Question Number 88235 by Rio Michael last updated on 09/Apr/20 $$\:\mathrm{find}\:\mathrm{a}\:\mathrm{maclaurine}\:\mathrm{series}\:\mathrm{solution}\:\mathrm{to}\:\mathrm{the}\:\mathrm{differential}\:\mathrm{equation} \\ $$$$\mathrm{up}\:\mathrm{to}\:\mathrm{the}\:\mathrm{term}\:\mathrm{in}\:{x}^{\mathrm{4}} . \\ $$$$\:\frac{{dy}}{{dx}}\:−\:{x}\:=\:{xy}\:\:\:\mathrm{if}\:\:{y}\:=\:\mathrm{1}\:\mathrm{when}\:{x}\:=\:\mathrm{0}. \\ $$ Commented by niroj last updated on 11/Apr/20…
Question Number 22692 by Sahib singh last updated on 22/Oct/17 Commented by Sahib singh last updated on 22/Oct/17 $${find}\:{hinge}\:{reaction}\:{at}\:{A} \\ $$$$\&\:{angular}\:{velocity}\:{of}\:{rod}. \\ $$ Answered by…
Question Number 22679 by Tinkutara last updated on 21/Oct/17 $$\mathrm{Maximum}\:\mathrm{covalency}\:\mathrm{of}\:\mathrm{nitrogen}\:\mathrm{is} \\ $$$$\mathrm{equal}\:\mathrm{to} \\ $$ Commented by math solver last updated on 21/Oct/17 $$\mathrm{4} \\ $$…
Question Number 22657 by *D¬ B£$T* last updated on 21/Oct/17 $${A}\:{real}\:{image}\:\mathrm{3}\:{times}\:{the}\:{size}\:{of}\:{the}\: \\ $$$${object}\:{formed}\:{by}\:{a}\:{concave}\:{mirror} \\ $$$${on}\:{a}\:{screen}.\:{later}\:{both}\:{the}\:{object}\: \\ $$$$\&\:{the}\:{screen}\:{are}\:{shifted}\:{untill}\:{the} \\ $$$${image}\:{formed}\:{is}\:\mathrm{6}\:{times}\:{the}\:{size} \\ $$$${of}\:{the}\:{object}.\:{if}\:{the}\:{distnce}\:{moved} \\ $$$${is}\:\mathrm{15}{cm}.\:{calculate}\:{the}\:{focal}\:{length} \\ $$$${of}\:{the}\:{mirror}.…
Question Number 22652 by Tinkutara last updated on 21/Oct/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{unordered}\:\mathrm{pairs} \\ $$$$\left\{{A},\:{B}\right\}\:\left(\mathrm{i}.\mathrm{e}.,\:\mathrm{the}\:\mathrm{pairs}\:\left\{{A},\:{B}\right\}\:\mathrm{and}\:\left\{{B},\:{A}\right\}\right. \\ $$$$\left.\mathrm{are}\:\mathrm{considered}\:\mathrm{to}\:\mathrm{be}\:\mathrm{the}\:\mathrm{same}\right)\:\mathrm{of} \\ $$$$\mathrm{subsets}\:\mathrm{of}\:\mathrm{an}\:{n}-\mathrm{element}\:\mathrm{set}\:{X}\:\mathrm{which} \\ $$$$\mathrm{satisfy}\:\mathrm{the}\:\mathrm{conditions}: \\ $$$$\left(\mathrm{a}\right)\:{A}\:\neq\:{B}; \\ $$$$\left(\mathrm{b}\right)\:{A}\:\cup\:{B}\:=\:{X} \\ $$$$\left[\mathrm{e}.\mathrm{g}.,\:\mathrm{if}\:{X}\:=\:\left\{{a},\:{b},\:{c},\:{d}\right\},\:\mathrm{then}\:\left\{\left\{{a},\:{b}\right\},\right.\right. \\…
Question Number 88169 by jagoll last updated on 08/Apr/20 $$\mathrm{find}\:\mathrm{Laplace}\:\mathrm{transform}\: \\ $$$$\mathrm{t}^{\mathrm{3}} .\:\mathrm{cos}\:\:\mathrm{4t} \\ $$ Commented by mathmax by abdo last updated on 08/Apr/20 $${L}\left({x}^{\mathrm{3}}…
Question Number 22624 by Tinkutara last updated on 21/Oct/17 $$\mathrm{A}\:\mathrm{uniform}\:\mathrm{chain}\:\mathrm{of}\:\mathrm{length}\:\mathrm{L}\:\mathrm{and}\:\mathrm{mass} \\ $$$$\mathrm{M}\:\mathrm{is}\:\mathrm{lying}\:\mathrm{on}\:\mathrm{a}\:\mathrm{smooth}\:\mathrm{table}\:\mathrm{and}\:\mathrm{one} \\ $$$$\mathrm{third}\:\mathrm{of}\:\mathrm{its}\:\mathrm{length}\:\mathrm{is}\:\mathrm{hanging}\:\mathrm{vertically} \\ $$$$\mathrm{down}\:\mathrm{over}\:\mathrm{the}\:\mathrm{edge}\:\mathrm{of}\:\mathrm{the}\:\mathrm{table}.\:\mathrm{If}\:\mathrm{g}\:\mathrm{is} \\ $$$$\mathrm{acceleration}\:\mathrm{due}\:\mathrm{to}\:\mathrm{gravity},\:\mathrm{calculate} \\ $$$$\mathrm{work}\:\mathrm{required}\:\mathrm{to}\:\mathrm{pull}\:\mathrm{the}\:\mathrm{hanging}\:\mathrm{part} \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{table}. \\ $$ Answered…
Question Number 153685 by roxceefocus last updated on 09/Sep/21 Commented by liberty last updated on 09/Sep/21 $${f}\left({x}\right)=\mathrm{2}{x}^{\mathrm{3}} +\mathrm{5}{x}^{\mathrm{2}} +\mathrm{7}{x}+\mathrm{11} \\ $$$${divided}\:{by}\:{x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{1} \\ $$$${By}\:{Horner} \\…
Question Number 22594 by Tinkutara last updated on 20/Oct/17 $$\Delta\mathrm{H}_{\mathrm{f}} ^{\mathrm{o}} \:\mathrm{of}\:\mathrm{water}\:\mathrm{is}\:−\mathrm{285}.\mathrm{8}\:\mathrm{kJ}\:\mathrm{mol}^{−\mathrm{1}} .\:\mathrm{If} \\ $$$$\mathrm{enthalpy}\:\mathrm{of}\:\mathrm{neutralization}\:\mathrm{of}\:\mathrm{monoacid} \\ $$$$\mathrm{strong}\:\mathrm{base}\:\mathrm{is}\:−\mathrm{57}.\mathrm{3}\:\mathrm{kJ}\:\mathrm{mol}^{−\mathrm{1}} ,\:\Delta\mathrm{H}_{\mathrm{f}} ^{\mathrm{o}} \:\mathrm{of} \\ $$$$\mathrm{OH}^{−} \:\mathrm{ion}\:\mathrm{will}\:\mathrm{be} \\ $$…
Question Number 22582 by Tinkutara last updated on 20/Oct/17 $$\mathrm{A}\:\mathrm{chain}\:\mathrm{consisting}\:\mathrm{of}\:\mathrm{5}\:\mathrm{links}\:\mathrm{each}\:\mathrm{of} \\ $$$$\mathrm{mass}\:\mathrm{0}.\mathrm{1}\:\mathrm{kg}\:\mathrm{is}\:\mathrm{lifted}\:\mathrm{vertically}\:\mathrm{with}\:\mathrm{a} \\ $$$$\mathrm{constant}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{2}\:\mathrm{m}/\mathrm{s}^{\mathrm{2}} .\:\mathrm{The} \\ $$$$\mathrm{force}\:\mathrm{of}\:\mathrm{interaction}\:\left(\mathrm{in}\:\mathrm{newton}\right)\:\mathrm{between} \\ $$$$\mathrm{the}\:\mathrm{top}\:\mathrm{link}\:\mathrm{and}\:\mathrm{the}\:\mathrm{link}\:\mathrm{immediately} \\ $$$$\mathrm{below}\:\mathrm{it}\:\mathrm{will}\:\mathrm{be}\:: \\ $$$$\mathrm{Take}\:{g}\:=\:\mathrm{10}\:\mathrm{m}/\mathrm{s}^{\mathrm{2}} . \\…