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Question Number 64702 by Tanmay chaudhury last updated on 20/Jul/19 Answered by Tanmay chaudhury last updated on 20/Jul/19 $${abstaining}={a}\:\:\:\:{voting}={v}\:\: \\ $$$${a}=\mathrm{1}+{v}=\mathrm{7} \\ $$$${a}=\mathrm{2}+{v}=\mathrm{6} \\ $$$$……
Question Number 64697 by Rio Michael last updated on 20/Jul/19 $${i}\:{need}\:{some}\:{help}\:{here}.\: \\ $$$$\:{An}\:{object}\:{of}\:{mass}\:\:\:{m}\:\:\:{falls}\:{from}\:{a}\:{height}\:\:{h}_{\mathrm{1}} \:{and}\:{rebound} \\ $$$${to}\:{a}\:{height}\:{of}\:{h}_{\mathrm{2}} .\:{write}\:{an}\:{expression}\:{for}\:{its}\:{momentum}. \\ $$ Answered by peter frank last updated…
Question Number 64676 by meme last updated on 20/Jul/19 $${z}^{\mathrm{4}} −\mathrm{12}{iz}−\mathrm{100}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 130169 by BHOOPENDRA last updated on 23/Jan/21 $$\frac{\mathrm{1}}{{s}}{log}\frac{\left({s}−\mathrm{2}\right)}{\left({s}−\mathrm{3}\right)}\:{find}\:{inverse}\:{laplace} \\ $$ Answered by Olaf last updated on 23/Jan/21 $$\mathrm{F}\left({s}\right)\:=\:\frac{\mathrm{1}}{{s}}\mathrm{ln}\frac{{s}−\mathrm{2}}{{s}−\mathrm{3}} \\ $$$$\mathrm{F}\left({s}\right)\:=\:\frac{{s}−\mathrm{2}}{{s}}.\frac{\mathrm{ln}\left({s}−\mathrm{2}\right)}{{s}−\mathrm{2}}−\frac{{s}−\mathrm{3}}{{s}}.\frac{\mathrm{ln}\left({s}−\mathrm{3}\right)}{{s}−\mathrm{3}} \\ $$$$\mathrm{F}\left({s}\right)\:=\:\left(\frac{\mathrm{2}}{{s}}−\mathrm{1}\right)\left\{−\frac{\mathrm{1}}{{s}−\mathrm{2}}\left[\mathrm{ln}\left({s}−\mathrm{2}\right)+\gamma\right]\right\} \\…
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Question Number 130073 by BHOOPENDRA last updated on 22/Jan/21 Commented by BHOOPENDRA last updated on 22/Jan/21 $${find}\:{laplace}\:{transformation}? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 64534 by smartsmith459@gmail.com last updated on 19/Jul/19 $${evalate}\:{y}=\:\mathrm{3}{e}^{\mathrm{4}{x}} \:−\:\frac{\mathrm{5}}{\mathrm{3}{e}^{\mathrm{3}{x}\:} }\:+\:\mathrm{4}{lin}\mathrm{2}{x}\:{at}\:\: \\ $$$${points}\:\left({a}\right)\:\left(\mathrm{0}\:\mathrm{4}\right)\:{and}\:\left(\mathrm{1}\:\mathrm{8}\right). \\ $$ Commented by MJS last updated on 19/Jul/19 $$\mathrm{question}\:\mathrm{not}\:\mathrm{clear} \\…
Question Number 64522 by necx1 last updated on 18/Jul/19 $${In}\:{a}\:{hospital},\:{Dr}\:{Steve}\:{has}\:{worked} \\ $$$${more}\:{night}\:{shifts}\:{than}\:{Dr}\:{Gregg}\:{who} \\ $$$${has}\:{worked}\:{five}\:{night}\:{shifts}.\:{Dr}\:{Okon} \\ $$$${has}\:{worked}\:\mathrm{15}\:{night}\:{shifts}\:{more}\:{than} \\ $$$${Dr}\:{Steve}\:{and}\:{Dr}\:{Gregg}\:{combined}. \\ $$$${Dr}.\:{Uche}\:{has}\:{worked}\:{eight}\:{night}\:{shifts} \\ $$$${less}\:{than}\:{Dr}\:{Steve}.{How}\:{many}\:{night} \\ $$$${shifts}\:{has}\:{Dr}.\:{Steve}\:{worked}? \\…
Question Number 64471 by mmkkmm000m last updated on 18/Jul/19 $$\int\sqrt[{\mathrm{4}}]{{tanx}}{dx} \\ $$ Answered by MJS last updated on 18/Jul/19 $$\int\sqrt[{\mathrm{4}}]{\mathrm{tan}\:{x}}{dx}= \\ $$$$\:\:\:\:\:\left[{t}=\sqrt[{\mathrm{4}}]{\mathrm{tan}\:{x}}\:\rightarrow\:{dx}=\mathrm{4}\sqrt[{\mathrm{4}}]{\mathrm{tan}^{\mathrm{3}} \:{x}}\:\mathrm{cos}^{\mathrm{2}} \:{x}\:{dt}\right] \\…