Question Number 11413 by agni5 last updated on 24/Mar/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{arc}\:\mathrm{of}\:\mathrm{the}\:\mathrm{hyperbolic} \\ $$$$\mathrm{spiral}\:\:\mathrm{r}\theta=\mathrm{a}\:\:\mathrm{lying}\:\mathrm{between}\:\:\mathrm{r}=\mathrm{a}\:\:\mathrm{and}\: \\ $$$$\mathrm{r}=\mathrm{2a}. \\ $$ Answered by mrW1 last updated on 26/Mar/17 $${r}=\frac{{a}}{\theta} \\…
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Question Number 11389 by tawa last updated on 23/Mar/17 $$\mathrm{Given}\:\mathrm{that}\:\mathrm{the}\:\mathrm{mean}\:\mathrm{relative}\:\mathrm{atomic}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{chlorine}\:\mathrm{contain}\:\mathrm{two}\:\mathrm{isotopes} \\ $$$$\mathrm{of}\:\mathrm{mass}\:\mathrm{numbe}\:\mathrm{35}\:\mathrm{and}\:\mathrm{37}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{percentage}\:\mathrm{of}\:\mathrm{composition}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{isotope}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{number}\:\mathrm{37}\: \\ $$ Answered by sandy_suhendra last updated on 23/Mar/17 $$\mathrm{isotope}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{number}\:\mathrm{37}=\mathrm{x\%} \\…
Question Number 76922 by TawaTawa last updated on 01/Jan/20 Commented by ajfour last updated on 13/Jan/20 $${this}\:{post}\:{always}\:{comes}\:{at} \\ $$$${my}\:{recent}\:{activity}\:{page},\:{not} \\ $$$${matter}\:{what}\:{the}\:{recent}\:{posts} \\ $$$${there}\:{are},\:{something}\:{wrong}…! \\ $$$${Admin}\:{please}\:{help}.…
Question Number 11388 by tawa last updated on 23/Mar/17 $$\mathrm{A}\:\mathrm{cell}\:\mathrm{supplies}\:\mathrm{a}\:\mathrm{current}\:\mathrm{of}\:\mathrm{6}\:\mathrm{ameter}\:\mathrm{through}\:\mathrm{a}\:\mathrm{2}\:\mathrm{coil}\:\mathrm{and}\:\mathrm{a}\:\mathrm{current}\:\mathrm{of}\:\mathrm{0}.\mathrm{2}\: \\ $$$$\mathrm{ameter}\:\mathrm{through}\:\mathrm{7}\:\mathrm{coil}.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{limits}\:\mathrm{and}\:\mathrm{the}\:\mathrm{internal}\:\mathrm{resistance} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{cell} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 11372 by agni5 last updated on 22/Mar/17 $$\mathrm{If}\:\mathrm{G}_{\mathrm{1}} \:\mathrm{and}\:\mathrm{G}_{\mathrm{2}} \:\mathrm{are}\:\mathrm{groups}\:,\:\mathrm{and}\:\mathrm{f}\::\:\mathrm{G}_{\mathrm{1}} \:\rightarrow\mathrm{G}_{\mathrm{2}} \\ $$$$\mathrm{is}\:\mathrm{a}\:\mathrm{group}\:\mathrm{homomorphism}\:,\:\mathrm{then}\:\mathrm{prove} \\ $$$$\mathrm{that}\:\mathrm{o}\left(\mathrm{G}_{\mathrm{1}} \right)\:=\:\mathrm{o}\left(\mathrm{G}_{\mathrm{2}} \right)\:. \\ $$ Terms of Service Privacy…
Question Number 11373 by ketto last updated on 22/Mar/17 Answered by sm3l2996 last updated on 22/Mar/17 $$\overset{−} {\mathrm{D}}\overset{\rightarrow} {\mathrm{F}}=\mathrm{D}\overset{\rightarrow} {\mathrm{A}}+\mathrm{A}\overset{\rightarrow} {\mathrm{B}}+\mathrm{B}\overset{\rightarrow} {\mathrm{F}} \\ $$$$\mathrm{DF}=\sqrt{\mathrm{DA}^{\mathrm{2}} +\mathrm{AB}^{\mathrm{2}}…
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Question Number 11327 by 786786AM last updated on 20/Mar/17 $$\mathrm{pl}\:\mathrm{show}\:\mathrm{me}\:\mathrm{typing}\:\mathrm{and}\:\mathrm{shape}\:\mathrm{drawing}\:\mathrm{app}\:\mathrm{for}\:\mathrm{mobile}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 142383 by liki last updated on 30/May/21 Commented by liki last updated on 30/May/21 $$\mathrm{help}\:\mathrm{me}\:\mathrm{qn}\:\mathrm{no}\:\mathrm{4} \\ $$ Answered by physicstutes last updated on…