Question Number 16491 by Tinkutara last updated on 23/Jun/17 $$\mathrm{Men}\:\mathrm{are}\:\mathrm{running}\:\mathrm{in}\:\mathrm{a}\:\mathrm{line}\:\mathrm{along}\:\mathrm{a}\:\mathrm{road} \\ $$$$\mathrm{with}\:\mathrm{velocity}\:\mathrm{9}\:\mathrm{km}/\mathrm{hr}\:\mathrm{behind}\:\mathrm{one} \\ $$$$\mathrm{another}\:\mathrm{at}\:\mathrm{equal}\:\mathrm{distances}\:\mathrm{of}\:\mathrm{20}\:\mathrm{m}. \\ $$$$\mathrm{Cyclists}\:\mathrm{are}\:\mathrm{also}\:\mathrm{riding}\:\mathrm{along}\:\mathrm{the}\:\mathrm{same} \\ $$$$\mathrm{line}\:\mathrm{in}\:\mathrm{the}\:\mathrm{same}\:\mathrm{direction}\:\mathrm{at}\:\mathrm{18}\:\mathrm{km}/\mathrm{hr} \\ $$$$\mathrm{at}\:\mathrm{equal}\:\mathrm{intervals}\:\mathrm{of}\:\mathrm{30}\:\mathrm{m}.\:\mathrm{The}\:\mathrm{speed} \\ $$$$\mathrm{with}\:\mathrm{which}\:\mathrm{an}\:\mathrm{observer}\:\mathrm{must}\:\mathrm{travel} \\ $$$$\mathrm{along}\:\mathrm{the}\:\mathrm{road}\:\mathrm{in}\:\mathrm{opposite}\:\mathrm{direction}\:\mathrm{of} \\…
Question Number 16466 by tawa tawa last updated on 22/Jun/17 Answered by sandy_suhendra last updated on 22/Jun/17 Commented by sandy_suhendra last updated on 22/Jun/17 $$\mathrm{n}_{\mathrm{1}}…
Question Number 16455 by Tinkutara last updated on 22/Jun/17 $$\mathrm{The}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{a}\:\mathrm{projectile}\:\mathrm{when}\:\mathrm{it}\:\mathrm{is}\:\mathrm{at} \\ $$$$\mathrm{its}\:\mathrm{greatest}\:\mathrm{height}\:\mathrm{is}\:\sqrt{\frac{\mathrm{2}}{\mathrm{5}}}\:\mathrm{times}\:\mathrm{its} \\ $$$$\mathrm{speed}\:\mathrm{at}\:\mathrm{half}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{height}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{its}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{projection}? \\ $$ Answered by sandy_suhendra last updated on 23/Jun/17…
Question Number 81971 by TawaTawa last updated on 17/Feb/20 Answered by mind is power last updated on 17/Feb/20 $${angle}\:{between}\:{Wire}\:{and}\:{vertical}=\mathrm{cos}^{−\mathrm{1}} \left(\frac{\mathrm{1}.\mathrm{5}}{\mathrm{2}}\right)=\alpha \\ $$$${we}\:{get}\:\Sigma\overset{\rightarrow} {{F}}=\overset{\rightarrow} {\mathrm{0}} \\…
Question Number 147473 by Sanvi2007 last updated on 21/Jul/21 $${p}\left({t}\right)=\mathrm{4}{t}^{\mathrm{4}} +\mathrm{5}{t}^{\mathrm{3}} −{t}^{\mathrm{2}} +\mathrm{6}\:\:{at}\:\:{t}={a} \\ $$ Commented by physicstutes last updated on 21/Jul/21 $$\mathrm{at}\:{t}\:=\:{a}\:,\:{p}\left({a}\right)\:=\:\mathrm{4}{a}^{\mathrm{4}} +\mathrm{5}{a}^{\mathrm{3}} −{a}^{\mathrm{2}}…
Question Number 81851 by abdomathmax last updated on 16/Feb/20 $$\left.\mathrm{1}\right){find}\:\int\:\:\:\:\frac{{dx}}{\left({x}+\mathrm{1}\right)^{\mathrm{3}} \left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} } \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{dx}}{\left({x}+\mathrm{1}\right)^{\mathrm{3}} \left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} } \\ $$ Terms of Service…
Question Number 81843 by TawaTawa last updated on 15/Feb/20 Commented by mr W last updated on 16/Feb/20 Commented by mr W last updated on 16/Feb/20…
Question Number 16310 by tawa tawa last updated on 20/Jun/17 Commented by tawa tawa last updated on 20/Jun/17 $$\mathrm{please}\:\mathrm{i}\:\mathrm{need}\:\mathrm{the}\:\mathrm{solutions}\:\mathrm{urgent}\:\mathrm{sirs}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{youreffort}. \\ $$$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sirs}. \\ $$ Commented by…
Question Number 16281 by Tinkutara last updated on 20/Jun/17 $$\mathrm{A}\:\mathrm{plane}\:\mathrm{moves}\:\mathrm{in}\:\mathrm{windy}\:\mathrm{weather}\:\mathrm{due} \\ $$$$\mathrm{east}\:\mathrm{while}\:\mathrm{the}\:\mathrm{pilot}\:\mathrm{points}\:\mathrm{the}\:\mathrm{plane} \\ $$$$\mathrm{somewhat}\:\mathrm{south}\:\mathrm{of}\:\mathrm{east}.\:\mathrm{The}\:\mathrm{wind}\:\mathrm{is} \\ $$$$\mathrm{blowing}\:\mathrm{at}\:\mathrm{50}\:\mathrm{km}/\mathrm{hr}\:\mathrm{directed}\:\mathrm{30}°\:\mathrm{east} \\ $$$$\mathrm{of}\:\mathrm{north},\:\mathrm{while}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{moves}\:\mathrm{at}\:\mathrm{200} \\ $$$$\mathrm{km}/\mathrm{hr}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{wind}.\:\mathrm{What}\:\mathrm{is} \\ $$$$\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{ground}\:\mathrm{and}\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{direction}\:\mathrm{in} \\…
Question Number 16271 by aalieff last updated on 20/Jun/17 $${The}\:{unemployment}\:{rate}\:{among}\:{workers} \\ $$$${under}\:\mathrm{25}\:{in}\:{a}\:{state}\:{went}\:{from}\:\mathrm{8}.\mathrm{2\%} \\ $$$${to}\:\mathrm{7}.\mathrm{5\%}\:{in}\:{one}\:{year}.\:{Assume}\:{an}\:{average} \\ $$$${of}\:\mathrm{1340200}\:{workers}\:{and}\:{estimate} \\ $$$${the}\:{decrease}\:{in}\:{the}\:{number}\:{unemployed}. \\ $$ Answered by mrW1 last updated…