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Question-17129

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Question Number 17129 by virus last updated on 01/Jul/17 Answered by ajfour last updated on 01/Jul/17 $$\mathrm{v}_{\mathrm{avg}} =\frac{\mid\bigtriangleup\boldsymbol{\mathrm{r}}\mid}{\bigtriangleup\mathrm{t}}=\frac{\mathrm{2rsin}\:\left(\theta/\mathrm{2}\right)}{\mathrm{r}\theta/\mathrm{v}} \\ $$$$\:\:\:\:\:\:\:=\:\mathrm{v}\left[\frac{\mathrm{sin}\:\left(\theta/\mathrm{2}\right)}{\left(\theta/\mathrm{2}\right)}\right]\:, \\ $$$$\mathrm{a}_{\mathrm{avg}} =\frac{\mid\bigtriangleup\boldsymbol{\mathrm{v}}\mid}{\bigtriangleup\mathrm{t}}=\frac{\mathrm{2vsin}\:\left(\theta/\mathrm{2}\right)}{\mathrm{r}\theta/\mathrm{v}} \\ $$$$\:\:\:\:\:\:\:=\:\frac{\mathrm{v}^{\mathrm{2}}…

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A-clock-has-a-pendulum-made-of-iron-rod-of-length-2-5m-if-the-clock-keeps-accurate-time-at-0-C-By-how-much-time-will-it-be-late-running-at-a-temperature-30-C-for-1-day-coefficient-of-linear-expansi

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Question Number 17117 by tawa tawa last updated on 01/Jul/17 $$\mathrm{A}\:\mathrm{clock}\:\mathrm{has}\:\mathrm{a}\:\mathrm{pendulum}\:\mathrm{made}\:\mathrm{of}\:\mathrm{iron}\:\mathrm{rod}\:\mathrm{of}\:\mathrm{length}\:\mathrm{2}.\mathrm{5m}, \\ $$$$\mathrm{if}\:\mathrm{the}\:\mathrm{clock}\:\mathrm{keeps}\:\mathrm{accurate}\:\mathrm{time}\:\mathrm{at}\:\mathrm{0}°\mathrm{C}.\:\mathrm{By}\:\mathrm{how}\:\mathrm{much}\:\mathrm{time}\:\mathrm{will}\:\mathrm{it}\:\mathrm{be}\:\mathrm{late} \\ $$$$\mathrm{running}\:\mathrm{at}\:\mathrm{a}\:\mathrm{temperature}\:\mathrm{30}°\mathrm{C}\:\mathrm{for}\:\mathrm{1}\:\mathrm{day}.\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{linear}\:\mathrm{expansivity}\:\mathrm{of} \\ $$$$\mathrm{iron}\:\mathrm{is}\:\:\mathrm{1}.\mathrm{2}\:×\:\mathrm{10}^{−\mathrm{5}} \mathrm{per}\:\mathrm{k}. \\ $$ Answered by ajfour last updated…

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