Question Number 14310 by tawa tawa last updated on 30/May/17 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 14297 by Tinkutara last updated on 30/May/17 $$\mathrm{Select}\:\mathrm{the}\:\mathrm{correct}\:\mathrm{formulae}\:\mathrm{for} \\ $$$$\mathrm{uniformly}\:\mathrm{accelerated}\:\mathrm{motion}\:\mathrm{along}\:\mathrm{a} \\ $$$$\mathrm{straight}\:\mathrm{line}\:\left(\mathrm{More}\:\mathrm{than}\:\mathrm{one}\:\mathrm{option}\right. \\ $$$$\left.\mathrm{are}\:\mathrm{correct}\right) \\ $$$$\left(\mathrm{1}\right)\:{v}\:=\:{u}\:+\:{at} \\ $$$$\left(\mathrm{2}\right)\:{s}\:=\:\left(\frac{{u}\:+\:{v}}{\mathrm{2}}\right){t} \\ $$$$\left(\mathrm{3}\right)\:{s}\:=\:{vt}\:−\:\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} \\ $$$$\left(\mathrm{4}\right)\:{s}\:=\:\frac{{v}^{\mathrm{2}} \:−\:{u}^{\mathrm{2}}…
Question Number 14291 by Tinkutara last updated on 30/May/17 $$\mathrm{Is}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{correct}\:\mathrm{for}\:\mathrm{uniformly} \\ $$$$\mathrm{accelerated}\:\mathrm{motion}\:\mathrm{along}\:\mathrm{a}\:\mathrm{straight} \\ $$$$\mathrm{line}? \\ $$$${s}\:=\:{vt}\:−\:\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} \\ $$ Commented by tawa tawa last updated on…
Question Number 14246 by tawa tawa last updated on 30/May/17 Commented by ajfour last updated on 30/May/17 Commented by ajfour last updated on 30/May/17 $${a}=\frac{{v}−{u}}{\Delta{t}}\:=\frac{\mathrm{25}−\mathrm{30}}{\mathrm{3}}=−\frac{\mathrm{5}}{\mathrm{3}}{m}/{s}^{\mathrm{2}}…
Question Number 14219 by tawa tawa last updated on 29/May/17 Answered by ajfour last updated on 29/May/17 $$\:\:\:\:\:\:\:\:\:\:\:\:\bar {{s}}=\mathrm{4}{t}^{\mathrm{3}} \hat {{i}}−\mathrm{2}{t}^{\mathrm{2}} \hat {{j}}+\mathrm{3}{t}\hat {{k}}\:\:\:..\left({i}\right) \\…
Question Number 14215 by tawa tawa last updated on 29/May/17 Answered by ajfour last updated on 29/May/17 $$\bullet\left(\mathrm{5}\right). \\ $$$${x}=\mathrm{12}{t}^{\mathrm{2}} −\mathrm{2}{t}^{\mathrm{3}} =\mathrm{2}{t}^{\mathrm{2}} \left(\mathrm{6}−{t}\right)\:\:\:\:\:….\left({i}\right) \\ $$$$…
Question Number 79751 by Rio Michael last updated on 27/Jan/20 $${prove}\:{that}\:\mathrm{cos}\:^{\mathrm{6}} \theta\:+\:\mathrm{sin}\:^{\mathrm{6}} \theta\:=\:\mathrm{1}\:−\:\frac{\mathrm{3}}{\mathrm{4}}\:\mathrm{sin}\:^{\mathrm{2}} \mathrm{2}\theta \\ $$ Answered by mind is power last updated on 27/Jan/20…
Question Number 79735 by Rio Michael last updated on 27/Jan/20 $${write}\:{tanhx}\:{in}\:{terms}\:{of}\:{e},\:{hence}\:{prove}\:{that}\: \\ $$$${tanh}\mathrm{2}{x}\:=\:\frac{\mathrm{2}{tanhx}}{\mathrm{1}+{tanh}^{\mathrm{2}} {x}} \\ $$ Answered by Henri Boucatchou last updated on 28/Jan/20 $${tanhx}=\frac{{e}^{{x}}…
Question Number 79738 by Rio Michael last updated on 27/Jan/20 $${The}\:{forces}\:\boldsymbol{\mathrm{F}}_{\mathrm{1}} =\:\left(\mathrm{2}\boldsymbol{{i}}\:+\:{b}\boldsymbol{{j}}\right)\:{N},\:\boldsymbol{{F}}_{\mathrm{2}} =\:\left(−\boldsymbol{{i}}\:+\:\mathrm{2}\boldsymbol{{j}}\right)\:{N} \\ $$$${and}\:\boldsymbol{{F}}_{\mathrm{3}} =\:\left({a}\boldsymbol{{i}}\:−\mathrm{4}\boldsymbol{{j}}\right){N}\:{act}\:{through}\:{the}\:{points}\:{with} \\ $$$${position}\:{vectors}\:\boldsymbol{{r}}_{\mathrm{1}} =\:\left(\boldsymbol{{i}}\:+\:\mathrm{3}\boldsymbol{{j}}\right){m}\:,\boldsymbol{{r}}_{\mathrm{2}} =\left({x}\boldsymbol{{i}}\:+\:\mathrm{5}\boldsymbol{{j}}\right)\:{m} \\ $$$${and}\:\boldsymbol{{r}}_{\mathrm{3}} =\left(−\boldsymbol{{i}}\:+\:\boldsymbol{{j}}\right){m}\:{respectively}\:. \\ $$$${Given}\:{that}\:{this}\:{system}\:{of}\:{forces}\:{is}\:{equivalent}\:{to}\:{a}\:{couple}…
Question Number 79718 by Ell Tee last updated on 27/Jan/20 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com