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A-river-of-width-d-is-flowing-with-speed-u-as-shown-in-the-figure-John-can-swim-with-maximum-speed-v-relative-to-the-river-and-can-cross-it-in-shortest-time-T-John-starts-at-A-B-is-the-point-direct

Question Number 19200 by Tinkutara last updated on 06/Aug/17 $$\mathrm{A}\:\mathrm{river}\:\mathrm{of}\:\mathrm{width}\:{d}\:\mathrm{is}\:\mathrm{flowing}\:\mathrm{with}\:\mathrm{speed} \\ $$$${u}\:\mathrm{as}\:\mathrm{shown}\:\mathrm{in}\:\mathrm{the}\:\mathrm{figure}.\:\mathrm{John}\:\mathrm{can}\:\mathrm{swim} \\ $$$$\mathrm{with}\:\mathrm{maximum}\:\mathrm{speed}\:{v}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{river}\:\mathrm{and}\:\mathrm{can}\:\mathrm{cross}\:\mathrm{it}\:\mathrm{in}\:\mathrm{shortest}\:\mathrm{time} \\ $$$${T}.\:\mathrm{John}\:\mathrm{starts}\:\mathrm{at}\:{A}.\:{B}\:\mathrm{is}\:\mathrm{the}\:\mathrm{point} \\ $$$$\mathrm{directly}\:\mathrm{opposite}\:\mathrm{to}\:{A}\:\mathrm{on}\:\mathrm{the}\:\mathrm{other} \\ $$$$\mathrm{bank}\:\mathrm{of}\:\mathrm{the}\:\mathrm{river}.\:\mathrm{If}\:{t}\:\mathrm{be}\:\mathrm{the}\:\mathrm{time}\:\mathrm{John} \\ $$$$\mathrm{takes}\:\mathrm{to}\:\mathrm{reach}\:\mathrm{the}\:\mathrm{opposite}\:\mathrm{bank},\:\mathrm{match} \\…

Question-150228

Question Number 150228 by learner001 last updated on 10/Aug/21 Commented by learner001 last updated on 10/Aug/21 $$\mathrm{please}\:\mathrm{someone}\:\mathrm{explain}\:\mathrm{how}\:\mathrm{the}\:\mathrm{inequality}\:\mathrm{sign} \\ $$$$\mathrm{is}\:\mathrm{reserved}?\:\mathrm{after}\:\mathrm{ther}\:\mathrm{multiplied}\:\mathrm{through}\:\mathrm{by}\:\mathrm{a} \\ $$$$\mathrm{negative}. \\ $$ Terms of…

Two-particles-A-and-B-move-with-constant-velocities-v-1-and-v-2-along-two-mutually-perpendicular-straight-lines-towards-the-intersection-point-O-At-moment-t-0-the-particles-were-located-at-dista

Question Number 19167 by Tinkutara last updated on 06/Aug/17 $$\mathrm{Two}\:\mathrm{particles}\:{A}\:\mathrm{and}\:{B}\:\mathrm{move}\:\mathrm{with} \\ $$$$\mathrm{constant}\:\mathrm{velocities}\:{v}_{\mathrm{1}} \:\mathrm{and}\:{v}_{\mathrm{2}} \:\mathrm{along}\:\mathrm{two} \\ $$$$\mathrm{mutually}\:\mathrm{perpendicular}\:\mathrm{straight}\:\mathrm{lines} \\ $$$$\mathrm{towards}\:\mathrm{the}\:\mathrm{intersection}\:\mathrm{point}\:{O}.\:\mathrm{At} \\ $$$$\mathrm{moment}\:{t}\:=\:\mathrm{0},\:\mathrm{the}\:\mathrm{particles}\:\mathrm{were} \\ $$$$\mathrm{located}\:\mathrm{at}\:\mathrm{distances}\:{d}_{\mathrm{1}} \:\mathrm{and}\:{d}_{\mathrm{2}} \:\mathrm{from}\:{O} \\…

show-that-0-1-0-1-0-1-log-xyz-1-x-2-1-y-2-1-z-2-dx-dy-dz-3pi-2-G-16-

Question Number 84680 by M±th+et£s last updated on 15/Mar/20 $${show}\:{that} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \int_{\mathrm{0}} ^{\mathrm{1}} \int_{\mathrm{0}} ^{\mathrm{1}} \frac{{log}\left({xyz}\right)}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\left(\mathrm{1}+{y}^{\mathrm{2}} \right)\left(\mathrm{1}+{z}^{\mathrm{2}} \right)}\:{dx}\:{dy}\:{dz}=\frac{−\mathrm{3}\pi^{\mathrm{2}} {G}}{\mathrm{16}} \\ $$ Answered…

A-racing-car-travels-on-a-track-without-banking-ABCDEFA-ABC-is-a-circular-arc-of-radius-2R-CD-and-FA-are-straight-paths-of-length-R-and-DEF-is-a-circular-arc-of-radius-R-100-m-The-co-efficient-

Question Number 19140 by Tinkutara last updated on 05/Aug/17 $$\mathrm{A}\:\mathrm{racing}\:\mathrm{car}\:\mathrm{travels}\:\mathrm{on}\:\mathrm{a}\:\mathrm{track}\:\left(\mathrm{without}\right. \\ $$$$\left.\mathrm{banking}\right)\:{ABCDEFA}.\:{ABC}\:\mathrm{is}\:\mathrm{a}\:\mathrm{circular} \\ $$$$\mathrm{arc}\:\mathrm{of}\:\mathrm{radius}\:\mathrm{2}{R}.\:{CD}\:\mathrm{and}\:{FA}\:\mathrm{are} \\ $$$$\mathrm{straight}\:\mathrm{paths}\:\mathrm{of}\:\mathrm{length}\:{R}\:\mathrm{and}\:{DEF}\:\mathrm{is} \\ $$$$\mathrm{a}\:\mathrm{circular}\:\mathrm{arc}\:\mathrm{of}\:\mathrm{radius}\:{R}\:=\:\mathrm{100}\:\mathrm{m}.\:\mathrm{The} \\ $$$$\mathrm{co}-\mathrm{efficient}\:\mathrm{of}\:\mathrm{friction}\:\mathrm{on}\:\mathrm{the}\:\mathrm{road}\:\mathrm{is}\:\mu\:= \\ $$$$\mathrm{0}.\mathrm{1}.\:\mathrm{The}\:\mathrm{maximum}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{car}\:\mathrm{is} \\ $$$$\mathrm{50}\:\mathrm{ms}^{−\mathrm{1}} .\:\mathrm{Find}\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{time}\:\mathrm{for}…

Figure-shows-x-t-y-t-diagram-of-a-particle-moving-in-2-dimensions-If-the-particle-has-a-mass-of-500-g-find-the-force-direction-and-magnitude-acting-on-the-particle-

Question Number 19137 by Tinkutara last updated on 05/Aug/17 $$\mathrm{Figure}\:\mathrm{shows}\:\left({x},\:{t}\right),\:\left({y},\:{t}\right)\:\mathrm{diagram}\:\mathrm{of}\:\mathrm{a} \\ $$$$\mathrm{particle}\:\mathrm{moving}\:\mathrm{in}\:\mathrm{2}-\mathrm{dimensions}.\:\mathrm{If}\:\mathrm{the} \\ $$$$\mathrm{particle}\:\mathrm{has}\:\mathrm{a}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{500}\:\mathrm{g},\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{force}\:\left(\mathrm{direction}\:\mathrm{and}\:\mathrm{magnitude}\right)\:\mathrm{acting} \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{particle}. \\ $$ Commented by Tinkutara last updated…

prove-that-lim-x-1-1-x-x-e-

Question Number 84637 by Rio Michael last updated on 14/Mar/20 $$\mathrm{prove}\:\mathrm{that}\:\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\left(\mathrm{1}\:+\:\frac{\mathrm{1}}{{x}}\right)^{{x}} \:={e} \\ $$ Commented by ajfour last updated on 14/Mar/20 $${prove}\:{that}\:\:\mathrm{sin}\:\theta=\frac{{p}}{{h}}\:. \\ $$…

Question-150156

Question Number 150156 by Lekhraj last updated on 09/Aug/21 Answered by Ar Brandon last updated on 10/Aug/21 $${u}_{{n}} =−\mathrm{4},\:\mathrm{1},\:\mathrm{12},\:\mathrm{29},\:\mathrm{52},\:\mathrm{81},\:\mathrm{116},…\:{u}_{\mathrm{1}} =−\mathrm{4} \\ $$$$\Delta{u}_{{n}} =\mathrm{5},\:\mathrm{11},\:\mathrm{17},\:\mathrm{23},\:\mathrm{29},…\:\:{d}_{\mathrm{1}} =\mathrm{5} \\…