Question Number 64824 by Tanmay chaudhury last updated on 22/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64823 by Tanmay chaudhury last updated on 22/Jul/19 Commented by Tanmay chaudhury last updated on 22/Jul/19 $${pls}\:{try}\:{to}\:{solve}\:{the}\:{above}\:{two}… \\ $$ Commented by mr W…
Question Number 64812 by Rio Michael last updated on 21/Jul/19 $${how}\:{do}\:{i}\:{prove}\:{by}\:{induction}? \\ $$$${please} \\ $$ Commented by MJS last updated on 21/Jul/19 $$\mathrm{show}\:\mathrm{that}\:\mathrm{it}'\mathrm{s}\:\mathrm{true}\:\mathrm{for}\:{n}_{\mathrm{0}} \in\mathbb{N} \\…
Question Number 64804 by mmkkmm000m last updated on 21/Jul/19 $$\overset{+\infty} {\int}_{\mathrm{0}} {e}^{−{x}^{\mathrm{2}} } {dx} \\ $$ Answered by Tanmay chaudhury last updated on 21/Jul/19 $${x}={t}^{\frac{\mathrm{1}}{\mathrm{2}}}…
Question Number 130337 by EDWIN88 last updated on 24/Jan/21 $$\:\left(\mathrm{x}^{\mathrm{2}} −\mathrm{4x}+\mathrm{3}\right)^{\mathrm{x}^{\mathrm{2}} −\mathrm{6x}+\mathrm{4}} \:\leqslant\:\mathrm{1}\: \\ $$ Answered by mathmax by abdo last updated on 24/Jan/21 $$\mathrm{e}\Rightarrow\mathrm{e}^{\left(\mathrm{x}^{\mathrm{2}}…
Question Number 64791 by Tawa1 last updated on 21/Jul/19 Commented by Tawa1 last updated on 21/Jul/19 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:\mathrm{x} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 64788 by Rio Michael last updated on 21/Jul/19 $${two}\:{consercutive}\:{integers}\:{between}\:{which}\:{a}\:{root}\:{of}\:{the}\:{equation}\:{lie}\:{are}: \\ $$$${x}^{\mathrm{2}} +\mathrm{3}{x}+\mathrm{2}=\mathrm{0} \\ $$ Commented by MJS last updated on 21/Jul/19 $$\mathrm{the}\:\mathrm{roots}\:\mathrm{are}\:{x}=−\mathrm{2}\:\mathrm{and}\:{x}=−\mathrm{1}\:\mathrm{so}\:\mathrm{there}'\mathrm{s}\:\mathrm{no} \\…
Question Number 130280 by meya last updated on 23/Jan/21 $$\frac{{d}\left({u}\varphi\right)}{{dt}}=? \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64729 by Tanmay chaudhury last updated on 20/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64730 by Tanmay chaudhury last updated on 20/Jul/19 Answered by ajfour last updated on 20/Jul/19 $${E}=\rho{j} \\ $$$$\Rightarrow\:{E}=\frac{\rho{I}}{\mathrm{2}\pi{r}^{\mathrm{2}} } \\ $$$$\bigtriangleup{V}\:=\int{Eds}\:=\:\frac{\rho{I}}{\mathrm{2}\pi}\left(\frac{\mathrm{1}}{{D}}−\frac{\mathrm{1}}{{D}+{w}}\right) \\ $$$${i}=\frac{\bigtriangleup{V}}{{R}}=\:\frac{\rho{Iw}}{\mathrm{2}\pi{RD}\left({D}+{w}\right)}…