Question Number 14452 by christine last updated on 31/May/17 Commented by RasheedSindhi last updated on 01/Jun/17 $$\mathrm{The}\:\mathrm{question}\:\mathrm{is}\:\mathrm{invisible}! \\ $$$$\mathrm{Pl}\:\mathrm{type}\:\mathrm{it}. \\ $$ Commented by Joel577 last…
Question Number 14451 by christine last updated on 31/May/17 Answered by mrW1 last updated on 31/May/17 $$\mathrm{4}{x}=\mathrm{9}{n}+\mathrm{5} \\ $$$${x}=\frac{\mathrm{9}{n}+\mathrm{5}}{\mathrm{4}}=\frac{\mathrm{8}{n}+\mathrm{4}+{n}+\mathrm{1}}{\mathrm{4}}=\mathrm{2}{n}+\mathrm{1}+\frac{{n}+\mathrm{1}}{\mathrm{4}} \\ $$$${n}+\mathrm{1}=\mathrm{4}{k} \\ $$$${n}=\mathrm{4}{k}−\mathrm{1} \\ $$$${x}=\frac{\mathrm{9}\left(\mathrm{4}{k}−\mathrm{1}\right)+\mathrm{5}}{\mathrm{4}}=\mathrm{9}{k}−\mathrm{1},\:{k}\epsilon\mathbb{P}…
Question Number 14440 by christine last updated on 31/May/17 Answered by prakash jain last updated on 31/May/17 $$\mathrm{number}\:\mathrm{of}\:\mathrm{integer}\:\mathrm{1}\leqslant{n}\leqslant\mathrm{100} \\ $$$$\mathrm{divisible}\:\mathrm{by}\:\mathrm{4}\:=\lfloor\frac{\mathrm{100}}{\mathrm{4}}\rfloor=\mathrm{25} \\ $$$$\mathrm{divisible}\:\mathrm{by}\:\mathrm{6}\:=\lfloor\frac{\mathrm{100}}{\mathrm{6}}\rfloor=\mathrm{16} \\ $$$$\mathrm{divisible}\:\mathrm{by}\:\mathrm{by}\:\mathrm{4}\:\mathrm{and}\:\mathrm{6}\:=\lfloor\frac{\mathrm{100}}{\mathrm{12}}\rfloor=\mathrm{8} \\…
Question Number 79968 by Rio Michael last updated on 29/Jan/20 $${Find}\:{the}\:\mathrm{50}^{{th}} \:{entry}\:{of}\:\:\mathrm{3}.\mathrm{127356432}… \\ $$ Commented by mr W last updated on 29/Jan/20 $${what}'{s}\:{that}? \\ $$…
Question Number 79969 by Rio Michael last updated on 29/Jan/20 $${find}\:{the}\:{general}\:{solution}\:{for}\: \\ $$$$\:\:\mathrm{2sin}\:\mathrm{3}{x}\:=\:\mathrm{sin}\:\mathrm{2}{x} \\ $$ Answered by behi83417@gmail.com last updated on 29/Jan/20 $$\mathrm{2}\left(\mathrm{3sinx}−\mathrm{4sin}^{\mathrm{3}} \mathrm{x}\right)=\mathrm{2sinxcosx} \\…
Question Number 14421 by chux last updated on 31/May/17 $$\mathrm{express}\:\frac{\mathrm{2x}^{\mathrm{2}} −\mathrm{x}+\mathrm{2}}{\left(\mathrm{x}+\mathrm{2}\right)^{\mathrm{2}} \left(\mathrm{1}−\mathrm{2x}\right)}\mathrm{as}\:\mathrm{partial} \\ $$$$\mathrm{fraction} \\ $$ Answered by RasheedSindhi last updated on 01/Jun/17 $$\mathrm{Let} \\…
Question Number 79943 by TawaTawa last updated on 29/Jan/20 Commented by TawaTawa last updated on 29/Jan/20 $$\mathrm{Equilateral}\:\mathrm{triangle}\:\mathrm{not}\:\mathrm{equilibrium}\:\mathrm{triangle} \\ $$ Commented by TawaTawa last updated on…
Question Number 14387 by chux last updated on 31/May/17 Commented by chux last updated on 31/May/17 $$\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{solve}\:\mathrm{no}.\:\mathrm{11}\:\mathrm{and}\:\mathrm{12} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 14297 by Tinkutara last updated on 30/May/17 $$\mathrm{Select}\:\mathrm{the}\:\mathrm{correct}\:\mathrm{formulae}\:\mathrm{for} \\ $$$$\mathrm{uniformly}\:\mathrm{accelerated}\:\mathrm{motion}\:\mathrm{along}\:\mathrm{a} \\ $$$$\mathrm{straight}\:\mathrm{line}\:\left(\mathrm{More}\:\mathrm{than}\:\mathrm{one}\:\mathrm{option}\right. \\ $$$$\left.\mathrm{are}\:\mathrm{correct}\right) \\ $$$$\left(\mathrm{1}\right)\:{v}\:=\:{u}\:+\:{at} \\ $$$$\left(\mathrm{2}\right)\:{s}\:=\:\left(\frac{{u}\:+\:{v}}{\mathrm{2}}\right){t} \\ $$$$\left(\mathrm{3}\right)\:{s}\:=\:{vt}\:−\:\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} \\ $$$$\left(\mathrm{4}\right)\:{s}\:=\:\frac{{v}^{\mathrm{2}} \:−\:{u}^{\mathrm{2}}…