Question Number 23707 by Tinkutara last updated on 04/Nov/17 $$\mathrm{Two}\:\mathrm{blocks}\:{A}\:\mathrm{and}\:{B}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{1}\:\mathrm{kg}\:\mathrm{and} \\ $$$$\mathrm{2}\:\mathrm{kg}\:\mathrm{respectively}\:\mathrm{are}\:\mathrm{connected}\:\mathrm{by}\:\mathrm{a} \\ $$$$\mathrm{string},\:\mathrm{passing}\:\mathrm{over}\:\mathrm{a}\:\mathrm{light}\:\mathrm{frictionless} \\ $$$$\mathrm{pulley}.\:\mathrm{Both}\:\mathrm{the}\:\mathrm{blocks}\:\mathrm{are}\:\mathrm{resting}\:\mathrm{on}\:\mathrm{a} \\ $$$$\mathrm{horizontal}\:\mathrm{floor}\:\mathrm{and}\:\mathrm{the}\:\mathrm{pulley}\:\mathrm{is}\:\mathrm{held} \\ $$$$\mathrm{such}\:\mathrm{that}\:\mathrm{string}\:\mathrm{remains}\:\mathrm{just}\:\mathrm{taut}.\:\mathrm{At} \\ $$$$\mathrm{time}\:{t}\:=\:\mathrm{0},\:\mathrm{a}\:\mathrm{force}\:{F}\:=\:\mathrm{20}{t}\:\mathrm{N},\:\mathrm{starts} \\ $$$$\mathrm{acting}\:\mathrm{on}\:\mathrm{the}\:\mathrm{pulley}\:\mathrm{along}\:\mathrm{vertically} \\…
Question Number 89244 by 174 last updated on 16/Apr/20 Commented by mathmax by abdo last updated on 16/Apr/20 $${A}\:=\int_{\mathrm{0}} ^{\mathrm{1}} \left\{\frac{\mathrm{1}}{{x}}\right\}^{\mathrm{2}} \:{dx}\:\:{cha}\mathrm{7}{gement}\:\frac{\mathrm{1}}{{x}}={t}\:{give}\: \\ $$$${A}\:=−\int_{\mathrm{1}} ^{+\infty}…
Question Number 89236 by 675480065 last updated on 16/Apr/20 $$\mathrm{z}\left(\mathrm{z}^{\mathrm{2}} +\mathrm{3x}\right)+\mathrm{3y}=\mathrm{0} \\ $$$$\mathrm{show}\:\mathrm{that} \\ $$$$\frac{\partial^{\mathrm{2}} \mathrm{z}}{\partial\mathrm{x}^{\mathrm{2}} }+\frac{\partial^{\mathrm{2}} \mathrm{z}}{\partial\mathrm{y}^{\mathrm{2}} }=\frac{\mathrm{2z}\left(\mathrm{x}−\mathrm{1}\right)}{\left(\mathrm{z}^{\mathrm{2}} +\mathrm{x}\right)^{\mathrm{3}} } \\ $$ Answered by…
Question Number 89238 by cindiaulia last updated on 16/Apr/20 $$\int_{\mathrm{7}} ^{\mathrm{12}} \mathrm{x}^{\mathrm{2}} \sqrt{\mathrm{x}−\mathrm{3}} \\ $$ Commented by mathmax by abdo last updated on 16/Apr/20 $${I}=\int\:{x}^{\mathrm{2}}…
Question Number 23694 by Tinkutara last updated on 04/Nov/17 $${Calculate}\:{the}\:{lattice}\:{enthalpy}\:{of}\:{MgBr}_{\mathrm{2}} . \\ $$$${Given}\:{that} \\ $$$${Enthalpy}\:{of}\:{formation}\:{of}\:{MgBr}_{\mathrm{2}} \:=\:−\mathrm{524} \\ $$$${kJ}\:{mol}^{−\mathrm{1}} \\ $$$${Sublimation}\:{energy}\:{of}\:{Mg}\:=\:+\mathrm{2187} \\ $$$${kJ}\:{mol}^{−\mathrm{1}} \\ $$$${Vaporisation}\:{energy}\:{of}\:{Br}_{\mathrm{2}} \left({l}\right)\:=\:+\mathrm{31}…
Question Number 154741 by ajfour last updated on 21/Sep/21 $${I}\:{danced},\:{its}\:{a}\:{bit}\:{calculus}\:{based}! \\ $$$${I}\:{am}\:{all}\:{praises}\:{for}\:{Caro}\: \\ $$$${Emerald}'{s}\:{songs}. \\ $$ Commented by ajfour last updated on 21/Sep/21 https://youtu.be/OMZPFFTU-T4 Commented…
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Question Number 23666 by Tinkutara last updated on 03/Nov/17 $$\mathrm{A}\:\mathrm{uniform}\:\mathrm{rope}\:\mathrm{of}\:\mathrm{length}\:{L}\:\mathrm{and}\:\mathrm{mass} \\ $$$$\mathrm{per}\:\mathrm{unit}\:\lambda\:\mathrm{having}\:\mathrm{one}\:\mathrm{end}\:\mathrm{fixed}\:\mathrm{with} \\ $$$$\mathrm{the}\:\mathrm{ceiling}\:\mathrm{is}\:\mathrm{released}\:\mathrm{from}\:\mathrm{rest}.\:\mathrm{Find} \\ $$$$\mathrm{the}\:\mathrm{tension}\:\mathrm{in}\:\mathrm{the}\:\mathrm{fixed}\:\mathrm{end}\:\mathrm{as}\:\mathrm{a}\:\mathrm{function} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{travelled}\:\mathrm{by}\:\mathrm{the}\:\mathrm{movable} \\ $$$$\mathrm{end}. \\ $$ Commented by Tinkutara…
Question Number 23645 by Tinkutara last updated on 03/Nov/17 $$\mathrm{Ethylene}\:\mathrm{on}\:\mathrm{combustion}\:\mathrm{gives}\:\mathrm{carbon} \\ $$$$\mathrm{dioxide}\:\mathrm{and}\:\mathrm{water}.\:\mathrm{Its}\:\mathrm{enthalpy}\:\mathrm{of} \\ $$$$\mathrm{combustion}\:\mathrm{is}\:\mathrm{1410}\:\mathrm{kJ}/\mathrm{mol}.\:\mathrm{If}\:\mathrm{the} \\ $$$$\mathrm{enthalpy}\:\mathrm{of}\:\mathrm{formation}\:\mathrm{of}\:\mathrm{CO}_{\mathrm{2}} \:\mathrm{and}\:\mathrm{H}_{\mathrm{2}} \mathrm{O} \\ $$$$\mathrm{are}\:\mathrm{393}.\mathrm{3}\:\mathrm{kJ}\:\mathrm{and}\:\mathrm{286}.\mathrm{2}\:\mathrm{kJ}\:\mathrm{respectively}. \\ $$$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{enthalpy}\:\mathrm{of}\:\mathrm{formation}\:\mathrm{of} \\ $$$$\mathrm{ethylene}. \\…
Question Number 23632 by ajfour last updated on 02/Nov/17 Commented by mrW1 last updated on 03/Nov/17 $$\alpha_{\mathrm{A}} =\frac{\mathrm{d}\omega_{\mathrm{A}} }{\mathrm{dt}}=\frac{\mathrm{d}\omega_{\mathrm{A}} }{\mathrm{d}\theta}×\frac{\mathrm{d}\theta}{\mathrm{dt}}=\frac{\mathrm{d}\omega_{\mathrm{A}} }{\mathrm{d}\theta}×\omega\neq\frac{\mathrm{d}\omega_{\mathrm{A}} }{\mathrm{d}\theta}×\omega_{\mathrm{A}} \\ $$ Commented…