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Question Number 89126 by 43100Maryam last updated on 15/Apr/20 $$\mathrm{6}\left[\sqrt{\:\:}\right. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 23585 by Tinkutara last updated on 02/Nov/17 $$\mathrm{No}\:\mathrm{work}\:\mathrm{is}\:\mathrm{done}\:\mathrm{by}\:\mathrm{a}\:\mathrm{force}\:\mathrm{on}\:\mathrm{an}\:\mathrm{object}\:\mathrm{if} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{the}\:\mathrm{object}\:\mathrm{is}\:\mathrm{stationary}\:\mathrm{but}\:\mathrm{the} \\ $$$$\mathrm{point}\:\mathrm{of}\:\mathrm{application}\:\mathrm{of}\:\mathrm{the}\:\mathrm{force}\:\mathrm{moves} \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{object} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{the}\:\mathrm{object}\:\mathrm{moves}\:\mathrm{in}\:\mathrm{such}\:\mathrm{a}\:\mathrm{way} \\ $$$$\mathrm{that}\:\mathrm{the}\:\mathrm{point}\:\mathrm{of}\:\mathrm{application}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{force}\:\mathrm{remains}\:\mathrm{fixed} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{the}\:\mathrm{force}\:\mathrm{is}\:\mathrm{always}\:\mathrm{perpendicular}\:\mathrm{to} \\…
Question Number 23559 by ajfour last updated on 01/Nov/17 Commented by ajfour last updated on 01/Nov/17 $${For}\:{the}\:{situation}\:{shown},\:{find}\: \\ $$$${the}\:\boldsymbol{{tension}}\:\boldsymbol{{T}}_{\mathrm{0}} \:{at}\:{midpoint}\:{P}. \\ $$$${Also}\:{find}\:{the}\:{length}\:\boldsymbol{{l}}\:{of}\:{rope}\:{in} \\ $$$${terms}\:{of}\:\boldsymbol{{a}}.\:{Given}\:{mass}\:{of}\:{rope} \\…
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Question Number 89092 by 174 last updated on 15/Apr/20 $${Evaluate}\::\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:{e}^{−{n}} \:\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\frac{{n}^{{k}} }{{k}!} \\ $$ Commented by abdomathmax last updated on 15/Apr/20 $${we}\:{have}\:\:{e}^{{n}}…
Question Number 89089 by Abhinav Sonker last updated on 15/Apr/20 $$\mathrm{16}^{\mathrm{3}/\mathrm{4}} \:+\mathrm{2} \\ $$ Answered by Joel578 last updated on 15/Apr/20 $$\mathrm{16}\:=\:\mathrm{2}^{\mathrm{4}} \\ $$$$\Rightarrow\:\left(\mathrm{2}^{\mathrm{4}} \right)^{\mathrm{3}/\mathrm{4}}…
Question Number 23556 by Tinkutara last updated on 01/Nov/17 $$\mathrm{A}\:\mathrm{ball}\:\mathrm{falls}\:\mathrm{vertically}\:\mathrm{on}\:\mathrm{to}\:\mathrm{a}\:\mathrm{floor},\:\mathrm{with} \\ $$$$\mathrm{momentum}\:{p},\:\mathrm{and}\:\mathrm{then}\:\mathrm{bounces} \\ $$$$\mathrm{repeatedly},\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{restitution} \\ $$$$\mathrm{is}\:{e}.\:\mathrm{The}\:\mathrm{total}\:\mathrm{momentum}\:\mathrm{imparted}\:\mathrm{by} \\ $$$$\mathrm{the}\:\mathrm{ball}\:\mathrm{to}\:\mathrm{the}\:\mathrm{floor}\:\mathrm{is} \\ $$ Answered by ajfour last updated…
Question Number 23548 by ajfour last updated on 01/Nov/17 Commented by ajfour last updated on 01/Nov/17 $${Find}\:\boldsymbol{{v}}\:{in}\:{terms}\:{of}\:\boldsymbol{{u}},\boldsymbol{{a}},\:\boldsymbol{{b}},\:{and}\:\boldsymbol{{l}}\: \\ $$$${at}\:{a}\:{moment}\:{when}\:{the}\:{collars} \\ $$$${at}\:{distances}\:\boldsymbol{{a}},\:{and}\:\boldsymbol{{b}}\:{from}\:{the} \\ $$$${vertical}\:{rod}\:{of}\:{the}\:{stand}. \\ $$…
Question Number 89074 by Alhaji Bai Sama last updated on 15/Apr/20 $$×^{\mathrm{4}} +×^{\mathrm{2}} =\mathrm{1} \\ $$ Commented by john santu last updated on 15/Apr/20 $${x}^{\mathrm{4}}…