Question Number 64534 by smartsmith459@gmail.com last updated on 19/Jul/19 $${evalate}\:{y}=\:\mathrm{3}{e}^{\mathrm{4}{x}} \:−\:\frac{\mathrm{5}}{\mathrm{3}{e}^{\mathrm{3}{x}\:} }\:+\:\mathrm{4}{lin}\mathrm{2}{x}\:{at}\:\: \\ $$$${points}\:\left({a}\right)\:\left(\mathrm{0}\:\mathrm{4}\right)\:{and}\:\left(\mathrm{1}\:\mathrm{8}\right). \\ $$ Commented by MJS last updated on 19/Jul/19 $$\mathrm{question}\:\mathrm{not}\:\mathrm{clear} \\…
Question Number 64522 by necx1 last updated on 18/Jul/19 $${In}\:{a}\:{hospital},\:{Dr}\:{Steve}\:{has}\:{worked} \\ $$$${more}\:{night}\:{shifts}\:{than}\:{Dr}\:{Gregg}\:{who} \\ $$$${has}\:{worked}\:{five}\:{night}\:{shifts}.\:{Dr}\:{Okon} \\ $$$${has}\:{worked}\:\mathrm{15}\:{night}\:{shifts}\:{more}\:{than} \\ $$$${Dr}\:{Steve}\:{and}\:{Dr}\:{Gregg}\:{combined}. \\ $$$${Dr}.\:{Uche}\:{has}\:{worked}\:{eight}\:{night}\:{shifts} \\ $$$${less}\:{than}\:{Dr}\:{Steve}.{How}\:{many}\:{night} \\ $$$${shifts}\:{has}\:{Dr}.\:{Steve}\:{worked}? \\…
Question Number 64471 by mmkkmm000m last updated on 18/Jul/19 $$\int\sqrt[{\mathrm{4}}]{{tanx}}{dx} \\ $$ Answered by MJS last updated on 18/Jul/19 $$\int\sqrt[{\mathrm{4}}]{\mathrm{tan}\:{x}}{dx}= \\ $$$$\:\:\:\:\:\left[{t}=\sqrt[{\mathrm{4}}]{\mathrm{tan}\:{x}}\:\rightarrow\:{dx}=\mathrm{4}\sqrt[{\mathrm{4}}]{\mathrm{tan}^{\mathrm{3}} \:{x}}\:\mathrm{cos}^{\mathrm{2}} \:{x}\:{dt}\right] \\…
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Question Number 129985 by Dwaipayan Shikari last updated on 21/Jan/21 $$\overset{\bullet\bullet} {\theta}\left({t}\right)−\frac{\gamma}{{ml}}\overset{\bullet} {\theta}\left({t}\right)+\frac{{g}}{{l}}{sin}\theta\left({t}\right)=\mathrm{0} \\ $$ Answered by Olaf last updated on 21/Jan/21 $$\overset{\bullet\bullet} {\theta}−\frac{\gamma}{{ml}}\overset{\bullet} {\theta}+\frac{{g}}{{l}}\mathrm{sin}\theta\:=\:\mathrm{0}\:\left(\mathrm{1}\right)…
Question Number 64397 by rachelleazarcon last updated on 17/Jul/19 $$\frac{\mathrm{7}}{\mathrm{4x}−\mathrm{1}}−\frac{\mathrm{5}}{\mathrm{4x}−\mathrm{1}} \\ $$ Answered by MJS last updated on 17/Jul/19 $$\mathrm{again},\:\mathrm{seriously}? \\ $$$$\frac{{a}}{{b}}+\frac{{c}}{{b}}=\frac{{a}+{c}}{{b}} \\ $$$$\frac{{a}}{{b}}−\frac{{c}}{{b}}=\frac{{a}−{c}}{{b}} \\…
Question Number 64396 by rachelleazarcon last updated on 17/Jul/19 $$\left(\mathrm{x}+\mathrm{2}\right)\left(\mathrm{x}−\mathrm{2}\right) \\ $$ Answered by MJS last updated on 17/Jul/19 $$\mathrm{are}\:\mathrm{you}\:\mathrm{serious}? \\ $$$$\mathrm{study}\:\mathrm{these}\:\mathrm{formulas} \\ $$$$\left({a}+{b}\right)^{\mathrm{2}} ={a}^{\mathrm{2}}…
Question Number 64391 by rachelleazarcon last updated on 17/Jul/19 $$\frac{\mathrm{6}}{\mathrm{a}+\mathrm{5}}+\frac{\mathrm{4}}{\mathrm{a}+\mathrm{5}} \\ $$ Commented by mathmax by abdo last updated on 17/Jul/19 $$=\frac{\mathrm{6}+\mathrm{4}}{{a}+\mathrm{5}}\:=\frac{\mathrm{10}}{{a}+\mathrm{5}} \\ $$ Terms…
Question Number 64381 by ketto2 last updated on 17/Jul/19 Commented by MJS last updated on 17/Jul/19 $$\frac{\mathrm{drawing}}{\mathrm{reality}}=\frac{\mathrm{5}{cm}}{\mathrm{250}{m}}=\frac{\mathrm{5}}{\mathrm{250}}×\frac{{cm}}{{m}}=\frac{\mathrm{1}}{\mathrm{50}}×\frac{\mathrm{1}}{\mathrm{100}}=\frac{\mathrm{1}}{\mathrm{5000}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 64356 by udu last updated on 17/Jul/19 $$ \\ $$ Answered by MJS last updated on 17/Jul/19 $$\mathrm{42} \\ $$ Terms of Service…