Question Number 23823 by tawa tawa last updated on 06/Nov/17 $$\mathrm{The}\:\mathrm{period}\:\mathrm{of}\:\mathrm{a}\:\mathrm{simple}\:\mathrm{pendulum}\:\mathrm{A}\:\mathrm{is}\:\mathrm{6}\:\mathrm{secs}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{period}\:\mathrm{of}\:\mathrm{a}\:\mathrm{simple} \\ $$$$\mathrm{pendulum}\:\mathrm{B},\:\mathrm{if}\:\mathrm{A}\:\mathrm{makes}\:\mathrm{30}\:\mathrm{oscillation}\:\mathrm{in}\:\mathrm{the}\:\mathrm{time}\:\mathrm{it}\:\mathrm{takes}\:\mathrm{B}\:\mathrm{to}\:\mathrm{make}\:\mathrm{70} \\ $$$$\mathrm{oscillation}. \\ $$ Answered by mrW1 last updated on 07/Nov/17 $$\mathrm{30}{T}_{{A}}…
Question Number 23793 by math solver last updated on 06/Nov/17 Commented by math solver last updated on 06/Nov/17 $$\mathrm{q}.\mathrm{2},\mathrm{3} \\ $$ Answered by ajfour last…
Question Number 89324 by 174 last updated on 16/Apr/20 Commented by mathmax by abdo last updated on 16/Apr/20 $$\:\:{let}\:\:{f}\left({a}\right)=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {ln}\left({a}+{cos}^{\mathrm{2}} {x}\right){dx}\:\:{with}\:{a}>\mathrm{0} \\ $$$${f}^{'} \left({a}\right)\:=\int_{\mathrm{0}}…
Question Number 23773 by FilupES last updated on 06/Nov/17 $$\mathrm{I}\:\mathrm{have}\:\mathrm{a}\:\mathrm{leaderboard}\:\mathrm{with}\:\mathrm{the}\:\mathrm{data}\:\mathrm{of}\:'\mathrm{runners}'. \\ $$$$\mathrm{Each}\:\mathrm{runner}\:\mathrm{has}\:\mathrm{a}\:'\mathrm{place}'\:\left(\mathrm{1st},\:\mathrm{2nd},\:\mathrm{etc}.\right), \\ $$$$\mathrm{and}\:\mathrm{a}\:'\mathrm{time}'\:\left(\mathrm{in}\:\mathrm{seconds}\right). \\ $$$$\: \\ $$$$\mathrm{Every}\:\mathrm{day}\:\mathrm{I}\:\mathrm{have}\:\mathrm{been}\:\mathrm{comparing}\:\mathrm{the}\:\mathrm{data}. \\ $$$$\mathrm{What}\:\mathrm{information}\:\mathrm{is}\:\mathrm{important}\:\mathrm{to}\:\mathrm{note}\:\mathrm{when} \\ $$$$\mathrm{looking}\:\mathrm{at}\:\mathrm{data}\:\mathrm{such}\:\mathrm{as}\:\mathrm{this}? \\ $$$$\: \\…
Question Number 23739 by ajfour last updated on 04/Nov/17 Commented by ajfour last updated on 04/Nov/17 $${If}\:{system}\:{of}\:{pair}\:{of}\:{rods}\:{shown} \\ $$$${is}\:{released}\:{at}\:{rest}\:{when}\:\theta_{\mathrm{0}} =\phi_{\mathrm{0}} =\frac{\pi}{\mathrm{4}}\:; \\ $$$${find}\:\phi\:{as}\:{a}\:{function}\:{of}\:\theta\:{a}\:{little} \\ $$$${later}\:\left({till}\:{smaller}\:{rod}\:{is}\:{in}\:{contact}\right.…
Question Number 23722 by Tinkutara last updated on 04/Nov/17 $$\mathrm{A}\:\mathrm{block}\:\mathrm{of}\:\mathrm{mass}\:{m}\:\mathrm{is}\:\mathrm{pulled}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{smooth}\:\mathrm{horizontal}\:\mathrm{floor}\:\mathrm{using}\:\mathrm{two} \\ $$$$\mathrm{methods}\:\mathrm{I}\:\mathrm{and}\:\mathrm{II}.\:\mathrm{The}\:\mathrm{ratio}\:\mathrm{of} \\ $$$$\mathrm{acceleration}\:\frac{{a}_{{I}} }{{a}_{{II}} }\:\mathrm{is} \\ $$ Commented by Tinkutara last updated…
Question Number 23715 by Tinkutara last updated on 04/Nov/17 $$\mathrm{Why}\:\Delta\mathrm{S}\:>\:\mathrm{0}\:\mathrm{for}\:\mathrm{the}\:\mathrm{reaction} \\ $$$$\mathrm{2HgO}\left(\mathrm{s}\right)\:\rightarrow\:\mathrm{2Hg}\left({l}\right)\:+\:\mathrm{O}_{\mathrm{2}} \left(\mathrm{g}\right)? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 23711 by Tinkutara last updated on 04/Nov/17 $$\mathrm{A}\:\mathrm{certain}\:\mathrm{ideal}\:\mathrm{gas}\:\mathrm{has}\:\mathrm{C}_{\mathrm{v},\:\mathrm{m}} \:=\:\mathrm{a}\:+\:\mathrm{bT}, \\ $$$$\mathrm{where}\:\mathrm{a}\:=\:\mathrm{25}\:\mathrm{J}/\left(\mathrm{mol}.\:\mathrm{K}\right)\:\mathrm{and}\:\mathrm{b}\:=\:\mathrm{0}.\mathrm{03} \\ $$$$\mathrm{J}\left(\mathrm{mol}.\mathrm{K}^{\mathrm{2}} \right).\:\mathrm{Let}\:\mathrm{2}\:\mathrm{mole}\:\mathrm{of}\:\mathrm{this}\:\mathrm{gas}\:\mathrm{go} \\ $$$$\mathrm{from}\:\mathrm{300}\:\mathrm{K}\:\mathrm{and}\:\mathrm{2}\:\mathrm{litre}\:\mathrm{volume}\:\mathrm{to}\:\mathrm{600}\:\mathrm{K} \\ $$$$\mathrm{and}\:\mathrm{4}\:\mathrm{litre}.\:\Delta\mathrm{S}_{\mathrm{gas}} \:\mathrm{is} \\ $$ Answered by…
Question Number 23707 by Tinkutara last updated on 04/Nov/17 $$\mathrm{Two}\:\mathrm{blocks}\:{A}\:\mathrm{and}\:{B}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{1}\:\mathrm{kg}\:\mathrm{and} \\ $$$$\mathrm{2}\:\mathrm{kg}\:\mathrm{respectively}\:\mathrm{are}\:\mathrm{connected}\:\mathrm{by}\:\mathrm{a} \\ $$$$\mathrm{string},\:\mathrm{passing}\:\mathrm{over}\:\mathrm{a}\:\mathrm{light}\:\mathrm{frictionless} \\ $$$$\mathrm{pulley}.\:\mathrm{Both}\:\mathrm{the}\:\mathrm{blocks}\:\mathrm{are}\:\mathrm{resting}\:\mathrm{on}\:\mathrm{a} \\ $$$$\mathrm{horizontal}\:\mathrm{floor}\:\mathrm{and}\:\mathrm{the}\:\mathrm{pulley}\:\mathrm{is}\:\mathrm{held} \\ $$$$\mathrm{such}\:\mathrm{that}\:\mathrm{string}\:\mathrm{remains}\:\mathrm{just}\:\mathrm{taut}.\:\mathrm{At} \\ $$$$\mathrm{time}\:{t}\:=\:\mathrm{0},\:\mathrm{a}\:\mathrm{force}\:{F}\:=\:\mathrm{20}{t}\:\mathrm{N},\:\mathrm{starts} \\ $$$$\mathrm{acting}\:\mathrm{on}\:\mathrm{the}\:\mathrm{pulley}\:\mathrm{along}\:\mathrm{vertically} \\…
Question Number 89244 by 174 last updated on 16/Apr/20 Commented by mathmax by abdo last updated on 16/Apr/20 $${A}\:=\int_{\mathrm{0}} ^{\mathrm{1}} \left\{\frac{\mathrm{1}}{{x}}\right\}^{\mathrm{2}} \:{dx}\:\:{cha}\mathrm{7}{gement}\:\frac{\mathrm{1}}{{x}}={t}\:{give}\: \\ $$$${A}\:=−\int_{\mathrm{1}} ^{+\infty}…