$$\mathrm{and}\:\mathrm{O}_{\mathrm{2}} \:\mathrm{is}\:\mathrm{used}\:\mathrm{as}\:\mathrm{oxidizer}.\:\mathrm{The}\:\mathrm{standard} \\ $$$$\mathrm{enthalpy}\:\mathrm{of}\:\mathrm{combustion}\:\mathrm{of}\:\mathrm{methanol}\:\mathrm{is} \\ $$$$−\mathrm{726}\:\mathrm{kJ}\:\mathrm{mol}^{−\mathrm{1}} .\:\mathrm{The}\:\mathrm{standard}\:\mathrm{free} \\ $$$$\mathrm{energies}\:\mathrm{of}\:\mathrm{formation}\:\mathrm{of}\:\mathrm{CH}_{\mathrm{3}} \mathrm{OH}\left(\mathrm{l}\right), \\ $$$$\mathrm{CO}_{\mathrm{2}} \left(\mathrm{g}\right)\:\mathrm{and}\:\mathrm{H}_{\mathrm{2}} \mathrm{O}\left(\mathrm{l}\right)\:\mathrm{are}\:−\mathrm{166}.\mathrm{3},\:−\mathrm{394}.\mathrm{4}…

The-reversible-expansion-of-an-ideal-gas-under-adiabatic-and-isothermal-conditions-is-shown-in-the-figure-Which-of-the-following-statement-s-is-are-correct-1-T-1-T-2-2-T-3-gt-T-1-3-

Question Number 24263 by Tinkutara last updated on 14/Nov/17 $$\mathrm{The}\:\mathrm{reversible}\:\mathrm{expansion}\:\mathrm{of}\:\mathrm{an}\:\mathrm{ideal} \\ $$$$\mathrm{gas}\:\mathrm{under}\:\mathrm{adiabatic}\:\mathrm{and}\:\mathrm{isothermal} \\ $$$$\mathrm{conditions}\:\mathrm{is}\:\mathrm{shown}\:\mathrm{in}\:\mathrm{the}\:\mathrm{figure}.\:\mathrm{Which} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{statement}\left(\mathrm{s}\right)\:\mathrm{is}\:\left(\mathrm{are}\right) \\ $$$$\mathrm{correct}? \\ $$$$\left(\mathrm{1}\right)\:\mathrm{T}_{\mathrm{1}} \:=\:\mathrm{T}_{\mathrm{2}} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{T}_{\mathrm{3}} \:>\:\mathrm{T}_{\mathrm{1}} \\…

Which-of-the-following-reaction-is-are-exothermic-reaction-s-1-CaCO-3-CaO-CO-2-2-Fe-S-FeS-3-NaOH-HCl-NaCl-H-2-O-4-CH-4-O-2-CO-2-2H-2-O-

Question Number 24259 by Tinkutara last updated on 14/Nov/17 $$\mathrm{Which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{reaction}\:\mathrm{is}/\mathrm{are} \\ $$$$\mathrm{exothermic}\:\mathrm{reaction}/\mathrm{s}? \\ $$$$\left(\mathrm{1}\right)\:\mathrm{CaCO}_{\mathrm{3}} \:\rightarrow\:\mathrm{CaO}\:+\:\mathrm{CO}_{\mathrm{2}} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{Fe}\:+\:\mathrm{S}\:\rightarrow\:\mathrm{FeS} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{NaOH}\:+\:\mathrm{HCl}\:\rightarrow\:\mathrm{NaCl}\:+\:\mathrm{H}_{\mathrm{2}} \mathrm{O} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{CH}_{\mathrm{4}} \:+\:\mathrm{O}_{\mathrm{2}} \:\rightarrow\:\mathrm{CO}_{\mathrm{2}} \:+\:\mathrm{2H}_{\mathrm{2}}…

f-x-f-x-3pi-8-x-R-if-0-3pi-8-f-x-dx-t-then-pi-5pi-2-f-x-pi-dx-A-2t-B-3t-C-4t-D-6t-E-8t-

Question Number 89745 by jagoll last updated on 19/Apr/20 $$\mathrm{f}\left(\mathrm{x}\right)\:=\:\mathrm{f}\left(\mathrm{x}+\frac{\mathrm{3}\pi}{\mathrm{8}}\right)\:,\:\forall\mathrm{x}\in\:\mathbb{R} \\ $$$$\mathrm{if}\:\underset{\mathrm{0}} {\overset{\mathrm{3}\pi/\mathrm{8}} {\int}}\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{dx}\:=\:\mathrm{t}\:,\:\mathrm{then}\: \\ $$$$\underset{\pi} {\overset{\mathrm{5}\pi/\mathrm{2}} {\int}}\mathrm{f}\left(\mathrm{x}−\pi\right)\:\mathrm{dx}\:=\: \\ $$$$\mathrm{A}.\:\mathrm{2t}\:\:\:\:\:\:\:\mathrm{B}.\:\mathrm{3t}\:\:\:\:\:\:\:\mathrm{C}.\:\mathrm{4t}\:\:\:\:\:\:\:\mathrm{D}.\:\mathrm{6t} \\ $$$$\mathrm{E}.\:\mathrm{8t}\: \\ $$ Commented…

Find-the-area-bounded-by-3x-4y-12-and-the-coordinate-axes-

Question Number 89728 by Mr.Panoply last updated on 18/Apr/20 $${Find}\:{the}\:{area}\:{bounded}\:{by}\:\mathrm{3}{x}+\mathrm{4}{y}=\mathrm{12} \\ $$$${and}\:{the}\:{coordinate}\:{axes}? \\ $$ Answered by MJS last updated on 19/Apr/20 $$\mathrm{3}{x}+\mathrm{4}{y}=\mathrm{12}\:\mathrm{is}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{line} \\ $$$${x}=\mathrm{0}\:\Rightarrow\:{y}=\mathrm{3} \\…

n-1-equal-point-masses-each-of-mass-m-are-placed-at-the-vertices-of-a-regular-n-polygon-The-vacant-vertex-has-a-position-vector-a-with-respect-to-the-centre-of-the-polygon-Find-the-position-vect

Question Number 24186 by Tinkutara last updated on 14/Nov/17 $$\left({n}\:−\:\mathrm{1}\right)\:\mathrm{equal}\:\mathrm{point}\:\mathrm{masses}\:\mathrm{each}\:\mathrm{of}\:\mathrm{mass} \\ $$$${m}\:\mathrm{are}\:\mathrm{placed}\:\mathrm{at}\:\mathrm{the}\:\mathrm{vertices}\:\mathrm{of}\:\mathrm{a}\:\mathrm{regular} \\ $$$${n}-\mathrm{polygon}.\:\mathrm{The}\:\mathrm{vacant}\:\mathrm{vertex}\:\mathrm{has}\:\mathrm{a} \\ $$$$\mathrm{position}\:\mathrm{vector}\:{a}\:\mathrm{with}\:\mathrm{respect}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{centre}\:\mathrm{of}\:\mathrm{the}\:\mathrm{polygon}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{position} \\ $$$$\mathrm{vector}\:\mathrm{of}\:\mathrm{centre}\:\mathrm{of}\:\mathrm{mass}. \\ $$ Commented by mrW1…