Question Number 63891 by Tawa1 last updated on 10/Jul/19 $$\mathrm{A}\:\mathrm{bus}\:\mathrm{is}\:\mathrm{travelling}\:\mathrm{along}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{road}\:\mathrm{at}\:\mathrm{100Km}/\mathrm{hr}\:\mathrm{and} \\ $$$$\mathrm{the}\:\mathrm{bus}\:\mathrm{conductor}\:\mathrm{walks}\:\mathrm{at}\:\mathrm{6Km}/\mathrm{hr}\:\mathrm{on}\:\mathrm{the}\:\mathrm{floor}\:\mathrm{of}\:\mathrm{the}\:\mathrm{bus} \\ $$$$\mathrm{and}\:\mathrm{in}\:\mathrm{the}\:\mathrm{same}\:\mathrm{direction}\:\mathrm{as}\:\mathrm{the}\:\mathrm{bus}.\: \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{conductor}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{road},\:\mathrm{and} \\ $$$$\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{bus}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{bus}\:\mathrm{conductor}\:\mathrm{now}\:\mathrm{works}\:\mathrm{at}\:\mathrm{the}\:\mathrm{same} \\ $$$$\mathrm{rate}\:\mathrm{but}\:\mathrm{in}\:\mathrm{the}\:\mathrm{opposite}\:\mathrm{direction}\:\mathrm{as}\:\mathrm{the}\:\mathrm{bus},\:\mathrm{find}\:\mathrm{his}\:\mathrm{new}\:\mathrm{speed} \\ $$$$\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{road}. \\ $$$$\mathrm{Answers}\:\mathrm{in}\:\mathrm{textbook}:\:\:\:\:\mathrm{106Km}/\mathrm{hr},\:\:\:\:\mathrm{64Km}/\mathrm{hr},\:\:\:\:\:\mathrm{94Km}/\mathrm{hr} \\…
Question Number 129378 by BHOOPENDRA last updated on 15/Jan/21 Answered by Dwaipayan Shikari last updated on 15/Jan/21 $$\mathscr{L}\left({ut}^{\mathrm{2}} {e}^{−\mathrm{2}{t}} −{ute}^{−\mathrm{2}{t}} \right)={u}\int_{\mathrm{0}} ^{\infty} {t}^{\mathrm{2}} {e}^{−\left({s}+\mathrm{2}\right){t}} −{u}\int_{\mathrm{0}}…
Question Number 129376 by Dwaipayan Shikari last updated on 15/Jan/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} {e}^{−{x}^{\mathrm{2}} } {dx}=\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{3}^{\mathrm{2}} }{\mathrm{7}+\frac{\mathrm{10}^{\mathrm{2}} }{\mathrm{32}+\frac{\mathrm{42}^{\mathrm{2}} }{\mathrm{174}+\frac{\mathrm{216}^{\mathrm{2}} }{\mathrm{1196}+\frac{\mathrm{1312}^{\mathrm{2}} }{….}}}}}}} \\ $$ Commented by Dwaipayan…
Question Number 129367 by BHOOPENDRA last updated on 15/Jan/21 Commented by BHOOPENDRA last updated on 15/Jan/21 $${using}\:{unit}\:{step}\:{function}\:{find}\:{laplace}\:{transform} \\ $$ Answered by mathmax by abdo last…
Question Number 63812 by kaivan.ahmadi last updated on 09/Jul/19 $$ \\ $$$${A}\:\:{can}\:{terminate}\:{a}\:{work}\:\:\mathrm{9}\:{hour}\:{earlier} \\ $$$${than}\:{B}. \\ $$$${A}\:\:{and}\:\:{B}\:\:{terminate}\:{that}\:{work}\:\:{after}\:\mathrm{20}\:{hour}\:{together}. \\ $$$${A}\:{can}\:{terminate}\:{that}\:{work}\:{after}\:….\:{hour}. \\ $$$$ \\ $$$$ \\ $$ Commented…
Question Number 129345 by BHOOPENDRA last updated on 15/Jan/21 $$\frac{\mathrm{1}}{\left({s}^{\mathrm{2}} +\mathrm{2}{s}+\mathrm{5}\right)^{\mathrm{2}} }\:{find}\:{inverse}\:{laplace} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 129337 by TITA last updated on 15/Jan/21 $$\mathrm{a}\:\mathrm{set}\:\mathrm{S}\subset\mathbb{R}\:\:\:\mathrm{and}\:\:\mathrm{S}=\left\{\frac{\mathrm{n}}{\:\sqrt{\mathrm{n}^{\mathrm{2}} +\mathrm{1}}}:\:\mathrm{n}\in\mathbb{N},\:\mathrm{n}\geqslant\mathrm{1}\right\} \\ $$$$\mathrm{show}\:\mathrm{that}\:\mathrm{minS}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\:\mathrm{and}\:\:\mathrm{supS}=\mathrm{1} \\ $$ Commented by TITA last updated on 15/Jan/21 $$\mathrm{please}\:\mathrm{help} \\ $$…
Question Number 63790 by rajesh4661kumar@gamil.com last updated on 09/Jul/19 Answered by Hope last updated on 10/Jul/19 $${a}+{b}=\mathrm{6}{k} \\ $$$${b}+{c}=\mathrm{7}{k} \\ $$$${c}+{a}=\mathrm{8}{k} \\ $$$${add}\:{them} \\ $$$$\mathrm{2}\left({a}+{b}+{c}\right)=\mathrm{21}{k}…
Question Number 63788 by rajesh4661kumar@gamil.com last updated on 09/Jul/19 Answered by mr W last updated on 09/Jul/19 $${a}+{b}=\mathrm{6}{k} \\ $$$${b}+{c}=\mathrm{7}{k} \\ $$$${c}+{a}=\mathrm{8}{k} \\ $$$$\mathrm{2}\left({a}+{b}+{c}\right)=\left(\mathrm{6}+\mathrm{7}+\mathrm{8}\right){k} \\…
Question Number 63789 by rajesh4661kumar@gamil.com last updated on 09/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com