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a-set-S-R-and-S-n-n-2-1-n-N-n-1-show-that-minS-1-2-and-supS-1-

Question Number 129337 by TITA last updated on 15/Jan/21 $$\mathrm{a}\:\mathrm{set}\:\mathrm{S}\subset\mathbb{R}\:\:\:\mathrm{and}\:\:\mathrm{S}=\left\{\frac{\mathrm{n}}{\:\sqrt{\mathrm{n}^{\mathrm{2}} +\mathrm{1}}}:\:\mathrm{n}\in\mathbb{N},\:\mathrm{n}\geqslant\mathrm{1}\right\} \\ $$$$\mathrm{show}\:\mathrm{that}\:\mathrm{minS}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\:\mathrm{and}\:\:\mathrm{supS}=\mathrm{1} \\ $$ Commented by TITA last updated on 15/Jan/21 $$\mathrm{please}\:\mathrm{help} \\ $$…

Question-63790

Question Number 63790 by rajesh4661kumar@gamil.com last updated on 09/Jul/19 Answered by Hope last updated on 10/Jul/19 $${a}+{b}=\mathrm{6}{k} \\ $$$${b}+{c}=\mathrm{7}{k} \\ $$$${c}+{a}=\mathrm{8}{k} \\ $$$${add}\:{them} \\ $$$$\mathrm{2}\left({a}+{b}+{c}\right)=\mathrm{21}{k}…

Question-63788

Question Number 63788 by rajesh4661kumar@gamil.com last updated on 09/Jul/19 Answered by mr W last updated on 09/Jul/19 $${a}+{b}=\mathrm{6}{k} \\ $$$${b}+{c}=\mathrm{7}{k} \\ $$$${c}+{a}=\mathrm{8}{k} \\ $$$$\mathrm{2}\left({a}+{b}+{c}\right)=\left(\mathrm{6}+\mathrm{7}+\mathrm{8}\right){k} \\…

Tanmay-Sir-Are-you-ok-

Question Number 63758 by Prithwish sen last updated on 08/Jul/19 $$\mathrm{Tanmay}\:\mathrm{Sir}.\:\mathrm{Are}\:\mathrm{you}\:\mathrm{ok}\:? \\ $$ Commented by mathmax by abdo last updated on 09/Jul/19 $${i}\:{see}\:{that}\:{sir}\:{Tanmay}\:{is}\:{absent}\:{in}\:{the}\:{forum}\:.{i}\:{hope}\:{that}\:{we} \\ $$$${know}\:{the}\:{cause}\:{of}\:{his}\:{absence}….…

Q-129271-please-answer-

Question Number 129292 by AgnibhoMukhopadhyay last updated on 14/Jan/21 $$\mathrm{Q}\:\mathrm{129271}\:\mathrm{please}\:\mathrm{answer} \\ $$ Commented by prakash jain last updated on 14/Jan/21 $$\mathrm{I}\:\mathrm{get}\:−\mathrm{ve}\:\mathrm{answer}.\:\mathrm{check}\:\mathrm{original} \\ $$$$\mathrm{questions}\:\mathrm{comment}. \\ $$$$\mathrm{Maybe}\:\mathrm{somebody}\:\mathrm{else}\:\mathrm{can}\:\mathrm{comment}…

1-s-2-2s-5-2-find-inverse-laplace-

Question Number 129268 by BHOOPENDRA last updated on 14/Jan/21 $$\frac{\mathrm{1}}{\left({s}^{\mathrm{2}} +\mathrm{2}{s}+\mathrm{5}\right)^{\mathrm{2}} }\:{find}\:{inverse}\:{laplace} \\ $$ Answered by mnjuly1970 last updated on 14/Jan/21 $$\:\mathscr{F}\left({s}\right)=\frac{\mathrm{1}}{\left(\left({s}+\mathrm{1}\right)^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}} \right)^{\mathrm{2}} }…