Question Number 18749 by Tinkutara last updated on 29/Jul/17 $$\mathrm{Motion}\:\mathrm{in}\:\mathrm{two}\:\mathrm{dimensions},\:\mathrm{in}\:\mathrm{a}\:\mathrm{plane} \\ $$$$\mathrm{can}\:\mathrm{be}\:\mathrm{studied}\:\mathrm{by}\:\mathrm{expressing}\:\mathrm{position}, \\ $$$$\mathrm{velocity}\:\mathrm{and}\:\mathrm{acceleration}\:\mathrm{as}\:\mathrm{vectors}\:\mathrm{in} \\ $$$$\mathrm{Cartesian}\:\mathrm{co}-\mathrm{ordinates}\:\overset{\rightarrow} {{A}}\:=\:{A}_{{x}} \overset{\wedge} {{i}}\:+\:{A}_{{y}} \overset{\wedge} {{j}} \\ $$$$\mathrm{where}\:\overset{\wedge} {{i}}\:\mathrm{and}\:\overset{\wedge} {{j}}\:\mathrm{are}\:\mathrm{unit}\:\mathrm{vector}\:\mathrm{along}\:{x}…
Question Number 84263 by Rio Michael last updated on 10/Mar/20 $$\mathrm{Using}\:\mathrm{the}\:\mathrm{approximation} \\ $$$$\:{h}\left(\frac{{dy}}{{dx}}\right)_{{n}} \:\approx\:{y}_{{n}+\mathrm{1}} −{y}_{{n}} \:\mathrm{and}\:\mathrm{that}\:\frac{{dy}}{{dx}}\:=\:\mathrm{1},\:{y}\:=\mathrm{2} \\ $$$$\mathrm{when}\:{x}\:=\:\mathrm{0}\:.\:\mathrm{then}\:,\:{y}_{\mathrm{1}} \:= \\ $$$$\left[\mathrm{A}\right]\:{h}−\mathrm{2} \\ $$$$\left[\mathrm{B}\right]\:{h}\:+\:\mathrm{2} \\ $$$$\left[\mathrm{C}\right]\:{h}−\mathrm{1}…
Question Number 84242 by Rio Michael last updated on 10/Mar/20 $$\underset{\mathrm{0}} {\overset{\mathrm{ln2}} {\int}}\frac{\mathrm{1}}{\mathrm{cosh}\left({x}\:+\:\mathrm{ln4}\right)}{dx} \\ $$ Commented by mathmax by abdo last updated on 10/Mar/20 $${I}\:=\int_{\mathrm{0}}…
Question Number 84231 by Rio Michael last updated on 10/Mar/20 $$\mathrm{A}\:\mathrm{compound}\:\mathrm{pendulum}\:\mathrm{oscillates}\:\mathrm{though}\:\mathrm{a} \\ $$$$\mathrm{small}\:\mathrm{angle}\:\theta\:\mathrm{about}\:\mathrm{its}\:\mathrm{equilibrium}\:\mathrm{position} \\ $$$$\mathrm{such}\:\mathrm{that} \\ $$$$\:\:\:\mathrm{10}{a}\left(\frac{{d}\theta}{{dt}}\right)^{\mathrm{2}} \:=\:\mathrm{4}{g}\:\mathrm{cos}\:\theta\:,\:{a}\:>\mathrm{0}\:.\:\mathrm{its}\:\mathrm{period}\:\mathrm{is}\: \\ $$$$\left[\mathrm{A}\right]\:\mathrm{2}\pi\sqrt{\frac{\mathrm{5}{a}}{\mathrm{4}{g}}\:\:}\:\:\:\left[\mathrm{B}\right]\:\frac{\mathrm{2}\pi}{\mathrm{5}}\sqrt{\frac{{a}}{{g}}}\:\:\left[\mathrm{C}\right]\:\mathrm{2}\pi\sqrt{\frac{\mathrm{2}{g}}{\mathrm{5}{a}}\:}\:\:\left[\mathrm{D}\right]\:\mathrm{2}\pi\sqrt{\frac{\mathrm{5}{a}}{{g}}}\: \\ $$ Answered by TANMAY…
Question Number 84218 by Rio Michael last updated on 10/Mar/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{the}\:\mathrm{planes} \\ $$$$\:\mathrm{2}\boldsymbol{{x}}−\boldsymbol{{y}}−\boldsymbol{{z}}\:=\:\mathrm{24}\:\mathrm{and}\:\mathrm{2}\boldsymbol{{x}}−\boldsymbol{{y}}−\boldsymbol{{z}}\:=\:\mathrm{36} \\ $$ Commented by M±th+et£s last updated on 10/Mar/20 $$\mathrm{2}{x}−{y}−{z}=\mathrm{24}\Rightarrow\Rightarrow\mathrm{2}{x}−{y}−{z}−\mathrm{24}=\mathrm{0} \\ $$$$\mathrm{2}{x}−{y}−{z}=\mathrm{36}\Rightarrow\Rightarrow\mathrm{2}{x}−{y}−{z}−\mathrm{36}=\mathrm{0}…
Question Number 84220 by Rio Michael last updated on 10/Mar/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{value}\:\mathrm{of}\:\frac{\mathrm{2}}{\mathrm{3cosh2}{x}\:+\mathrm{2}} \\ $$ Commented by mr W last updated on 10/Mar/20 $$\mathrm{cosh}\:\mathrm{2}{x}\:\geqslant\mathrm{1} \\ $$$$\mathrm{3}\:\mathrm{cosh}\:\mathrm{2}{x}+\mathrm{2}\:\geqslant\mathrm{3}×\mathrm{1}+\mathrm{2}=\mathrm{5} \\…
Question Number 84219 by Rio Michael last updated on 10/Mar/20 $$\int_{−\mathrm{1}} ^{\mathrm{1}} {e}^{\mid{x}\mid} {dx}\:=? \\ $$ Answered by TANMAY PANACEA last updated on 10/Mar/20 $$\int_{−\mathrm{1}}…
Question Number 84215 by mathocean1 last updated on 10/Mar/20 $${hi} \\ $$$${show}\:{that}\:{the}\:{following}\:{sequence} \\ $$$${is}\:{limited}: \\ $$$${U}_{{n}} =\frac{\mathrm{3}{n}+\mathrm{2}}{\mathrm{2}{n}+\mathrm{1}} \\ $$$${precise}\:{the}\:{upper}\:{and}\:{lower}. \\ $$ Answered by Rio Michael…
Question Number 18666 by tawa tawa last updated on 26/Jul/17 $$\mathrm{An}\:\mathrm{elastic}\:\mathrm{material}\:\mathrm{has}\:\mathrm{a}\:\mathrm{length}\:\mathrm{of}\:\:\mathrm{36cm}\:\mathrm{when}\:\mathrm{a}\:\mathrm{load}\:\mathrm{of}\:\mathrm{40N}\:\mathrm{is}\:\mathrm{hung}\:\mathrm{on}\:\mathrm{it}\:\mathrm{and} \\ $$$$\mathrm{a}\:\mathrm{length}\:\mathrm{of}\:\mathrm{45cm}\:\mathrm{when}\:\mathrm{a}\:\mathrm{load}\:\mathrm{of}\:\mathrm{60N}\:\mathrm{is}\:\mathrm{hung}\:\mathrm{on}\:\mathrm{it}.\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{Original}\: \\ $$$$\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{string}\:? \\ $$ Answered by mrW1 last updated on 27/Jul/17 $$\mathrm{36}−\frac{\mathrm{45}−\mathrm{36}}{\mathrm{60}−\mathrm{40}}×\mathrm{40}=\mathrm{18}\:\mathrm{cm}…
Question Number 18645 by tawa tawa last updated on 26/Jul/17 Terms of Service Privacy Policy Contact: info@tinkutara.com