Question Number 64391 by rachelleazarcon last updated on 17/Jul/19 $$\frac{\mathrm{6}}{\mathrm{a}+\mathrm{5}}+\frac{\mathrm{4}}{\mathrm{a}+\mathrm{5}} \\ $$ Commented by mathmax by abdo last updated on 17/Jul/19 $$=\frac{\mathrm{6}+\mathrm{4}}{{a}+\mathrm{5}}\:=\frac{\mathrm{10}}{{a}+\mathrm{5}} \\ $$ Terms…
Question Number 64381 by ketto2 last updated on 17/Jul/19 Commented by MJS last updated on 17/Jul/19 $$\frac{\mathrm{drawing}}{\mathrm{reality}}=\frac{\mathrm{5}{cm}}{\mathrm{250}{m}}=\frac{\mathrm{5}}{\mathrm{250}}×\frac{{cm}}{{m}}=\frac{\mathrm{1}}{\mathrm{50}}×\frac{\mathrm{1}}{\mathrm{100}}=\frac{\mathrm{1}}{\mathrm{5000}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 64356 by udu last updated on 17/Jul/19 $$ \\ $$ Answered by MJS last updated on 17/Jul/19 $$\mathrm{42} \\ $$ Terms of Service…
Question Number 64354 by Rio Michael last updated on 17/Jul/19 $${some}\:{one}\:{write}\:{the}\:{statement} \\ $$$$\:{a}\:\equiv−{a}\left({mod}\:{m}\right)\: \\ $$$${show}\:{that}\:{this}\:{statement}\:{is}\:{not}\:{generally}\:{true}.!\:{giving}\:{a}\:{counter} \\ $$$${example} \\ $$ Answered by MJS last updated on…
Question Number 64350 by Rio Michael last updated on 16/Jul/19 $${Given}\:{that}\:{f}\left({x}\right)\:=\:\begin{vmatrix}{{x}}&{{x}^{\mathrm{2}} }&{{x}^{\mathrm{3}} }\\{\mathrm{1}}&{\mathrm{2}{x}}&{\mathrm{3}{x}^{\mathrm{2}} }\\{\mathrm{0}}&{\mathrm{2}}&{\mathrm{6}{x}}\end{vmatrix},\:{find}\:{f}\:'\:\left({x}\right) \\ $$ Commented by Tony Lin last updated on 17/Jul/19 $${f}\left({x}\right)=\mathrm{12}{x}^{\mathrm{3}}…
Question Number 64347 by Rio Michael last updated on 16/Jul/19 $${Two}\:{consecutive}\:{integers}\:{between}\:{which}\:{a}\:{root}\:{of}\:{the}\:{equation} \\ $$$$\left.\:\mathrm{1}\right){x}^{\mathrm{3}} +{x}−\mathrm{16}=\mathrm{0}\: \\ $$$$\left.\mathrm{2}\right)\:{x}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{2}=\mathrm{0} \\ $$$${lies}\:{are}; \\ $$ Terms of Service Privacy…
Question Number 129811 by AgnibhoMukhopadhyay last updated on 19/Jan/21 $$\left(\frac{\mathrm{1}}{\mathrm{4}}\right)\left(\frac{\mathrm{2}}{\mathrm{4}}\right)\left(\frac{\mathrm{5}}{\mathrm{6}}\right)\left(\frac{\mathrm{7}}{\mathrm{8}}\right)=\:? \\ $$ Answered by EDWIN88 last updated on 20/Jan/21 $$\:\frac{\mathrm{70}}{\mathrm{4}^{\mathrm{4}} ×\mathrm{3}} \\ $$ Terms of…
Question Number 64218 by Hope last updated on 15/Jul/19 $${so}\:{goodbye}\:{everybody}\:{i}\:{am}\:{leaving}\:{this}\:{platform} \\ $$ Commented by MJS last updated on 15/Jul/19 $$\mathrm{why}?\::−\left(\right. \\ $$ Commented by ajfour…
Question Number 129679 by BHOOPENDRA last updated on 17/Jan/21 Answered by mathmax by abdo last updated on 18/Jan/21 $$\mathrm{I}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \mathrm{x}\sqrt{\mathrm{tanx}}\mathrm{dx}\:\:\mathrm{changement}\:\sqrt{\mathrm{tanx}}=\mathrm{t}\:\mathrm{give}\:\mathrm{tanx}=\mathrm{t}^{\mathrm{2}} \:\Rightarrow\mathrm{x}=\mathrm{arctan}\left(\mathrm{t}^{\mathrm{2}} \right)\:\Rightarrow \\ $$$$\mathrm{I}=\int_{\mathrm{0}}…
Question Number 64138 by Tawa1 last updated on 14/Jul/19 Answered by som(math1967) last updated on 14/Jul/19 $$\bigtriangleup{ADC}\sim\bigtriangleup{BAC} \\ $$$$\therefore\frac{{AC}}{{DC}}=\frac{{BC}}{{AC}}=\frac{{AB}}{{AD}} \\ $$$$\therefore\frac{{AC}}{{DC}}=\frac{{AB}}{{AD}}=\frac{\mathrm{14}}{\mathrm{7}}\:\:\therefore{AC}=\mathrm{2}{DC} \\ $$$${Again}\:\frac{{AC}}{{DC}}=\frac{{BC}}{{AC}}\:\Rightarrow{AC}^{\mathrm{2}} ={BC}×{DC} \\…