Question Number 22447 by Tinkutara last updated on 18/Oct/17 $$\mathrm{The}\:\mathrm{standard}\:\mathrm{heats}\:\mathrm{of}\:\mathrm{formation}\:\mathrm{of}\:\mathrm{at} \\ $$$$\mathrm{298}\:\mathrm{K}\:\mathrm{for}\:\mathrm{CCl}_{\mathrm{4}} \left(\mathrm{g}\right),\:\mathrm{H}_{\mathrm{2}} \mathrm{O}\left(\mathrm{g}\right),\:\mathrm{CO}_{\mathrm{2}} \left(\mathrm{g}\right)\:\mathrm{and} \\ $$$$\mathrm{HCl}\left(\mathrm{g}\right)\:\mathrm{are}\:−\mathrm{25}.\mathrm{5},\:−\mathrm{57}.\mathrm{8},\:−\mathrm{94}.\mathrm{1}\:\mathrm{and} \\ $$$$−\mathrm{22}.\mathrm{1}\:\mathrm{kcal}\:\mathrm{mol}^{−\mathrm{1}} \:\mathrm{respectively}.\:\mathrm{Calculate} \\ $$$$\Delta_{\mathrm{r}} \mathrm{H}^{\circleddash} \:\mathrm{for}\:\mathrm{the}\:\mathrm{reaction} \\…
Question Number 22446 by Tinkutara last updated on 18/Oct/17 $$\mathrm{Select}\:\mathrm{the}\:\mathrm{species}\:\mathrm{which}\:\mathrm{has}\:\mathrm{the}\:\mathrm{smallest} \\ $$$$\mathrm{radius}\:\mathrm{stating}\:\mathrm{appropriate}\:\mathrm{reason}. \\ $$$$\mathrm{K}^{+} ,\:\mathrm{Sr}^{\mathrm{2}+} ,\:\mathrm{Ar} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 22437 by Tinkutara last updated on 18/Oct/17 $$\mathrm{A}\:\mathrm{cubical}\:\mathrm{block}\:\mathrm{is}\:\mathrm{held}\:\mathrm{stationary} \\ $$$$\mathrm{against}\:\mathrm{a}\:\mathrm{rough}\:\mathrm{wall}\:\mathrm{by}\:\mathrm{applying}\:\mathrm{force} \\ $$$$'\mathrm{F}'\:\mathrm{then}\:\boldsymbol{{incorrect}}\:\mathrm{statement}\:\mathrm{among} \\ $$$$\mathrm{the}\:\mathrm{following}\:\mathrm{is} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{frictional}\:\mathrm{force},\:\mathrm{f}\:=\:\mathrm{Mg} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{f}\:=\:\mathrm{N},\:\mathrm{N}\:\mathrm{is}\:\mathrm{normal}\:\mathrm{reaction} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{F}\:\mathrm{does}\:\mathrm{not}\:\mathrm{apply}\:\mathrm{any}\:\mathrm{torque} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{N}\:\mathrm{does}\:\mathrm{not}\:\mathrm{apply}\:\mathrm{any}\:\mathrm{torque} \\…
Question Number 22395 by math solver last updated on 17/Oct/17 Commented by math solver last updated on 17/Oct/17 $${yup}!\:{but}\:{plz}\:{tell}\:{method}? \\ $$$$ \\ $$ Commented by…
Question Number 153464 by roxceefocus last updated on 07/Sep/21 Commented by roxceefocus last updated on 07/Sep/21 $${pls}\:{i}\:{need}\:{answers}\:{on}\:{this}\:{question} \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 22370 by Tinkutara last updated on 16/Oct/17 $$\mathrm{A}\:\mathrm{uniform}\:\mathrm{flexible}\:\mathrm{chain}\:\mathrm{of}\:\mathrm{length}\:\frac{\mathrm{3}}{\mathrm{2}}\:\mathrm{m} \\ $$$$\mathrm{rests}\:\mathrm{on}\:\mathrm{a}\:\mathrm{fixed}\:\mathrm{smooth}\:\mathrm{sphere}\:\mathrm{of} \\ $$$$\mathrm{radius}\:{R}\:=\:\frac{\mathrm{2}}{\pi}\:\mathrm{m}\:\mathrm{such}\:\mathrm{that}\:\mathrm{one}\:\mathrm{end}\:{A}\:\mathrm{of} \\ $$$$\mathrm{chain}\:\mathrm{is}\:\mathrm{on}\:\mathrm{the}\:\mathrm{top}\:\mathrm{of}\:\mathrm{the}\:\mathrm{sphere}\:\mathrm{while} \\ $$$$\mathrm{the}\:\mathrm{other}\:\mathrm{end}\:{B}\:\mathrm{is}\:\mathrm{hanging}\:\mathrm{freely}.\:\mathrm{Chain} \\ $$$$\mathrm{is}\:\mathrm{held}\:\mathrm{stationary}\:\mathrm{by}\:\mathrm{a}\:\mathrm{horizontal} \\ $$$$\mathrm{thread}\:{PA}.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{acceleration} \\ $$$$\mathrm{of}\:\mathrm{chain}\:\mathrm{when}\:\mathrm{the}\:\mathrm{horizontal}\:\mathrm{string}\:{PA} \\…
Question Number 22368 by Tinkutara last updated on 16/Oct/17 $$\mathrm{The}\:\mathrm{first}\:\mathrm{and}\:\mathrm{second}\:\mathrm{ionization} \\ $$$$\mathrm{potentials}\:\mathrm{of}\:\mathrm{helium}\:\mathrm{atoms}\:\mathrm{are}\:\mathrm{24}.\mathrm{58}\:\mathrm{eV} \\ $$$$\mathrm{and}\:\mathrm{54}.\mathrm{4}\:\mathrm{eV}\:\mathrm{per}\:\mathrm{mole}\:\mathrm{respectively}. \\ $$$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{energy}\:\mathrm{in}\:\mathrm{kJ}\:\mathrm{required}\:\mathrm{to} \\ $$$$\mathrm{produce}\:\mathrm{1}\:\mathrm{mole}\:\mathrm{of}\:\mathrm{He}^{\mathrm{2}+} \:\mathrm{ions}. \\ $$ Terms of Service Privacy…
Question Number 153438 by BHOOPENDRA last updated on 07/Sep/21 Commented by MJS_new last updated on 07/Sep/21 $$\mathrm{to}\:\mathrm{reach}\:\mathrm{maximum}\:\mathrm{height}\:\mathrm{putting}\:\mathrm{a}\:\mathrm{hemisphere} \\ $$$$\mathrm{on}\:\mathrm{one}\:\mathrm{with}\:{r}_{\mathrm{1}} =\mathrm{1}\:\mathrm{you}\:\mathrm{need}\:{r}_{\mathrm{2}} =\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}.\:\mathrm{this}\:\mathrm{should} \\ $$$$\mathrm{help}… \\ $$…
Question Number 87870 by Prithwish Sen 1 last updated on 06/Apr/20 $$\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{amd}}\:\boldsymbol{\mathrm{y}}\:\boldsymbol{\mathrm{are}}\:\boldsymbol{\mathrm{imtegers}}. \\ $$$$\boldsymbol{\mathrm{how}}\:\boldsymbol{\mathrm{many}}\:\boldsymbol{\mathrm{possible}}\:\boldsymbol{\mathrm{solitions}}\:\boldsymbol{\mathrm{do}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{eqiation}}\:\boldsymbol{\mathrm{has}} \\ $$$$\boldsymbol{\mathrm{x}}^{\mathrm{2}} −\mathrm{10}\boldsymbol{\mathrm{y}}^{\mathrm{2}} \:=\:\pm\mathrm{1} \\ $$ Terms of Service Privacy Policy…
Question Number 87862 by Rio Michael last updated on 06/Apr/20 $$\mathrm{Evaluate}\:\:\:\:\overset{\mathrm{1}} {\int}_{−\mathrm{1}} \frac{\mathrm{1}}{{x}−\mathrm{1}}\:{dx}\: \\ $$ Commented by MJS last updated on 06/Apr/20 $$\mathrm{doesn}'\mathrm{t}\:\mathrm{exist} \\ $$$$\int\frac{{dx}}{{x}−\mathrm{1}}=\mathrm{ln}\:\mid{x}−\mathrm{1}\mid\:+{C}…