Question Number 63983 by Rio Michael last updated on 11/Jul/19 $${Please}\:{i}\:{need}\:{someones}\:{help}\:{on}\:{this}\: \\ $$$${How}\:{do}\:{i}\:{find}\:{an}\:{Asymptote}\:{to}\:{a}\:{curve}? \\ $$$${and}\:{also}\:{how}\:{find}\:{a}\:{general}\:{solution}\:{for}\:{a}\:{differential}\: \\ $$$${equation}. \\ $$$$ \\ $$ Answered by MJS last…
Question Number 63984 by Rio Michael last updated on 11/Jul/19 $${is}\:{it}\:{true}? \\ $$$$\:\:{e}^{{lnx}} =\:{x}? \\ $$$${if}\:{so}\:{then}\:\:\frac{{d}}{{dx}}\left({e}^{{lnx}} \right)=? \\ $$ Commented by mathmax by abdo last…
Question Number 129516 by greg_ed last updated on 16/Jan/21 $$\boldsymbol{\mathrm{Why}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{it}}\:\boldsymbol{\mathrm{so}}\:\boldsymbol{\mathrm{impossible}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{update}}\:\boldsymbol{\mathrm{directly}}\:\boldsymbol{\mathrm{instead}} \\ $$$$\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{reinstalling}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{whole}}\:\boldsymbol{\mathrm{app}}\:?!? \\ $$$$\boldsymbol{\mathrm{please}},\:\boldsymbol{\mathrm{fix}}\:\boldsymbol{\mathrm{it}}\:! \\ $$ Commented by mr W last updated on 16/Jan/21 $${i}\:{can}\:{update}\:{the}\:{app}\:{directly}\:{without}…
Question Number 129514 by abdurehime last updated on 16/Jan/21 $$\mathrm{The}\:\mathrm{polynomial}\:\mathrm{p}\left(\mathrm{x}\right)\mathrm{is}\:\mathrm{divided}\:\mathrm{by}\:\mathrm{x}−\mathrm{4}\:\mathrm{and}\:\mathrm{x}+\mathrm{2}\:\mathrm{the}\:\mathrm{remainders}\:\mathrm{are}\:\mathrm{8}\:\mathrm{and}\:\mathrm{4}\:\mathrm{respectivily}.\:\mathrm{find}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{when}\:\mathrm{p}\left(\mathrm{x}\right)\mathrm{is}\:\mathrm{divided}\:\mathrm{by}\:\left(\mathrm{x}−\mathrm{4}\right)\left(\mathrm{x}+\mathrm{2}\right) \\ $$$$ \\ $$ Commented by mr W last updated on 16/Jan/21 $${please}\:{don}'{t}\:{write}\:{the}\:{whole}\:{post}\:{in} \\ $$$${a}\:{single}\:{line}!\:{try}\:{to}\:{use}\:{line}\:{breack}!…
Question Number 63891 by Tawa1 last updated on 10/Jul/19 $$\mathrm{A}\:\mathrm{bus}\:\mathrm{is}\:\mathrm{travelling}\:\mathrm{along}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{road}\:\mathrm{at}\:\mathrm{100Km}/\mathrm{hr}\:\mathrm{and} \\ $$$$\mathrm{the}\:\mathrm{bus}\:\mathrm{conductor}\:\mathrm{walks}\:\mathrm{at}\:\mathrm{6Km}/\mathrm{hr}\:\mathrm{on}\:\mathrm{the}\:\mathrm{floor}\:\mathrm{of}\:\mathrm{the}\:\mathrm{bus} \\ $$$$\mathrm{and}\:\mathrm{in}\:\mathrm{the}\:\mathrm{same}\:\mathrm{direction}\:\mathrm{as}\:\mathrm{the}\:\mathrm{bus}.\: \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{conductor}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{road},\:\mathrm{and} \\ $$$$\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{bus}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{bus}\:\mathrm{conductor}\:\mathrm{now}\:\mathrm{works}\:\mathrm{at}\:\mathrm{the}\:\mathrm{same} \\ $$$$\mathrm{rate}\:\mathrm{but}\:\mathrm{in}\:\mathrm{the}\:\mathrm{opposite}\:\mathrm{direction}\:\mathrm{as}\:\mathrm{the}\:\mathrm{bus},\:\mathrm{find}\:\mathrm{his}\:\mathrm{new}\:\mathrm{speed} \\ $$$$\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{road}. \\ $$$$\mathrm{Answers}\:\mathrm{in}\:\mathrm{textbook}:\:\:\:\:\mathrm{106Km}/\mathrm{hr},\:\:\:\:\mathrm{64Km}/\mathrm{hr},\:\:\:\:\:\mathrm{94Km}/\mathrm{hr} \\…
Question Number 129378 by BHOOPENDRA last updated on 15/Jan/21 Answered by Dwaipayan Shikari last updated on 15/Jan/21 $$\mathscr{L}\left({ut}^{\mathrm{2}} {e}^{−\mathrm{2}{t}} −{ute}^{−\mathrm{2}{t}} \right)={u}\int_{\mathrm{0}} ^{\infty} {t}^{\mathrm{2}} {e}^{−\left({s}+\mathrm{2}\right){t}} −{u}\int_{\mathrm{0}}…
Question Number 129376 by Dwaipayan Shikari last updated on 15/Jan/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} {e}^{−{x}^{\mathrm{2}} } {dx}=\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{3}^{\mathrm{2}} }{\mathrm{7}+\frac{\mathrm{10}^{\mathrm{2}} }{\mathrm{32}+\frac{\mathrm{42}^{\mathrm{2}} }{\mathrm{174}+\frac{\mathrm{216}^{\mathrm{2}} }{\mathrm{1196}+\frac{\mathrm{1312}^{\mathrm{2}} }{….}}}}}}} \\ $$ Commented by Dwaipayan…
Question Number 129367 by BHOOPENDRA last updated on 15/Jan/21 Commented by BHOOPENDRA last updated on 15/Jan/21 $${using}\:{unit}\:{step}\:{function}\:{find}\:{laplace}\:{transform} \\ $$ Answered by mathmax by abdo last…
Question Number 63812 by kaivan.ahmadi last updated on 09/Jul/19 $$ \\ $$$${A}\:\:{can}\:{terminate}\:{a}\:{work}\:\:\mathrm{9}\:{hour}\:{earlier} \\ $$$${than}\:{B}. \\ $$$${A}\:\:{and}\:\:{B}\:\:{terminate}\:{that}\:{work}\:\:{after}\:\mathrm{20}\:{hour}\:{together}. \\ $$$${A}\:{can}\:{terminate}\:{that}\:{work}\:{after}\:….\:{hour}. \\ $$$$ \\ $$$$ \\ $$ Commented…
Question Number 129345 by BHOOPENDRA last updated on 15/Jan/21 $$\frac{\mathrm{1}}{\left({s}^{\mathrm{2}} +\mathrm{2}{s}+\mathrm{5}\right)^{\mathrm{2}} }\:{find}\:{inverse}\:{laplace} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com