Question Number 225322 by mr W last updated on 21/Oct/25 $${Tinku}\:{Tara}\:{sir}: \\ $$$${it}\:{could}\:{be}\:{a}\:{new}\:{issue}: \\ $$$${when}\:{i}\:{cancel}\:{a}\:{comment}\:{or}\:{an}\:{answer}, \\ $$$${by}\:{tapping}\:{the}\:{back}\:{button},\:{it}\:{should} \\ $$$${popup}\:{a}\:{window}\:{asking}\:{if}\:{discard}\: \\ $$$${or}\:{save}.\:{now}\:{this}\:{popup}\:{window}\: \\ $$$${doesn}'{t}\:{appear}\:{and}\:{the}\:{work}\:{made}\: \\ $$$${goes}\:{automatically}\:{lost}.…
Question Number 224790 by Tawa11 last updated on 04/Oct/25 Commented by Tawa11 last updated on 04/Oct/25 Commented by Tawa11 last updated on 04/Oct/25 $$\mathrm{Am}\:\mathrm{not}\:\mathrm{sure}\:\mathrm{sir} \\…
Question Number 224753 by Tawa11 last updated on 01/Oct/25 Commented by fantastic last updated on 01/Oct/25 $${wdym}\:{by}\:{magnitude}\:{of}\:{reaction} \\ $$$${is}\:{the}\:{mass}\:{of}\:{the}\:{block}\:{on}\:{inclined} \\ $$$${surface}\:{is}\:\mathrm{7}{kg}? \\ $$ Commented by…
Question Number 224688 by Tawa11 last updated on 26/Sep/25 A gun, kept on a straight horizontal road, is used to hit a car travelling along…
Question Number 224466 by Jubr last updated on 13/Sep/25 Commented by fantastic last updated on 14/Sep/25 $${the}\:{acceleration}\: \\ $$$${a}=\frac{\mathrm{4}{m}_{\mathrm{1}} {m}_{\mathrm{2}} +{m}_{\mathrm{0}} \left({m}_{\mathrm{1}} −{m}_{\mathrm{2}} \right)}{\mathrm{4}{m}_{\mathrm{1}} {m}_{\mathrm{2}}…
Question Number 224417 by Tawa11 last updated on 09/Sep/25 Commented by mr W last updated on 09/Sep/25 $${a}=\frac{\mathrm{2}{g}\:\mathrm{sin}\:\theta}{\mathrm{3}},\: \\ $$$${if}\:{no}\:{friction}\:{and}\:{spool}\:{is}\:{solid}\:{cylinder}. \\ $$ Commented by Tawa11…
Question Number 224406 by Tawa11 last updated on 08/Sep/25 Answered by mr W last updated on 09/Sep/25 $${mur}\:\mathrm{sin}\:\theta_{\mathrm{0}} ={mUr} \\ $$$$\Rightarrow{u}\:\mathrm{sin}\:\theta_{\mathrm{0}} ={U} \\ $$$$\frac{{mu}^{\mathrm{2}} }{\mathrm{2}}=\frac{{mU}^{\mathrm{2}}…
Question Number 224106 by OmoloyeMichael last updated on 20/Aug/25 Commented by OmoloyeMichael last updated on 20/Aug/25 $$\boldsymbol{{how}}\:\boldsymbol{{to}}\:\boldsymbol{{prove}}\:\boldsymbol{{this}}\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 224092 by mr W last updated on 19/Aug/25 $${what}'{s}\:{the}\:{matter}? \\ $$$${yesterday}\:{the}\:{app}\:{was}\:{not}\:{accessible} \\ $$$${for}\:{many}\:{hours}.\:{now}\:{it}\:{seems}\:{to} \\ $$$${work}\:{normally}\:{again}.\:{but}\:{actually} \\ $$$${it}\:{doesn}'{t},\:{at}\:{least}\:{with}\:{me}.\:{when} \\ $$$${i}\:{tip}\:“\boldsymbol{{view}}\:\boldsymbol{{older}}''\:{to}\:{scroll}\:{through} \\ $$$${the}\:{old}\:{posts},\:{the}\:{app}\:{crashes}\:{always} \\ $$$${at}\:{some}\:{point},\:{showing}\:{a}\:{message}…
Question Number 224049 by MASANJAJJ last updated on 16/Aug/25 Answered by RedstoneGG4 last updated on 17/Aug/25 $${O}\:=\:\left(\mathrm{0},\mathrm{0}\right) \\ $$$$ \\ $$$${T}\left({O}\right)\:=\:\left(\mathrm{3},-\mathrm{2}\right) \\ $$$${S}\left({O}\right)\:=\:\left(-\mathrm{2},\mathrm{1}\right) \\ $$$$\left(\mathrm{a}\right)\:\left({S}\:\circ\:{T}\right)\left({O}\right)\:=\:\left(\mathrm{1},-\mathrm{1}\right)…