Question Number 20411 by Tinkutara last updated on 26/Aug/17 $$\mathrm{A}\:\mathrm{stone}\:\mathrm{of}\:\mathrm{weight}\:{W}\:\mathrm{is}\:\mathrm{thrown}\:\mathrm{straight} \\ $$$$\mathrm{up}\:\mathrm{from}\:\mathrm{the}\:\mathrm{ground}\:\mathrm{with}\:\mathrm{an}\:\mathrm{initial} \\ $$$$\mathrm{speed}\:{u}.\:\mathrm{if}\:\mathrm{a}\:\mathrm{drag}\:\mathrm{force}\:\mathrm{of}\:\mathrm{constant} \\ $$$$\mathrm{magnitude}\:{f}\:\mathrm{acts}\:\mathrm{on}\:\mathrm{the}\:\mathrm{stone}\:\mathrm{through} \\ $$$$\mathrm{out}\:\mathrm{its}\:\mathrm{flight},\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{stone}\:\mathrm{just} \\ $$$$\mathrm{before}\:\mathrm{reaching}\:\mathrm{the}\:\mathrm{ground}\:\mathrm{is} \\ $$ Answered by ajfour…
Question Number 151468 by peter frank last updated on 21/Aug/21 $$\mathrm{z}^{\mathrm{2}} −\mathrm{7z}+\mathrm{16}=\mathrm{i}\left(\mathrm{z}−\mathrm{11}\right) \\ $$$$ \\ $$ Answered by peter frank last updated on 21/Aug/21 $$\mathrm{z}^{\mathrm{2}}…
Question Number 20375 by Tinkutara last updated on 26/Aug/17 $$\mathrm{A}\:\mathrm{small}\:\mathrm{particle}\:\mathrm{of}\:\mathrm{mass}\:{m}\:\mathrm{is}\:\mathrm{projected} \\ $$$$\mathrm{at}\:\mathrm{an}\:\mathrm{angle}\:\theta\:\mathrm{with}\:\mathrm{the}\:{x}-\mathrm{axis}\:\mathrm{with}\:\mathrm{an} \\ $$$$\mathrm{initial}\:\mathrm{velocity}\:{v}_{\mathrm{0}} \:\mathrm{in}\:\mathrm{the}\:{x}-{y}\:\mathrm{plane}\:\mathrm{as} \\ $$$$\mathrm{shown}\:\mathrm{in}\:\mathrm{the}\:\mathrm{Figure}.\:\mathrm{At}\:\mathrm{a}\:\mathrm{time} \\ $$$${t}\:<\:\frac{{v}_{\mathrm{0}} \:\mathrm{sin}\:\theta}{{g}},\:\mathrm{the}\:\mathrm{angular}\:\mathrm{momentum}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{particle}\:\mathrm{is} \\ $$ Commented…
Question Number 85888 by M±th+et£s last updated on 25/Mar/20 $${i}−\int_{\mathrm{0}} ^{\mathrm{5}} \left({x}+\left[\mathrm{2}{x}\right]\right)^{\left[\frac{{x}}{\mathrm{3}}\right]} {dx} \\ $$$$ \\ $$$${ii}−\int_{\mathrm{0}} ^{\mathrm{3}} \left({z}−\left\{{z}\right\}\right)^{\left[{z}\right]} \:{dz} \\ $$ Commented by abdomathmax…
Question Number 20346 by Tinkutara last updated on 25/Aug/17 $$\mathrm{To}\:\mathrm{paint}\:\mathrm{the}\:\mathrm{side}\:\mathrm{of}\:\mathrm{a}\:\mathrm{building},\:\mathrm{painter} \\ $$$$\mathrm{normally}\:\mathrm{hoists}\:\mathrm{himself}\:\mathrm{up}\:\mathrm{by}\:\mathrm{pulling}\:\mathrm{on} \\ $$$$\mathrm{the}\:\mathrm{rope}\:{A}\:\mathrm{as}\:\mathrm{in}\:\mathrm{figure}.\:\mathrm{The}\:\mathrm{painter}\:\mathrm{and} \\ $$$$\mathrm{platform}\:\mathrm{together}\:\mathrm{weigh}\:\mathrm{200}\:\mathrm{N}.\:\mathrm{The} \\ $$$$\mathrm{rope}\:{B}\:\mathrm{can}\:\mathrm{withstand}\:\mathrm{300}\:\mathrm{N}.\:\mathrm{Find}\:\mathrm{the} \\ $$$$\mathrm{maximum}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{the}\:\mathrm{painter}. \\ $$ Commented by Tinkutara…
Question Number 20349 by Tinkutara last updated on 25/Aug/17 $$\mathrm{A}\:\mathrm{ball}\:\mathrm{rolled}\:\mathrm{on}\:\mathrm{ice}\:\mathrm{with}\:\mathrm{a}\:\mathrm{velocity}\:\mathrm{of} \\ $$$$\mathrm{14}\:\mathrm{ms}^{−\mathrm{1}} \:\mathrm{comes}\:\mathrm{to}\:\mathrm{rest}\:\mathrm{after}\:\mathrm{travelling} \\ $$$$\mathrm{40}\:\mathrm{m}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{friction}. \\ $$$$\left(\mathrm{Given},\:{g}\:=\:\mathrm{9}.\mathrm{8}\:\mathrm{m}/\mathrm{s}^{\mathrm{2}} \right) \\ $$ Commented by Tinkutara last updated…
Question Number 20344 by Tinkutara last updated on 25/Aug/17 $$\mathrm{Determine}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{with}\:\mathrm{which}\:\mathrm{block} \\ $$$${B}\:\mathrm{rises}\:\mathrm{in}\:\mathrm{figure}\:\mathrm{if}\:\mathrm{the}\:\mathrm{end}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cord}\:\mathrm{at} \\ $$$${A}\:\mathrm{is}\:\mathrm{pulled}\:\mathrm{down}\:\mathrm{with}\:\mathrm{a}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{2}\:\mathrm{m}/\mathrm{s}. \\ $$ Commented by Tinkutara last updated on 25/Aug/17 Commented by…
Question Number 85872 by Wepa last updated on 25/Mar/20 $$\int\mathrm{cos}^{\mathrm{2020}} \mathrm{x}\:\mathrm{dx}\:=\:? \\ $$ Commented by mr W last updated on 25/Mar/20 $${I}_{{n}} =\int\mathrm{cos}^{{n}} \:{x}\:{dx} \\…
Question Number 20338 by Tinkutara last updated on 25/Aug/17 $$\mathrm{Why}\:\mathrm{Al}_{\mathrm{2}} \mathrm{O}_{\mathrm{3}} \:\mathrm{is}\:\mathrm{amphoteric}\:\mathrm{while}\:\mathrm{B}_{\mathrm{2}} \mathrm{O}_{\mathrm{3}} \\ $$$$\mathrm{is}\:\mathrm{acidic}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 20335 by Tinkutara last updated on 25/Aug/17 $$\mathrm{Covalent}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{an}\:\mathrm{element}\:\mathrm{having} \\ $$$$\mathrm{82}\:\mathrm{electrons}\:\mathrm{in}\:\mathrm{extranuclear}\:\mathrm{part}\:\mathrm{and}\:\mathrm{82} \\ $$$$\mathrm{protons}\:\mathrm{in}\:\mathrm{the}\:\mathrm{nucleus}\:\mathrm{is}\:\mathrm{146}\:\overset{\mathrm{o}} {\mathrm{A}}.\:\mathrm{Calculate} \\ $$$$\mathrm{the}\:\mathrm{electronegativity}\:\mathrm{on}\:\mathrm{Allred}\:\mathrm{Rochow} \\ $$$$\mathrm{scale}\:\mathrm{of}\:\mathrm{that}\:\mathrm{element}. \\ $$ Terms of Service Privacy…