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A-pendulum-bob-of-mass-2kg-is-attached-to-a-string-2m-long-and-made-to-revolve-in-horizontal-circle-of-radius-0-8-find-the-tension-in-the-string-

Question Number 17995 by tawa tawa last updated on 13/Jul/17 $$\mathrm{A}\:\mathrm{pendulum}\:\mathrm{bob}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{2kg}\:\mathrm{is}\:\mathrm{attached}\:\mathrm{to}\:\mathrm{a}\:\mathrm{string}\:\:\mathrm{2m}\:\mathrm{long}\:\mathrm{and}\:\mathrm{made}\:\mathrm{to} \\ $$$$\mathrm{revolve}\:\mathrm{in}\:\mathrm{horizontal}\:\mathrm{circle}\:\mathrm{of}\:\mathrm{radius}\:\mathrm{0}.\mathrm{8}\:,\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{tension}\:\mathrm{in}\:\mathrm{the}\:\mathrm{string}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

A-driver-is-5-2-below-the-surface-of-water-of-density-1000kg-m-if-the-atmospheric-pressure-is-1-02-10-5-Pa-calculate-the-pressure-on-the-driver-

Question Number 17976 by tawa tawa last updated on 13/Jul/17 $$\mathrm{A}\:\mathrm{driver}\:\mathrm{is}\:\mathrm{5}.\mathrm{2}\:\mathrm{below}\:\mathrm{the}\:\mathrm{surface}\:\mathrm{of}\:\mathrm{water}\:\mathrm{of}\:\mathrm{density}\:\mathrm{1000kg}/\mathrm{m}.\:\:\mathrm{if}\:\mathrm{the} \\ $$$$\mathrm{atmospheric}\:\mathrm{pressure}\:\mathrm{is}\:\mathrm{1}.\mathrm{02}\:×\:\mathrm{10}^{\mathrm{5}} \:\mathrm{Pa}.\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{pressure}\:\mathrm{on}\:\mathrm{the}\:\mathrm{driver}. \\ $$ Answered by ajfour last updated on 13/Jul/17 $$\mathrm{P}=\mathrm{P}_{\mathrm{0}} +\rho\mathrm{gh}…

Question-17970

Question Number 17970 by tawa tawa last updated on 13/Jul/17 Answered by 42 last updated on 13/Jul/17 $$\mathrm{C}_{\mathrm{3}} \mathrm{H}_{\mathrm{8}} \:+\:\mathrm{5O}_{\mathrm{2}} \:\rightarrow\:\mathrm{3CO}_{\mathrm{2}} \:+\:\mathrm{4H}_{\mathrm{2}} \mathrm{O} \\ $$…

Question-17961

Question Number 17961 by ketto last updated on 13/Jul/17 Answered by alex041103 last updated on 13/Jul/17 $${Let}\:{the}\:{total}\:{amount}\:{of}\:{money}\:{be}\:{M}. \\ $$$${And}\:{the}\:{money}\:{Lightness}\:{got}\:−\:{x} \\ $$$${Then} \\ $$$${M}=\frac{\mathrm{5}}{\mathrm{11}}{M}\:+\:\left(\mathrm{1}−\frac{\mathrm{5}}{\mathrm{11}}\right)\frac{\mathrm{7}}{\mathrm{12}}{M}\:+\:{x} \\ $$$$\Rightarrow{M}=\frac{\mathrm{5}}{\mathrm{11}}{M}+\frac{\mathrm{7}}{\mathrm{22}}{M}+{x}…

If-only-downward-motion-along-lines-is-allowed-what-is-the-total-number-of-paths-from-point-P-to-point-Q-in-the-figure-below-

Question Number 17938 by Tinkutara last updated on 12/Jul/17 $$\mathrm{If}\:\mathrm{only}\:\mathrm{downward}\:\mathrm{motion}\:\mathrm{along}\:\mathrm{lines}\:\mathrm{is} \\ $$$$\mathrm{allowed},\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{total}\:\mathrm{number}\:\mathrm{of} \\ $$$$\mathrm{paths}\:\mathrm{from}\:\mathrm{point}\:\mathrm{P}\:\mathrm{to}\:\mathrm{point}\:\mathrm{Q}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{figure}\:\mathrm{below}? \\ $$ Commented by Tinkutara last updated on 12/Jul/17…

Write-the-electronic-configuration-and-the-block-to-which-an-element-with-Z-90-belongs-

Question Number 17918 by Tinkutara last updated on 12/Jul/17 $$\mathrm{Write}\:\mathrm{the}\:\mathrm{electronic}\:\mathrm{configuration}\:\mathrm{and} \\ $$$$\mathrm{the}\:\mathrm{block}\:\mathrm{to}\:\mathrm{which}\:\mathrm{an}\:\mathrm{element}\:\mathrm{with} \\ $$$$\mathrm{Z}\:=\:\mathrm{90}\:\mathrm{belongs}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

How-do-the-electronic-configurations-of-the-elements-with-Z-107-109-differ-from-one-another-

Question Number 17919 by Tinkutara last updated on 12/Jul/17 $$\mathrm{How}\:\mathrm{do}\:\mathrm{the}\:\mathrm{electronic}\:\mathrm{configurations}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{elements}\:\mathrm{with}\:\mathrm{Z}\:=\:\mathrm{107}\:−\:\mathrm{109}\:\mathrm{differ} \\ $$$$\mathrm{from}\:\mathrm{one}\:\mathrm{another}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com