Question Number 13091 by tawa tawa last updated on 13/May/17 $$\mathrm{A}\:\mathrm{motor}\:\mathrm{car}\:\mathrm{moves}\:\mathrm{with}\:\mathrm{a}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{20m}/\mathrm{s}\:\mathrm{on}\:\mathrm{a}\:\mathrm{rough}\:\mathrm{horizontal}\:\mathrm{road}\:\mathrm{and} \\ $$$$\mathrm{covers}\:\mathrm{a}\:\mathrm{displacement}\:\mathrm{of}\:\mathrm{50m}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{dynamic}\:\mathrm{friction}\:\mathrm{between} \\ $$$$\mathrm{the}\:\mathrm{tyre}\:\mathrm{and}\:\mathrm{the}\:\mathrm{ground}\:\:\left(\mathrm{g}\:=\:\mathrm{10m}/\mathrm{s}^{\mathrm{2}} \right). \\ $$ Answered by mrW1 last updated on 14/May/17…
Question Number 144136 by akolade last updated on 21/Jun/21 Commented by MJS_new last updated on 22/Jun/21 $$\mathrm{trying}\:\mathrm{I}\:\mathrm{almost}\:\mathrm{immediately}\:\mathrm{found} \\ $$$${x}=\pm\mathrm{1} \\ $$ Terms of Service Privacy…
Question Number 13054 by chux last updated on 12/May/17 $$\mathrm{An}\:\mathrm{object}\:\mathrm{is}\:\mathrm{placed}\:\mathrm{between}\:\mathrm{a}\: \\ $$$$\mathrm{converging}\:\mathrm{lens}\:\mathrm{and}\:\mathrm{a}\:\mathrm{plane}\:\mathrm{mirror}. \\ $$$$\mathrm{Explain}\:\mathrm{how}\:\mathrm{two}\:\mathrm{real}\:\mathrm{images}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{object}\:\mathrm{may}\:\mathrm{be}\:\mathrm{produced}\:\mathrm{by}\:\mathrm{the}\: \\ $$$$\mathrm{system}. \\ $$$$\mathrm{If}\:\mathrm{the}\:\mathrm{focal}\:\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{lens}\:\mathrm{is}\:\mathrm{15cm} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{object}\:\mathrm{is}\:\mathrm{20cm}\:\mathrm{from}\:\mathrm{both}\: \\ $$$$\mathrm{the}\:\mathrm{lens}\:\mathrm{and}\:\mathrm{the}\:\mathrm{mirror}.\mathrm{Calculate} \\…
Question Number 13049 by tawa tawa last updated on 12/May/17 $$\mathrm{Two}\:\mathrm{charges}\:\mathrm{q}_{\mathrm{1}} \:=\:\mathrm{10}\:\mu\mathrm{C}\:\mathrm{and}\:\:\mathrm{q}_{\mathrm{2}} \:=\:\mathrm{5}\:\mu\mathrm{C}\:\:\mathrm{are}\:\mathrm{placed}\:\mathrm{on}\:\mathrm{the}\:\mathrm{axis}\:\mathrm{at}\:\mathrm{A}\:\left(\mathrm{10},\:\mathrm{0}\right)\:\mathrm{cm} \\ $$$$\mathrm{and}\:\left(\mathrm{20},\:\mathrm{0}\right)\:\mathrm{cm}\:\:\mathrm{respectively}.\:\mathrm{Determine}\:\mathrm{a}\:\mathrm{position}\:\mathrm{between}\:\mathrm{the}\:\mathrm{two}\:\mathrm{charges} \\ $$$$\mathrm{where}\:\mathrm{the}\:\mathrm{electric}\:\mathrm{field}\:\mathrm{intensity}\:\mathrm{is}\:\mathrm{0}.\: \\ $$ Answered by ajfour last updated on…
Question Number 13040 by chux last updated on 12/May/17 $$\mathrm{which}\:\mathrm{is}\:\mathrm{heavier},\mathrm{HOT}\:\mathrm{water}\:\mathrm{or}\: \\ $$$$\mathrm{COLD}\:\mathrm{water}?\:\:\mathrm{pls}\:\mathrm{give}\:\mathrm{explanation} \\ $$$$ \\ $$$$\mathrm{Thanks} \\ $$ Answered by ajfour last updated on 12/May/17…
Question Number 78569 by Rio Michael last updated on 18/Jan/20 $${which}\:{of}\:{the}\:{following}\:{is}\:{increasing}\:{or}\:{decreasing} \\ $$$${a}.\:\:{u}_{{n}} \:=\:\frac{{n}!}{{n}^{{n}} } \\ $$$${b}.\:\:{u}_{{n}} =\:\frac{\mathrm{4}^{{n}} }{\mathrm{3}^{{n}} +\mathrm{1}} \\ $$$${c}.\:{u}_{{n}} =\:\frac{\mathrm{2}^{{n}} }{{n}^{\mathrm{2}} }…
Question Number 419 by 123456 last updated on 25/Jan/15 $${f}\left({x},{y}\right)=\frac{{x}}{{x}^{\mathrm{4}} +{y}^{\mathrm{2}} }+\frac{{y}}{{x}^{\mathrm{2}} +{y}^{\mathrm{4}} } \\ $$$${g}\left({x},{y}\right)={x}\frac{\partial{f}}{\partial{x}}+{y}\frac{\partial{f}}{\partial{y}} \\ $$$${g}\left(\mathrm{1},\mathrm{1}\right)= \\ $$ Answered by 9999 last updated…
Question Number 414 by 123456 last updated on 25/Jan/15 $${f}\left({x},{y}\right)=\begin{cases}{\frac{\left({x}−\mathrm{1}\right)\left({y}−\mathrm{1}\right)\left({xy}−\mathrm{1}\right)+\left({x}^{\mathrm{2}} −\mathrm{1}\right)\left({y}^{\mathrm{2}} −\mathrm{1}\right)}{{x}^{\mathrm{2}} −{xy}}}&{\left({x},{y}\right)\neq\left(\mathrm{1},\mathrm{1}\right)}\\{\mathrm{0}}&{\left({x},{y}\right)=\left(\mathrm{1},\mathrm{1}\right)}\end{cases} \\ $$$$\mathrm{is}\:{f}\left({x},{y}\right)\:\mathrm{continuos}\:\mathrm{at}\:\left({x},{y}\right)=\left(\mathrm{1},\mathrm{1}\right)? \\ $$ Answered by prakash jain last updated on 31/Dec/14…
Question Number 65951 by ketto2 last updated on 06/Aug/19 Commented by Tony Lin last updated on 06/Aug/19 $${if}\:{the}\:{son}\:{is}\:{x}\:{now}\: \\ $$$$\Rightarrow{his}\:{father}\:{is}\:\mathrm{30}+{x} \\ $$$${after}\:\mathrm{10}\:{years} \\ $$$$\Rightarrow\mathrm{40}+{x}=\mathrm{3}\left({x}+\mathrm{10}\right) \\…
Question Number 396 by 123456 last updated on 25/Jan/15 $$\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{3}}{\mathrm{4}}+\frac{\mathrm{5}}{\mathrm{6}}−\frac{\mathrm{7}}{\mathrm{8}}+\centerdot\centerdot\centerdot={x} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{4}}+\frac{\mathrm{1}}{\mathrm{6}}−\frac{\mathrm{1}}{\mathrm{8}}+…={y} \\ $$$$−−−−−−−−−−−−−−−−−− \\ $$$$\underset{{i}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{2}{i}+\mathrm{1}}{\mathrm{2}^{{i}} }\:\mathrm{converge}? \\ $$ Commented by 123456 last…